Problem 69
Question
Choose a method and solve the quadratic equation. Explain your choice. $$ 2 x^{2}+7 x+3=0 $$
Step-by-Step Solution
Verified Answer
The solutions for the equation \(2x^{2}+7x+3=0\) are \(x= -0.5\) and \(x= -3\).
1Step 1: Identify the coefficients
The coefficients for this quadratic equation are \(a = 2\), \(b = 7\), and \(c = 3\). These values will be substituted in the quadratic formula to solve for \(x\).
2Step 2: Substitute the coefficients into the Quadratic formula
Now, substitute \(a = 2\), \(b = 7\), and \(c = 3\) into the quadratic formula: \[x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a}\] which gives: \[x = \frac{-7 \pm \sqrt{7^{2}-4*2*3}}{2*2}\]
3Step 3: Solving the formula
Next, perform the operations \(7^{2}-4*2*3 = 49-24 = 25\) and \(2*2 = 4\), giving: \[x = \frac{-7 \pm \sqrt{25}}{4}\] Simplify further by taking the square root of 25, which gives: \[x = \frac{-7 + 5}{4}\] and \[x = \frac{-7 - 5}{4}\] Finally, this simplifies to \(x = -0.5\) and \(x = -3\) respectively.
Key Concepts
Quadratic FormulaSolving QuadraticsFactorizationRoots of Equations
Quadratic Formula
The quadratic formula is a robust tool for solving any quadratic equation of the form \(ax^2 + bx + c = 0\). This formula helps find the equation's roots by using the coefficients \(a\), \(b\), and \(c\). The quadratic formula is expressed as:
\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]
This formula works universally for quadratics, regardless of whether they are factorable. All you need is to substitute the values of \(a\), \(b\), and \(c\) into the formula. This method is especially useful when a quadratic doesn't factor nicely using integers. Often students use it when other methods become cumbersome. Just remember, if the expression under the square root (the discriminant \(b^2 - 4ac\)) is negative, the roots will be complex, not real numbers.
\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]
This formula works universally for quadratics, regardless of whether they are factorable. All you need is to substitute the values of \(a\), \(b\), and \(c\) into the formula. This method is especially useful when a quadratic doesn't factor nicely using integers. Often students use it when other methods become cumbersome. Just remember, if the expression under the square root (the discriminant \(b^2 - 4ac\)) is negative, the roots will be complex, not real numbers.
Solving Quadratics
Solving quadratics involves finding the values of \(x\) that make the equation true, where the equation is typically expressed as \(ax^2 + bx + c = 0\). There are various methods to solve quadratics including:
- Factoring: This is attempted first if the quadratic is easily factorable.
- Quadratic Formula: A universal method for any quadratic equation.
- Completing the Square: Useful for equations that are difficult to factor.
Factorization
Factorization involves expressing the quadratic equation \(ax^2 + bx + c = 0\) as a product of two binomials. This method works well when the quadratic can be broken down into easier-to-handle expressions like \((x + p)(x + q) = 0\). Solving each binomial for zero will give the values of \(x\) where:
- \(p\) and \(q\) are integers that multiply to \(ac\).
- The sum of \(p\) and \(q\) is \(b\).
Roots of Equations
The roots of a quadratic equation are the values of \(x\) that make the equation true. In other words, they are the points where the quadratic function crosses the x-axis. For the quadratic equation \(ax^2 + bx + c = 0\), the roots can be real or complex numbers depending on the discriminant \(b^2 - 4ac\).
If the discriminant is:
If the discriminant is:
- Positive: There are two distinct real roots.
- Zero: There is exactly one real root (the roots are repeated).
- Negative: The roots are complex or imaginary.
Other exercises in this chapter
Problem 68
Simplify the radical expression. $$\frac{3 \sqrt{7}}{\sqrt{9}}$$
View solution Problem 69
Simplify the expression. $$ \frac{5}{4 x}+\frac{7}{3 x} $$
View solution Problem 69
Solve the equation by factoring. $$ 2+3 x^{2}=-5 x $$
View solution Problem 69
Find the product. $$ (3 x+5 y)(3 x-5 y) $$
View solution