Problem 69
Question
\(65-76=\) Find the indicated power using DeMoivre's Theorem. $$ \left(\frac{\sqrt{2}}{2}+\frac{\sqrt{2}}{2} i\right)^{12} $$
Step-by-Step Solution
Verified Answer
The result is \(-1\).
1Step 1: Identify the Complex Number
The complex number given is \( \frac{\sqrt{2}}{2} + \frac{\sqrt{2}}{2} i \). We need to convert it to polar form for easier computation.
2Step 2: Convert to Polar Form
The modulus of the complex number is \( r = \sqrt{ \left( \frac{\sqrt{2}}{2} \right)^2 + \left( \frac{\sqrt{2}}{2} \right)^2 } = 1 \). The argument \( \theta \) such that \( \cos(\theta) = \frac{\sqrt{2}}{2} \) and \( \sin(\theta) = \frac{\sqrt{2}}{2} \) is \( \theta = \frac{\pi}{4} \). Thus, the polar form is \( 1 \text{cis} \frac{\pi}{4} \).
3Step 3: Apply DeMoivre's Theorem
DeMoivre's Theorem states that \( (r \text{cis} \theta)^n = r^n \text{cis} (n\theta) \). Here, \( n = 12 \), \( r = 1 \), and \( \theta = \frac{\pi}{4} \). Therefore, the expression becomes \( 1^{12} \text{cis} (12 \cdot \frac{\pi}{4}) = \text{cis} 3\pi \).
4Step 4: Simplify the Argument
The angle \( 3\pi \) is equivalent to \( 3\pi - 2\pi = \pi \) since we can subtract \( 2\pi \) to find a coterminal angle. Therefore, the expression simplifies to \( \text{cis} \pi \), which in rectangular form is \( \cos(\pi) + i \sin(\pi) = -1 + 0i \).
Key Concepts
Complex NumbersPolar FormModulus and ArgumentRectangular Form
Complex Numbers
Complex numbers extend the idea of one-dimensional numbers, like real numbers, to two dimensions by including imaginary components. They are typically written in the form \( a + bi \), where \( a \) is the real part, and \( bi \) is the imaginary part of the complex number.
The imaginary unit \( i \) is defined as \( i^2 = -1 \). This allows for calculations that are not possible with just real numbers.
The imaginary unit \( i \) is defined as \( i^2 = -1 \). This allows for calculations that are not possible with just real numbers.
- Real Part: The coefficient \( a \) of a complex number \( a + bi \).
- Imaginary Part: The coefficient \( b \) in the complex number \( a + bi \).
Polar Form
Complex numbers can also be represented in polar form, which can sometimes simplify the process of multiplication and division. The polar form emphasizes the modulus and the argument of a complex number.
A complex number in polar form is represented as \( r \text{cis} \theta \), where \( r \) is the modulus and \( \theta \) is the argument.
A complex number in polar form is represented as \( r \text{cis} \theta \), where \( r \) is the modulus and \( \theta \) is the argument.
- The term \( \text{cis} \theta \) is a shorthand notation for \( \cos \theta + i \sin \theta \).
- Polar form is particularly useful for applying DeMoivre's Theorem, which simplifies the calculation of powers and roots of complex numbers.
Modulus and Argument
In polar form, two important concepts are the modulus and the argument of a complex number. The modulus, sometimes referred to as the magnitude, represents the distance from the origin to the point in the complex plane.
- The modulus \( r \) of a complex number \( a + bi \) is calculated using the formula \( r = \sqrt{a^2 + b^2} \).
- The argument \( \theta \) is the angle formed with the positive real axis and is measured counterclockwise. It is often determined using trigonometric ratios: \( \theta = \tan^{-1}(\frac{b}{a}) \).
Rectangular Form
While polar form is very powerful, complex numbers are most commonly written in rectangular form as \( a + bi \). This form emphasizes the coordinates of the complex number on the complex plane with a real part and an imaginary part.
Rectangular form is particularly useful for straightforward addition and subtraction of complex numbers because like terms (real with real and imaginary with imaginary) are easily combined.
Rectangular form is particularly useful for straightforward addition and subtraction of complex numbers because like terms (real with real and imaginary with imaginary) are easily combined.
- Addition: \( (a + bi) + (c + di) = (a + c) + (b + d)i \)
- Subtraction: \( (a + bi) - (c + di) = (a - c) + (b - d)i \)
Other exercises in this chapter
Problem 67
\(65-76=\) Find the indicated power using DeMoivre's Theorem. $$ (2 \sqrt{3}+2 i)^{5} $$
View solution Problem 68
\(65-76=\) Find the indicated power using DeMoivre's Theorem. $$ (1-i)^{8} $$
View solution Problem 72
\(65-76=\) Find the indicated power using DeMoivre's Theorem. $$ \left(-\frac{1}{2}-\frac{\sqrt{3}}{2} i\right)^{15} $$
View solution Problem 73
\(65-76=\) Find the indicated power using DeMoivre's Theorem. $$ (-1-i)^{7} $$
View solution