Problem 68
Question
Writing to Learn Explain why there is no value \(L\) for which \(\lim _{x \rightarrow \infty} \sin x=L\)
Step-by-Step Solution
Verified Answer
There is no value \(L\) for which \(\lim _{x \rightarrow \infty} \sin x=L\), because the sine function does not approach a specific number as \(x\) increases indefinitely, but continues to oscillate between -1 and 1.
1Step 1: Recognize the Sine Function
The function \(\sin x\) is moderately difficult to analyze, because it does not tend towards a limit as \(x\) approaches infinity. Here, a deep understanding of the sine function is required, which is a wave pattern that oscillates between -1 and 1.
2Step 2: Understand the Limit Concept
A limit as \(x\) approaches infinity of a function equals \(L\) only if the values of the function get arbitrarily close to \(L\) as \(x\) becomes larger and larger (i.e. approaches infinity). Essentially, this means that the function begins to flatline as \(x\) becomes extremely large, and it will continually get closer and closer to \(L\).
3Step 3: Analyze the Combination of Sine function and Limit Property
The sine function does not flatline or get arbitrarily close to any single number as \(x\) approaches infinity. Instead, it continues to oscillate indefinitely. So there is no single limit \(L\) as \(x\) approaches infinity.
Key Concepts
Sine FunctionOscillationInfinite Limits
Sine Function
The sine function, often represented as \( \sin x \), is a mathematical function that plays a crucial role in trigonometry. Its graph is a continuous wave that oscillates between -1 and 1. This wave pattern is consistent, making it both predictable and periodic. The period of the sine function is equal to \( 2\pi \), which means it repeats its values every \( 2\pi \) units of \( x \).
Key characteristics of the sine function include:
Key characteristics of the sine function include:
- Amplitude: The maximum value of the sine function is 1, and the minimum is -1.
- Periodicity: The function repeats every \( 2\pi \) radians, creating a smooth and continuous wave.
- Symmetry: The sine function is symmetric about the origin, demonstrating odd symmetry (\( \sin(-x) = -\sin(x) \)).
Oscillation
Oscillation refers to the repeated and regular fluctuation of a quantity or value. In the case of the sine function, oscillation is a fundamental aspect, as it continuously moves up and down between its maximum and minimum values. This oscillating behavior is what makes the sine function so unique in calculus and trigonometry.
The key points about oscillation in the sine function include:
The key points about oscillation in the sine function include:
- No Fixed Approach: Because the sine function oscillates, it never settles at a single value as \( x \) increases.
- Indefinite Repetition: The oscillation continues infinitely without changing in amplitude or frequency.
- Influence on Limits: The oscillating nature of \( \sin x \) directly affects its behavior concerning limits, as it cannot approach a finite limit \( L \) when \( x \) tends towards infinity.
Infinite Limits
Infinite limits occur when the value of a function becomes large beyond bounds as the input or \( x \) approaches certain points or infinity. However, the concept of an infinite limit implies that a function's values grow increasingly large towards a particular end.In considering limits with the sine function as \( x \) approaches infinity:
- Typical Limit Concept: For most functions, if a limit as \( x \) approaches infinity is \( L \), the function's values become closer and closer to \( L \).
- Failure with Sine Function: The sine function does not tend toward any particular \( L \), because it continues to oscillate indefinitely between -1 and 1.
Other exercises in this chapter
Problem 67
In Exercises \(67 - 70\) , use the following function. \(f ( x ) = \left\\{ \begin{array} { l l } { 2 - x , } & { x \leq 1 } \\ { \frac { x } { 2 } + 1 , } & {
View solution Problem 68
In Exercises \(67 - 70\) , use the following function. \(f ( x ) = \left\\{ \begin{array} { l l } { 2 - x , } & { x \leq 1 } \\ { \frac { x } { 2 } + 1 , } & {
View solution Problem 69
In Exercises \(67 - 70\) , use the following function. \(f ( x ) = \left\\{ \begin{array} { l l } { 2 - x , } & { x \leq 1 } \\ { \frac { x } { 2 } + 1 , } & {
View solution Problem 69
In Exercises 69-71, find the limit. Give a convincing argument that the value is correct. $$\lim _{x \rightarrow \infty} \frac{\ln x^{2}}{\ln x}$$
View solution