Problem 68
Question
Verify the identity. $$ \frac{\csc ^{2} x-\cot ^{2} x}{\sec ^{2} x}=\cos ^{2} x $$
Step-by-Step Solution
Verified Answer
The identity is verified: LHS simplifies to \(\cos^2 x\), which equals the RHS.
1Step 1: Convert Terms to Sine and Cosine
To verify the identity, start by rewriting both the numerator and the denominator of the left-hand side (LHS) in terms of sine and cosine. Recall that \( \csc x = \frac{1}{\sin x} \) and \( \cot x = \frac{\cos x}{\sin x} \):\[\frac{\csc ^{2} x-\cot ^{2} x}{\sec ^{2} x} = \frac{\frac{1}{\sin^2 x}-\frac{\cos^2 x}{\sin^2 x}}{\frac{1}{\cos^2 x}}\]
2Step 2: Simplify the Numerator
Combine the fractions in the numerator over a common denominator:\[\frac{\frac{1-\cos^2 x}{\sin^2 x}}{\frac{1}{\cos^2 x}}\] Since \(1 - \cos^2 x = \sin^2 x\), simplify further:\[\frac{\frac{\sin^2 x}{\sin^2 x}}{\frac{1}{\cos^2 x}} = \frac{1}{\frac{1}{\cos^2 x}}\]
3Step 3: Simplify the Overall Expression
Since the numerator simplifies to 1, the expression becomes:\[\frac{1}{\frac{1}{\cos^2 x}} = \cos^2 x\] Thus, the LHS equals the right-hand side (RHS).
4Step 4: Verify the Identity
After simplification, we have shown that the LHS of the original identity simplifies to \(\cos^2 x\), which is the same as the RHS. Thus, the identity is verified:\[\frac{\csc ^{2} x-\cot ^{2} x}{\sec ^{2} x} = \cos ^{2} x\]
Key Concepts
Cosecant FunctionCotangent FunctionSecant Function
Cosecant Function
The cosecant function, denoted as \( \csc x \), is one of the six fundamental trigonometric functions. It is the reciprocal of the sine function. Therefore, the cosecant of an angle \( x \) can be expressed as the ratio of the hypotenuse to the opposite side in a right triangle. In mathematical form, this is written as:\[ \csc x = \frac{1}{\sin x} \]It's important to note that because \( \csc x \) is the reciprocal of \( \sin x \), it is only defined for angles where \( \sin x eq 0 \). This means \( \csc x \) is undefined for integer multiples of \( \pi \) since at these angles \( \sin x \) equals zero.
- Graph: The graph of \( \csc x \) has vertical asymptotes at every multiple of \( \pi \) because the sine function equals zero there.
- Properties: The cosecant function is periodic with a period of \( 2\pi \).
Cotangent Function
The cotangent function, symbolized as \( \cot x \), is another trigonometric function, representing the reciprocal of the tangent function. It can be defined as the ratio of the adjacent side to the opposite side in a right triangle. Mathematically, it's represented as:\[ \cot x = \frac{1}{\tan x} = \frac{\cos x}{\sin x} \]Like \( \csc x \), \( \cot x \) is undefined when \( \sin x = 0 \), which occurs at integer multiples of \( \pi \).
- Graph: Similar to tangent, the cotangent function graph has vertical asymptotes at multiples of \( \pi \), but shifted by \( \frac{\pi}{2} \).
- Properties: The cotangent function has a period of \( \pi \).
Secant Function
The secant function, expressed as \( \sec x \), is the reciprocal of the cosine function. It represents the ratio of the hypotenuse to the adjacent side in a right triangle. This function can be mathematically defined as:\[ \sec x = \frac{1}{\cos x} \]\( \sec x \) is undefined where \( \cos x = 0 \), specifically at odd multiples of \( \frac{\pi}{2} \), since the cosine function equals zero at these points.
- Graph: The graph of the secant function shows vertical asymptotes at odd multiples of \( \frac{\pi}{2} \).
- Properties: Secant has a periodicity of \( 2\pi \), similar to the cosine function.
Other exercises in this chapter
Problem 67
Use a double-or half-angle formula to solve the equation in the interval \([0,2 \pi) .\) $$\cos 2 x+\cos x=2$$
View solution Problem 67
59–76 Prove the identity. $$\tan 3 x=\frac{3 \tan x-\tan ^{3} x}{1-3 \tan ^{2} x}$$
View solution Problem 68
59–76 Prove the identity. $$4\left(\sin ^{6} x+\cos ^{6} x\right)=4-3 \sin ^{2} 2 x$$
View solution Problem 69
Verify the identity. $$ \tan ^{2} u-\sin ^{2} u=\tan ^{2} u \sin ^{2} u $$
View solution