Problem 68
Question
Verify the identity by transforming the lefthand side into the right-hand side. $$\frac{1+\cos ^{2} 3 \theta}{\sin ^{2} 3 \theta}=2 \csc ^{2} 3 \theta-1$$
Step-by-Step Solution
Verified Answer
Identity is verified by showing both sides simplify to \( \frac{2 - \sin^2 3\theta}{\sin^2 3\theta} \).
1Step 1: Rewrite Cosecant Identity
Recall that the cosecant function is the reciprocal of the sine function: \[ \csc^2 3\theta = \frac{1}{\sin^2 3\theta} \]Therefore, \[ 2 \csc^2 3\theta = \frac{2}{\sin^2 3\theta}. \]
2Step 2: Substitute and Simplify Right-Hand Side
Substitute the expression from Step 1 into the right-hand side:\[ 2 \csc^2 3\theta - 1 = \frac{2}{\sin^2 3\theta} - 1. \]Find a common denominator:\[ \frac{2}{\sin^2 3\theta} - 1 = \frac{2}{\sin^2 3\theta} - \frac{\sin^2 3\theta}{\sin^2 3\theta} = \frac{2 - \sin^2 3\theta}{\sin^2 3\theta}. \]
3Step 3: Use Pythagorean Identity for Cosine
Recall the Pythagorean identity: \[ \sin^2 \theta + \cos^2 \theta = 1 \rightarrow \cos^2 \theta = 1 - \sin^2 \theta. \] Apply this identity for \( \cos^2 3\theta \):\[ \cos^2 3\theta = 1 - \sin^2 3\theta. \]
4Step 4: Substitute and Simplify Left-Hand Side
Start with the left-hand side expression:\[ \frac{1 + \cos^2 3\theta}{\sin^2 3\theta}. \]Use the identity from Step 3:\[ \cos^2 3\theta = 1 - \sin^2 3\theta \rightarrow 1 + \cos^2 3\theta = 1 + (1 - \sin^2 3\theta) = 2 - \sin^2 3\theta. \]Replace in the equation:\[ \frac{2 - \sin^2 3\theta}{\sin^2 3\theta}. \]
5Step 5: Verify Identity
The expression on the left-hand side is now:\[ \frac{2 - \sin^2 3\theta}{\sin^2 3\theta}, \]which matches the simplified expression obtained for the right-hand side in Step 2. This verifies the identity.
Key Concepts
Cosecant IdentityPythagorean IdentitySine FunctionCosine Function
Cosecant Identity
The cosecant function is an important part of trigonometry, often abbreviated as "csc." Its identity is straightforward and stems from its relationship with the sine function. Simply put, the cosecant of an angle is the reciprocal of its sine.
This means that the cosecant of any angle \(θ\) can be expressed as: \[ \csc\,θ = \frac{1}{\sin\,θ}. \]
For squared versions, we have: \[ \csc^2\,θ = \frac{1}{\sin^2\,θ}. \]
This relationship is vital in simplifying trigonometric expressions, especially when identities or transformations are involved.
In our exercise, the identity for \(\csc^2 3θ\) was used to transform part of the equation. Recognizing and applying this identity simplifies complex trigonometric identities more easily, allowing us to progress through problems with precision.
This means that the cosecant of any angle \(θ\) can be expressed as: \[ \csc\,θ = \frac{1}{\sin\,θ}. \]
For squared versions, we have: \[ \csc^2\,θ = \frac{1}{\sin^2\,θ}. \]
This relationship is vital in simplifying trigonometric expressions, especially when identities or transformations are involved.
In our exercise, the identity for \(\csc^2 3θ\) was used to transform part of the equation. Recognizing and applying this identity simplifies complex trigonometric identities more easily, allowing us to progress through problems with precision.
Pythagorean Identity
The Pythagorean identity is one of the cornerstone equations in trigonometry, fundamental for solving identities and equations. This identity provides a relationship between the sine and cosine functions.
It states that for any angle \(θ\): \[ \sin^2 θ + \cos^2 θ = 1. \]
From this equation, we can rearrange terms to solve for \(\cos^2 θ\)
In the exercise, this identity was utilized to express \(\cos^2 3θ\) as \(1 - \sin^2 3θ\), allowing for the transformation of the expression as needed.
It states that for any angle \(θ\): \[ \sin^2 θ + \cos^2 θ = 1. \]
From this equation, we can rearrange terms to solve for \(\cos^2 θ\)
- ew{\sin^2 θ} by subtracting \(\sin^2 θ\) from both sides, which gives: \[ \cos^2 θ = 1 - \sin^2 θ. \]
In the exercise, this identity was utilized to express \(\cos^2 3θ\) as \(1 - \sin^2 3θ\), allowing for the transformation of the expression as needed.
Sine Function
The sine function is a fundamental concept in trigonometry. It relates to the ratio of the opposite side to the hypotenuse in a right-angled triangle.
Defined as: \[ \sin\,θ = \frac{\text{opposite}}{\text{hypotenuse}}. \]
Defined as: \[ \sin\,θ = \frac{\text{opposite}}{\text{hypotenuse}}. \]
- Measured from 0° to 360° in degrees or from 0 to \(2π\) in radians
- Repeats its values every 360°, making it a periodic function.
Cosine Function
The cosine function, much like its companion the sine function, is essential in trigonometry. It serves a similar purpose: expressing relationships in right-angled triangles. The cosine of an angle \(θ\) is the ratio of the adjacent side over the hypotenuse:
Defined as: \[ \cos\,θ = \frac{\text{adjacent}}{\text{hypotenuse}}. \]
This illustrates the crucial role of cosine in evaluating and balancing complex trigonometric equations.
Defined as: \[ \cos\,θ = \frac{\text{adjacent}}{\text{hypotenuse}}. \]
- Also a periodic function with a period of 360° or \(2π\) radians.
- Starts at maximum value when \(θ = 0\,°\ or\ 0\) radians and repeats every full cycle.
This illustrates the crucial role of cosine in evaluating and balancing complex trigonometric equations.
Other exercises in this chapter
Problem 67
Verify the identity by transforming the lefthand side into the right-hand side. $$\sec ^{2} 3 \theta \csc ^{2} 3 \theta=\sec ^{2} 3 \theta+\csc ^{2} 3 \theta$$
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Exer. 67-70: The formula specifies the position of a point \(P\) that is moving harmonically on a vertical axis, where \(t\) is in seconds and \(d\) is in centi
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