Problem 68
Question
Using the value of \(K_{s p}\) for \(\mathrm{Ag}_{2} \mathrm{~S}, K_{a 1}\) and \(\mathrm{K}_{a 2}\) for \(\mathrm{H}_{2} \mathrm{~S},\) and \(K_{f}=1.1 \times 10^{5}\) for \(\mathrm{AgCl}_{2}^{-},\) calculate the equilibrium constant for the following reaction: $$ \mathrm{Ag}_{2} \mathrm{~S}(s)+4 \mathrm{Cl}^{-}(a q)+2 \mathrm{H}^{+}(a q) \rightleftharpoons 2 \mathrm{AgCl}_{2}^{-}(a q)+\mathrm{H}_{2} \mathrm{~S}(a q) $$
Step-by-Step Solution
Verified Answer
The overall equilibrium constant for the given reaction is \(K = K_{sp}\cdot K_{a1}\cdot K_{a2}\cdot K_{f}^2\). Plugging the given values for \(K_{sp}\), \(K_{a1}\), \(K_{a2}\), and \(K_f\), we can calculate the value of \(K\).
1Step 1: Write down the reactions with their equilibrium constants
The three separate reactions with their given equilibrium constants are:
1. Dissolution of silver sulfide (\(Ag_2S\)):
\[Ag_2S(s) \rightleftharpoons 2Ag^+(aq) + S^{2-}(aq)\]
Given: \(K_{sp} = [Ag^+]^2[S^{2-}]\)
2. The first dissociation of hydrogen sulfide (\(H_2S\)):
\[H_2S(aq) \rightleftharpoons H^+(aq) + HS^-(aq)\]
Given: \(K_{a1} = [H^+][HS^-]/[H_2S]\)
3. The second dissociation of hydrogen sulfide:
\[HS^-(aq) \rightleftharpoons H^+(aq) + S^{2-}(aq)\]
Given: \(K_{a2} = [H^+][S^{2-}]/[HS^-]\)
4. Formation of the silver chloride complex (\(AgCl_2^-\)):
\[Ag^+(aq) + 2Cl^-(aq) \rightleftharpoons AgCl_2^-(aq)\]
Given: \(K_f = [AgCl_2^-]/([Ag^+][Cl^-]^2)\)
2Step 2: Add the equations and find the overall equation
To obtain the overall balanced equation, we will sum up the individual reactions and cancel out the species that appear on both sides of the overall equation:
\[Ag_2S(s) + 4Cl^-(aq) + 2H^+(aq) \rightleftharpoons 2AgCl_2^-(aq) + H_2S(aq)\]
3Step 3: Calculate the overall equilibrium constant
Since we have the individual equilibrium constants, we can now find the overall equilibrium constant for the reaction. When adding the individual reactions, we multiply their corresponding equilibrium constants.
Overall equilibrium constant (\(K\)):
\[K = K_{sp}\cdot K_{a1}\cdot K_{a2}\cdot K_{f}\cdot K_f\]
(Note that we multiply \(K_f\) twice, as there are two moles of \(AgCl_2^-\) in the overall equation)
Now, you can plug in the given values of \(K_{sp}\), \(K_{a1}\), \(K_{a2}\), and \(K_f\) into the equation above and solve for the overall equilibrium constant, \(K\).
Key Concepts
Chemical ReactionsSilver SulfideHydrogen Sulfide DissociationSilver Chloride Complex Formation
Chemical Reactions
In chemistry, understanding chemical reactions is like unraveling a complex puzzle. A chemical reaction involves the transformation of one or more substances into a different set of substances. These transformations occur when chemical bonds are broken and new ones are formed. It's the backbone of everything from baking a cake to rust forming on iron. The essence of chemical reactions involves the reactants and products, along with the rearrangement of atoms.
In a balanced chemical equation, we ensure that the number of each type of atom is the same on both sides of the equation. This conformity aligns with the Law of Conservation of Mass, asserting that matter is neither created nor destroyed in a chemical reaction.
In a balanced chemical equation, we ensure that the number of each type of atom is the same on both sides of the equation. This conformity aligns with the Law of Conservation of Mass, asserting that matter is neither created nor destroyed in a chemical reaction.
- Reactants: The starting substances.
- Products: The substances that are formed as the reaction progresses.
Silver Sulfide
Silver sulfide \( (Ag_2S) \) is a compound that forms when silver reacts with sulfur. It's responsible for the black tarnish often seen on silverware. In chemistry, we often need to dissolve silver sulfide in reactions, which isn't always straightforward.
The process of dissolving silver sulfide involves breaking it down into its ions in an aqueous solution. The reaction for this process is:
Silver sulfide's low solubility is why some silver objects tend to corrode when exposed to air, as they react slowly but continuously with sulfur compounds in the environment.
The process of dissolving silver sulfide involves breaking it down into its ions in an aqueous solution. The reaction for this process is:
- \(Ag_2S(s) \rightleftharpoons 2Ag^+(aq) + S^{2-}(aq)\)
Silver sulfide's low solubility is why some silver objects tend to corrode when exposed to air, as they react slowly but continuously with sulfur compounds in the environment.
Hydrogen Sulfide Dissociation
Hydrogen sulfide \( (H_2S) \) is a gas renowned for its rotten egg smell, which arises from its typical occurrence in sewers and volcanic gases. In an aqueous environment, hydrogen sulfide can dissociate into ions in two main steps. The dissociation occurs as follows:
- First dissociation: \(H_2S(aq) \rightleftharpoons H^+(aq) + HS^-(aq)\)
- Second dissociation: \(HS^-(aq) \rightleftharpoons H^+(aq) + S^{2-}(aq)\)
Silver Chloride Complex Formation
The formation of silver chloride complexes is an interesting chemical phenomenon. In solutions containing chloride ions, \( Ag^+ \) ions can form a complex ion known as \( AgCl_2^- \). This process is characterized by the reaction:
- \(Ag^+(aq) + 2Cl^-(aq) \rightleftharpoons AgCl_2^-(aq)\)
Other exercises in this chapter
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