Problem 68
Question
Use the properties of logarithms to rewrite each logarithm if possible. Assume that all variables represent positive real numbers. $$\log _{3} \frac{4 p}{q}$$
Step-by-Step Solution
Verified Answer
\( \log_{3} \frac{4p}{q} = \log_{3} 4 + \log_{3} p - \log_{3} q \)
1Step 1: Identify the Logarithmic Property to Use
The expression given is \( \log_{3} \left( \frac{4p}{q} \right) \). To rewrite this expression, we can use the property of logarithms related to division, which states: \( \log_{b} \left( \frac{M}{N} \right) = \log_{b} M - \log_{b} N \).
2Step 2: Apply the Division Property of Logarithms
Using the division property identified in Step 1, we rewrite the expression: \( \log_{3} \left( \frac{4p}{q} \right) = \log_{3} 4p - \log_{3} q \).
3Step 3: Further Simplify Using the Product Property
Now, apply the logarithmic property for multiplication, which is \( \log_{b} (MN) = \log_{b} M + \log_{b} N \), to the term \( \log_{3} 4p \). This gives us: \( \log_{3} 4p = \log_{3} 4 + \log_{3} p \).
4Step 4: Write the Final Expression
Substituting the result from Step 3 back into the expression from Step 2, we have: \( \log_{3} 4p - \log_{3} q = (\log_{3} 4 + \log_{3} p) - \log_{3} q = \log_{3} 4 + \log_{3} p - \log_{3} q \).
5Step 5: Final Simplified Expression
Combine all the terms found: \( \log_{3} \frac{4p}{q} = \log_{3} 4 + \log_{3} p - \log_{3} q \).
Key Concepts
Division Property of LogarithmsProduct Property of LogarithmsSimplification of Logarithmic Expressions
Division Property of Logarithms
Let's begin by exploring the division property of logarithms. This property is extremely useful when dealing with expressions that involve division inside a logarithm. What it tells us is quite simple but powerful: the logarithm of a quotient is the difference of the logarithms of the numerator and the denominator.
When you see something like \( \log_{b} \left( \frac{M}{N} \right) \), the division property comes into play. It transforms this expression into \( \log_{b} M - \log_{b} N \). This equation can simplify calculations and expressions by breaking down complex ratios into more manageable parts.
When you see something like \( \log_{b} \left( \frac{M}{N} \right) \), the division property comes into play. It transforms this expression into \( \log_{b} M - \log_{b} N \). This equation can simplify calculations and expressions by breaking down complex ratios into more manageable parts.
- Example: If you have \( \log_{3} \left( \frac{4p}{q} \right) \), using the division property results in: \( \log_{3} 4p - \log_{3} q \).
Product Property of Logarithms
Next up, let's delve into the product property of logarithms, which helps to handle multiplication inside logarithms. According to this property, the logarithm of a product can be expressed as the sum of the logarithms of the factors.
In mathematical form, for an expression like \( \log_{b} (MN) \), it transforms into \( \log_{b} M + \log_{b} N \). By converting multiplication into an addition of separate logarithms, it can be easier to simplify or evaluate logarithmic expressions.
In mathematical form, for an expression like \( \log_{b} (MN) \), it transforms into \( \log_{b} M + \log_{b} N \). By converting multiplication into an addition of separate logarithms, it can be easier to simplify or evaluate logarithmic expressions.
- Example: In our case, \( \log_{3} 4p \) can be rewritten using the product property as: \( \log_{3} 4 + \log_{3} p \).
Simplification of Logarithmic Expressions
Finally, let's talk about the simplification of logarithmic expressions. Using the properties discussed, we can streamline complex logarithmic expressions into their simplest forms.
The key is to incrementally apply the properties, breaking down the expression one piece at a time. By sequentially using both the division and product properties, you can simplify to a form that's straightforward to interpret.
In our example \( \log_{3} \frac{4p}{q} \), we first applied the division property to get \( \log_{3} 4p - \log_{3} q \). Then, we used the product property on \( \log_{3} 4p \), transforming it into \( \log_{3} 4 + \log_{3} p \).
Combining these operations, we reach a final simplified form: \( \log_{3} 4 + \log_{3} p - \log_{3} q \).
The process of simplification is not just about reaching a final answer. It aids in understanding the relationships between different parts of the expression, making these kinds of mathematical puzzles easier and more intuitive to solve.
The key is to incrementally apply the properties, breaking down the expression one piece at a time. By sequentially using both the division and product properties, you can simplify to a form that's straightforward to interpret.
In our example \( \log_{3} \frac{4p}{q} \), we first applied the division property to get \( \log_{3} 4p - \log_{3} q \). Then, we used the product property on \( \log_{3} 4p \), transforming it into \( \log_{3} 4 + \log_{3} p \).
Combining these operations, we reach a final simplified form: \( \log_{3} 4 + \log_{3} p - \log_{3} q \).
The process of simplification is not just about reaching a final answer. It aids in understanding the relationships between different parts of the expression, making these kinds of mathematical puzzles easier and more intuitive to solve.
Other exercises in this chapter
Problem 67
Use properties of exponents to write each function in the form \(f(t)=k a^{t},\) where \(k\) is a constant. (Hint: Recall that \(a^{x+y}=a^{x} \cdot a^{y}\).) $
View solution Problem 68
The given function \(f\) is one-to-one. Find \(f^{-1}(x)\). $$f(x)=\frac{3 x}{5-x}$$
View solution Problem 68
Use a graphing calculator to find the solution of each equation. Round your result to the nearest thousandth. $$1.5^{\ln x}=10^{0.5}$$
View solution Problem 68
The graph of \(y=e^{x-3}\) can be obtained by translating the graph of \(y=e^{x}\) to the right 3 units. Find a constant \(C\) such that the graph of \(y=C e^{x
View solution