Problem 68
Question
Solve for the specified variable. $$ P=2 l+2 w \quad \text { for } l $$
Step-by-Step Solution
Verified Answer
\( l = \frac{P - 2w}{2} \)
1Step 1: Write down the equation
Start with the given formula for perimeter, which is expressed as \( P = 2l + 2w \). Our goal is to solve this equation for \( l \).
2Step 2: Isolate the term with the variable
Subtract \( 2w \) from both sides of the equation to isolate the terms involving \( l \). Thus, the equation becomes \( P - 2w = 2l \).
3Step 3: Solve for the variable
Divide both sides of the equation by 2 to solve for \( l \). This gives us \( l = \frac{P - 2w}{2} \).
Key Concepts
Isolating VariablesPerimeter FormulaAlgebraic Manipulation
Isolating Variables
Whenever you need to solve an equation for a specific variable, isolating that variable is essential. This means getting the variable you are solving for, such as \( l \) in this exercise, alone on one side of the equation.
To isolate a variable, you'll often need to perform the same operation on both sides of the equation. In our original problem, we start with the equation for perimeter: \( P = 2l + 2w \). Here, we want \( l \) by itself on one side.
Here's what you should do:
To isolate a variable, you'll often need to perform the same operation on both sides of the equation. In our original problem, we start with the equation for perimeter: \( P = 2l + 2w \). Here, we want \( l \) by itself on one side.
Here's what you should do:
- Identify the terms: Look at the equation and find where your variable is involved. In this case, terms involving \( l \) are \( 2l \).
- Use opposite operations: If \( 2w \) is added to \( 2l \), subtract \( 2w \) to cancel it out, moving it to the other side: \( P - 2w = 2l \).
- Complete the isolation: Finally, to get \( l \) by itself, divide by 2, yielding \( l = \frac{P - 2w}{2} \).
Perimeter Formula
The perimeter formula is crucial when talking about the boundaries of geometric shapes. It’s the total distance around an object or shape. For rectangles, the formula is standard: \( P = 2l + 2w \), where \( P \) represents the perimeter, \( l \) the length, and \( w \) the width.
Understanding this formula:
Understanding this formula:
- Calculation of the perimeter: The formula adds up all sides of a rectangle. Since opposite sides of rectangles are equal, you multiply the width and the length each by 2 and then add the results.
- Use of the formula: You can rearrange it to express any variable, for example, find \( l \) when \( P \) and \( w \) are known, which means using algebraic techniques to manipulate it.
Algebraic Manipulation
Algebraic manipulation involves rearranging equations or expressions to find unknown variables. It requires understanding the properties of equality and performing operations correctly on both sides of the equation to maintain balance.
In our specific task of solving \( P = 2l + 2w \) for \( l \):
In our specific task of solving \( P = 2l + 2w \) for \( l \):
- Subtraction: Subtract \( 2w \) from both sides to get \( P - 2w = 2l \). This step utilized the inverse operation of addition (subtracting \( 2w \)).
- Division: Then, divide both sides by 2 to isolate \( l \), giving \( l = \frac{P - 2w}{2} \). This step uses division, the inverse of multiplication.
Other exercises in this chapter
Problem 68
Simplify by combining like terms. See Example 5 . $$3.7 x^{2}+3.3 x^{2}-1.1 x^{2}$$
View solution Problem 68
Solve each equation. If the equation is an identity or a contradiction, so indicate. See Example 9. $$ 4(2-3 t)+6 t=-6 t+8 $$
View solution Problem 68
Evaluate each expression. See Example \(8 .\) $$ -18 \div 6 \cdot 3 $$
View solution Problem 68
Insert either \(a\) symbol to make a true statement. $$ \frac{21}{50} \quad 0.4 $$
View solution