Problem 68
Question
Multiply the algebraic expressions using a Special Product Formula, and simplify. \((x-3)^{3}\)
Step-by-Step Solution
Verified Answer
The simplified result is \(x^3 - 9x^2 + 27x - 27\).
1Step 1: Identify the Special Product Formula
The expression \((x-3)^3\) represents a cube of a binomial. We will use the special product formula for a binomial cube: \((a-b)^3 = a^3 - 3a^2b + 3ab^2 - b^3\). Here, \(a = x\) and \(b = 3\).
2Step 2: Apply the Formula to the Expression
Substitute \(a = x\) and \(b = 3\) into the cube of a binomial formula: \((x-3)^3 = x^3 - 3(x^2)(3) + 3(x)(3^2) - 3^3\).
3Step 3: Perform Calculations on Each Term
Calculate each term separately:- \(x^3 = x^3\)- \(-3(x^2)(3) = -9x^2\)- \(3(x)(3^2) = 27x\)- \(-3^3 = -27\).Thus, the expanded form is \(x^3 - 9x^2 + 27x - 27\).
4Step 4: Combine Results Into Final Answer
Put all the calculated terms together to get the simplified expression: \(x^3 - 9x^2 + 27x - 27\).
Key Concepts
Binomial CubeAlgebraic ExpressionsSimplification
Binomial Cube
When dealing with algebraic expressions, understanding special product formulas, like the binomial cube, is vital. A binomial is simply a polynomial with two terms, such as
\((a-b)^3 = a^3 - 3a^2b + 3ab^2 - b^3\). This formula simplifies the process significantly. In this exercise, the binomial being worked with is \((x-3)\), meaning \(a = x\) and \(b = 3\). Using this specific formula saves a great deal of time and simplifies complex calculations, making it easier to handle algebraic expressions more efficiently.
- \((a + b)\)
\((a-b)^3 = a^3 - 3a^2b + 3ab^2 - b^3\). This formula simplifies the process significantly. In this exercise, the binomial being worked with is \((x-3)\), meaning \(a = x\) and \(b = 3\). Using this specific formula saves a great deal of time and simplifies complex calculations, making it easier to handle algebraic expressions more efficiently.
Algebraic Expressions
Algebraic expressions are a fundamental building block in mathematics. They involve combinations of numbers, variables, and operations. In the expression \((x-3)^3\), we have a simple algebraic expression composed of a variable \(x\) and a constant \(3\).
- Variables are symbols that represent numbers, typically changing based on given conditions or equations. Here, \(x\) can be any number.
- Constants are fixed numbers, like the 3 in our binomial.
Simplification
Simplification is an important concept in algebra that aims to make expressions easier to understand and solve. It involves reducing expressions to their simplest form.
In the exercise given, after expanding the binomial cube \((x-3)^3\) using the special product formula, we simplify it to the expression \(x^3 - 9x^2 + 27x - 27\). This involves performing calculations to combine like terms, if any, and ensure the expression reflects its most reduced form.
In the exercise given, after expanding the binomial cube \((x-3)^3\) using the special product formula, we simplify it to the expression \(x^3 - 9x^2 + 27x - 27\). This involves performing calculations to combine like terms, if any, and ensure the expression reflects its most reduced form.
- Combine terms: Look for terms that can be added or subtracted.
- Be precise: Ensuring each step in the simplification maintains the equality of the expression.
Other exercises in this chapter
Problem 68
Factor the expression completely. $$ 3 x^{3}-27 x $$
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Simplify the compound fractional expression. $$ \frac{\frac{x+2}{x-1}-\frac{x-3}{x-2}}{x+2} $$
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\(47-72\) . Simplify the expression, and eliminate any negative exponent(s). $$ \left(\frac{y}{5 x^{-2}}\right)^{-3} $$
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