Problem 68
Question
Let \(\mathrm{A}\) and \(\mathrm{B}\) denote the statements A: \(\cos \alpha+\cos \beta+\cos \lambda=0\) B: \(\sin \alpha+\sin \beta+\sin \lambda=0\) If \(\cos (\beta-\lambda)+\cos (\beta-\alpha)+\cos (\alpha-\beta)=-\frac{3}{2}\), then (A) A is true and B is false (B) A is false and \(\mathrm{B}\) is true (C) both \(\mathrm{A}\) and \(\mathrm{B}\) are true (D) both A and B are false
Step-by-Step Solution
Verified Answer
(C) both A and B are true.
1Step 1: Analyze given cosine equation
We start with the equation \( \cos (\beta - \lambda) + \cos (\beta - \alpha) + \cos (\alpha - \beta) = -\frac{3}{2} \). This suggests that the angular differences have a particular relationship that might help us deduce something about the individual angles.
2Step 2: Simplify using cosine identity
We use the formula \( \cos(A - B) = \cos A \cos B + \sin A \sin B \) and apply it to all terms: \( \cos(\beta - \lambda), \cos(\beta - \alpha), \text{ and } \cos(\alpha - \beta). \) This is equivalent to having the identity forms lying on axes of an equilateral triangle. It only holds if angles are \(120^{\circ}, -120^{\circ}, \text{and } 0^{\circ}. \)
3Step 3: Verify cosine condition
If the angles are equilateral as described above, the sum of their respective cosines should cancel out. Thus \( \cos(\alpha) + \cos(\beta) + \cos(\lambda) = 0 \), satisfying statement A.
4Step 4: Verify sine condition
Similarly check the sine values. With equilateral angles, the sine sums also cancel \( \sin(\alpha) + \sin(\beta) + \sin(\lambda) = 0 \), thereby satisfying statement B as well.
5Step 5: Determine truth values of A and B
Given both verifications, both conditions A and B are true according to their equations.
Key Concepts
Cosine LawSine RuleEquilateral Triangle Angles
Cosine Law
The Cosine Law is a fundamental principle in trigonometry, particularly useful in solving triangles. It connects the sides of a triangle to the cosine of one of its angles. In any triangle with sides denoted as \(a\), \(b\), and \(c\), and angle \(C\) opposite side \(c\), the formula is:
\[c^2 = a^2 + b^2 - 2ab \cdot \cos C\]This law helps in situations where you know:
\[c^2 = a^2 + b^2 - 2ab \cdot \cos C\]This law helps in situations where you know:
- Two sides and the included angle, allowing you to find the third side.
- All three sides, enabling you to calculate any angle.
Sine Rule
The Sine Rule, or Sine Law, is another valuable tool in trigonometry for solving triangles. It relates the sides of a triangle to the sines of its angles. The formula is:
\[\frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C}\]This rule is particularly useful when:
\[\frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C}\]This rule is particularly useful when:
- You need to know a side opposite a given angle, and you have another side and angle known.
- You need to find an angle given two sides and an angle not sandwiched between those sides.
Equilateral Triangle Angles
Equilateral triangles are intriguing in trigonometry due to their symmetry. All sides and angles are equal. This special property means each angle in an equilateral triangle is \(60^{\circ}\). However, in the exercise, we dive into a less conventional perspective where angles behave like \(120^{\circ}, -120^{\circ}, \) and \(0^{\circ}\). Here's why this works:
- Adding these angles maintains their circular nature, adding up to a full circle or a rearranged congruency.
- The cosine and sine relationships here simplify due to repeated and symmetric behavior, like canceling out to zero.
Other exercises in this chapter
Problem 65
The number of values of \(x\) in the interval \([0,3 \pi]\) satisfying the equation \(2 \sin ^{2} x+5 \sin x-3=0\) is (A) 4 (B) 6 (C) 1 (D) 2
View solution Problem 66
A triangular park is enclosed on two sides by a fence and on the third side by a straight river bank. The two sides having fence are of same length \(x\). The m
View solution Problem 69
Let \(\cos (\alpha+\beta)=\frac{4}{5}\) and \(\sin (\alpha-\beta)=\frac{5}{13}\), where \(0 \leq \alpha, \beta \leq \frac{\pi}{4}\), then \(\tan 2 \alpha=\) (A)
View solution Problem 70
For a regular polygon, let \(r\) and \(R\) be the respective radii of the inscribed and the circumscribed circles. A false statement among the following is [201
View solution