Problem 68
Question
In redesigning a piece of equipment, you need to replace a solid spherical part of mass \(M\) with a hollow spherical shell of the same size. If both parts must spin at the same rate about an axis through their center, and the new part must have the same kinetic energy as the old one, what must be the mass of the new part in terms of \(M ?\)
Step-by-Step Solution
Verified Answer
The mass of the hollow sphere must be \( \frac{3}{5}M \).
1Step 1: Understanding Kinetic Energy in Rotation
The kinetic energy due to rotation for any object is given by \[ KE = \frac{1}{2}I\omega^2 \] where \( I \) is the moment of inertia and \( \omega \) is the angular velocity. For two objects to have the same kinetic energy with the same angular velocity, their moments of inertia about the axis must be equal.
2Step 2: Moment of Inertia of a Solid Sphere
The moment of inertia for a solid sphere rotating about its diameter is \[ I_{solid} = \frac{2}{5}MR^2 \] where \( M \) is the mass and \( R \) is the radius.
3Step 3: Moment of Inertia of a Hollow Sphere
The moment of inertia for a hollow sphere rotating about its diameter is \[ I_{hollow} = \frac{2}{3}mR^2 \] where \( m \) is the mass of the hollow sphere and \( R \) is its radius. Since the hollow shell and the solid sphere have the same size, \( R \) is the same for both.
4Step 4: Equating the Moments of Inertia
Since both spheres must have the same kinetic energy with identical angular velocity, their moments of inertia must be equal: \[ I_{solid} = I_{hollow} \]Thus, \[ \frac{2}{5}MR^2 = \frac{2}{3}mR^2 \]
5Step 5: Solving for Mass of the Hollow Sphere
Cancel \( R^2 \) on both sides of the equation and solve for \( m \):\[ \frac{2}{5}M = \frac{2}{3}m \]Multiply through by 15 to clear fractions:\[ 6M = 10m \]Divide by 10:\[ m = \frac{3}{5}M \]
Key Concepts
Kinetic EnergyMoment of InertiaRotational Dynamics
Kinetic Energy
Kinetic energy is the energy an object possesses due to its motion. In the context of rotational motion, this energy is captured by the formula:
In our example, to maintain the same kinetic energy with a switch from a solid to a hollow sphere, we adjusted the mass of the hollow sphere to keep their energy outputs equivalent.
- \[ KE = \frac{1}{2}I\omega^2 \] where \( KE \) is the kinetic energy, \( I \) is the moment of inertia, and \( \omega \) is the angular velocity.
In our example, to maintain the same kinetic energy with a switch from a solid to a hollow sphere, we adjusted the mass of the hollow sphere to keep their energy outputs equivalent.
Moment of Inertia
The moment of inertia, denoted as \( I \), is a property of an object that quantifies its resistance to rotational motion. It varies with the mass distribution relative to the axis of rotation. For a solid sphere, it is calculated as:
- \[ I_{solid} = \frac{2}{5}MR^2 \]
- For a hollow sphere, the formula is slightly different: \[ I_{hollow} = \frac{2}{3}mR^2 \]
Rotational Dynamics
Rotational dynamics deals with the motion of objects that are rotating or spinning and involves complex interactions between forces and moments. Key elements such as angular velocity, torque, and moment of inertia all interact within this field. When addressing a redesign of machinery with rotating parts like spheres, understanding these interactions is crucial.
- The angular velocity \( \omega \) is vital because it retains similarity in both spheres as required in our scenario.
- Equally important is achieving equal kinetic energy offering a seamless transition in machinery operations despite the change in component type.
Other exercises in this chapter
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