Problem 68
Question
In Exercises 67–82, find each product. $$ (x+9 y)(6 x+7 y) $$
Step-by-Step Solution
Verified Answer
The product of the binomials \( (x+9y)(6x+7y) \) is \(6x^2 + 61xy + 63y^2\)
1Step 1: Distribute First Term of First Binomial
Multiply the first term of the first binomial (which is \(x\)) by each term in the second binomial. So, \(x * 6x = 6x^2\) and \(x * 7y = 7xy\).
2Step 2: Distribute Second Term of First Binomial
Multiply the second term of the first binomial (which is \(9y\)) by each term in the second binomial. So, \(9y * 6x = 54xy\) and \(9y * 7y = 63y^2\).
3Step 3: Combine Like Terms
Summarise all the results from the above steps in the form \(ax^2+ bxy + cy^2\). So, the expression becomes: \(6x^2 + 61xy + 63y^2\).
Key Concepts
Binomial ExpansionLike TermsDistributive Property
Binomial Expansion
When we talk about binomial expansion, we're referring to the process of multiplying two binomials. A binomial is an algebraic expression that contains two terms, like \((a + b)\) or \((x - y)\). To expand them, each term in the first binomial is multiplied by each term in the second binomial. This ensures that every possible combination of terms is created.
For example, in the exercise given, we have the binomials \((x+9y)\) and \((6x+7y)\). The first step in expanding is to individually multiply \(x\) and \(9y\) by each term in the second binomial. You'll get several results that need to be combined in the end. Binomial expansion is often visualized by the FOIL method (First, Outer, Inner, Last), but in problems like these, it's better to think of simply distributing terms.
For example, in the exercise given, we have the binomials \((x+9y)\) and \((6x+7y)\). The first step in expanding is to individually multiply \(x\) and \(9y\) by each term in the second binomial. You'll get several results that need to be combined in the end. Binomial expansion is often visualized by the FOIL method (First, Outer, Inner, Last), but in problems like these, it's better to think of simply distributing terms.
Like Terms
In algebra, 'like terms' are terms that contain the same variables, with corresponding variables having the same exponents. Like terms can be combined to simplify expressions.
In the context of the exercise, after multiplying the binomials, you get several terms: \(6x^2\), \(7xy\), \(54xy\), and \(63y^2\). Notice that \(7xy\) and \(54xy\) are like terms because they both contain the same variables \(xy\). These terms can be combined by simply adding their coefficients, resulting in \(61xy\). Always remember that you can only combine terms that have precisely the same variables and powers.
In the context of the exercise, after multiplying the binomials, you get several terms: \(6x^2\), \(7xy\), \(54xy\), and \(63y^2\). Notice that \(7xy\) and \(54xy\) are like terms because they both contain the same variables \(xy\). These terms can be combined by simply adding their coefficients, resulting in \(61xy\). Always remember that you can only combine terms that have precisely the same variables and powers.
Distributive Property
The distributive property is a key algebraic principle used in multiplication to expand expressions. It states that you can distribute a multiplication operation over an addition or subtraction operation within parentheses.
In simpler terms, if you have the expression \(a(b + c)\), it can be expanded to \(ab + ac\). This principle is what guides the entire process of binomial expansion. When you're expanding the binomial \((x+9y)(6x+7y)\), it works step-wise: \(x\) is distributed over \(6x\) and \(7y\), and similarly with \(9y\).
Each multiplication is then summed up according to the distributive property, simplifying to the final expression.
In simpler terms, if you have the expression \(a(b + c)\), it can be expanded to \(ab + ac\). This principle is what guides the entire process of binomial expansion. When you're expanding the binomial \((x+9y)(6x+7y)\), it works step-wise: \(x\) is distributed over \(6x\) and \(7y\), and similarly with \(9y\).
- The first set of multiplications involve the first term of one binomial being multiplied by all terms of the other binomial.
- The second set involves the second term of the first binomial being distributed over all terms of the second.
Each multiplication is then summed up according to the distributive property, simplifying to the final expression.
Other exercises in this chapter
Problem 67
Express the distance between the given numbers using absolute value. Then find the distance by evaluating the absolute value expression. $$2\quad and\quad 17$$
View solution Problem 68
simplify each complex rational expression. $$ \frac{\frac{x}{x-2}+1}{\frac{3}{x^{2}-4}+1} $$
View solution Problem 68
Factor completely, or state that the polynomial is prime. $$6 x^{2}-18 x-60$$
View solution Problem 68
Simplify the radical expressions in Exercises \(67-74\) if possible. $$ \sqrt[3]{150} $$
View solution