Problem 68
Question
In Exercises \(67 - 70\) , use the following function. \(f ( x ) = \left\\{ \begin{array} { l l } { 2 - x , } & { x \leq 1 } \\ { \frac { x } { 2 } + 1 , } & { x > 1 } \end{array} \right.\) Multiple Choice What is the value of \(\lim _ { x \rightarrow 1 } + f ( x ) ?\) (A) 5\(/ 2\) \(( \mathrm { B } ) 3 / 2\) \(( \mathbf { C } ) 1\) \(( \mathbf { D } ) 0\) (E) does not exist
Step-by-Step Solution
Verified Answer
(B) 3/2
1Step 1: Identify the Relevant Function Definition
Since the question asks for the limit as x approaches 1 from the right (\(x \rightarrow 1 ^+ \)), examine the definition of f(x) for \(x > 1\), which is \(x/2 + 1\).
2Step 2: Substitute Limit Value
Next, substitute the value of x=1 into the function definition, so it becomes \(1/2 + 1 = 3/2\).
3Step 3: Conclude the Result
The value obtained is the limit of the function as \(x \rightarrow 1 ^+ \). Thus, \( \lim _ { x \rightarrow 1 } + f ( x ) = 3/2 \)
Key Concepts
LimitsPiecewise FunctionsRight-Hand Limit
Limits
In calculus, limits help us understand the behavior of a function as its input approaches a certain value. It's like trying to find out what happens to the function's output as we get really close to a specific input value. Limits are a foundational concept because they are used to define derivatives and integrals, which are crucial to calculus.
Here are a few key points to consider about limits:
It's important to note that limits can be one-sided, meaning they can approach the point from the left or the right.
- They help describe how functions behave at boundary points.
- Limits look at the value a function approaches, not necessarily the value the function actually takes at that point.
- They are used to determine the continuity of a function, among many other things.
It's important to note that limits can be one-sided, meaning they can approach the point from the left or the right.
Piecewise Functions
Piecewise functions are those that have different expressions for different intervals of their domain. In simpler terms, it is one function that is broken into multiple parts, and each part has its expression or rule depending on the value of the input.
Here’s how piecewise functions are structured:
- They consist of two or more "pieces," each with its own function rule.
- Each piece applies to a specific interval of the input values.
- The function can be continuous or discontinuous depending on how the pieces connect at the endpoints of their intervals.
Right-Hand Limit
The right-hand limit refers to understanding what happens to a function's output as the input approaches a certain point from the right, or greater values. It's a part of studying one-sided limits, where the input approaches the specific value from one direction only.
Here's how the right-hand limit is analyzed:
- Identify which part of the piecewise function applies as the input approaches the point from the right.
- Plug the point value into this piece's expression if applicable, or analyze the limit behavior.
- The right-hand limit is particularly useful in determining the continuity and differentiability at points where the function definition changes.
Other exercises in this chapter
Problem 66
The Greatest Integer Function (a) Show that $$\frac{x-1}{x}0)$$ and $$\frac{x-1}{x}>\frac{\text { int } x}{x} \geq 1(x
View solution Problem 67
In Exercises \(67 - 70\) , use the following function. \(f ( x ) = \left\\{ \begin{array} { l l } { 2 - x , } & { x \leq 1 } \\ { \frac { x } { 2 } + 1 , } & {
View solution Problem 68
Writing to Learn Explain why there is no value \(L\) for which \(\lim _{x \rightarrow \infty} \sin x=L\)
View solution Problem 69
In Exercises \(67 - 70\) , use the following function. \(f ( x ) = \left\\{ \begin{array} { l l } { 2 - x , } & { x \leq 1 } \\ { \frac { x } { 2 } + 1 , } & {
View solution