Problem 68
Question
If \(f(x)\) defines a constant function over \((-\infty, \infty),\) how many elements are in the range of \((f \circ f)(x) ?\)
Step-by-Step Solution
Verified Answer
There is 1 element in the range of \((f \circ f)(x)\).
1Step 1: Understanding Constant Functions
A constant function is a function that always returns the same value no matter what the input is. If \( f(x) = c \), where \(c\) is a constant, the range of \(f(x)\) is \( \{c\} \), meaning it has only one element.
2Step 2: Defining the Composition Function
The composition of a function \(f\) with itself, denoted \((f \circ f)(x)\), means applying \(f\) to the result of \(f(x)\). Given \( f(x) = c \), applying \(f\) again results in \( f(c) \), which is still \(c\). Therefore, \( (f \circ f)(x) = c \).
3Step 3: Determine the Range of the Composite Function
Since \((f \circ f)(x) = c\) for all \(x\), the range of \((f \circ f)(x)\) is the set containing only \(c\). Thus, there is only one element in the range, \( \{c\} \).
Key Concepts
Function CompositionRange of a FunctionComposite Function
Function Composition
Function composition is a fundamental concept in mathematics, allowing us to build new functions by combining existing ones. When you compose two functions, you're essentially feeding the output of one function directly into another function. Let's break this down a bit more.
Suppose you have two functions, say \( f(x) \) and \( g(x) \). The composition of these functions, denoted by \((f \circ g)(x)\), means you first apply \(g(x)\), and then take the result to apply \(f\) on it.
Suppose you have two functions, say \( f(x) \) and \( g(x) \). The composition of these functions, denoted by \((f \circ g)(x)\), means you first apply \(g(x)\), and then take the result to apply \(f\) on it.
- Order matters: When composing functions, the order of operation is important - \((f \circ g)(x)\) is not the same as \((g \circ f)(x)\) unless \(f(x)\) and \(g(x)\) are specifically designed functions like constant functions.
- Notation: The notation \((f \circ g)(x)\) is shorthand for \(f(g(x))\). This tells us to apply \(g\) first, then \(f\).
- Example: If \(g(x) = 2x\) and \(f(x) = x + 3\), then \((f \circ g)(x) = f(2x)\) which simplifies to \(2x + 3\).
Range of a Function
The range of a function is the set of all possible output values it can produce. It is essential in understanding the behavior and scope of a function, giving insight into what values the function can take under different input scenarios.
For a constant function like \(f(x) = c\), the range is quite straightforward. Since every input \(x\) yields the output \(c\), the range is simply \(\{c\}\), a set with a single element.
For a constant function like \(f(x) = c\), the range is quite straightforward. Since every input \(x\) yields the output \(c\), the range is simply \(\{c\}\), a set with a single element.
- Constant function range: For a function \(f(x) = c\), regardless of what \(x\) is, \(f(x)\) always equals \(c\). Thus, the range is always \(\{c\}\).
- Range in terms of composite functions: When considering the range of a composite function like \((f \circ f)(x)\), the range remains constrained by the constant values achieved by \(f\).
- General understanding: For functions that are not constant, the range can be more diverse and is influenced by the nature of the function itself.
Composite Function
Composite functions are a marvel of mathematical design, letting us encapsulate more complex behaviors by nesting functions within one another. This method can simplify problem-solving by reducing large steps into smaller, more manageable processes.
Let's delve into how this applies to a constant function like \(f(x) = c\). When you compose \(f\) with itself, we get \((f \circ f)(x)\). Since \(f(x)\) outputs a constant \(c\) for any \(x\), the composite function \((f \circ f)(x)\) mirrors this behavior. The result is also a constant \(c\), showing that the compositional layers do not add complexity in this case.
Let's delve into how this applies to a constant function like \(f(x) = c\). When you compose \(f\) with itself, we get \((f \circ f)(x)\). Since \(f(x)\) outputs a constant \(c\) for any \(x\), the composite function \((f \circ f)(x)\) mirrors this behavior. The result is also a constant \(c\), showing that the compositional layers do not add complexity in this case.
- Understanding \((f \circ f)(x)\): Here \((f \circ f)(x) = f(f(x)) = f(c) = c\). This continues from the fact that the output of \(f(x)\) provides no new variables.
- Simplicity in constancy: Even when functions are composed, if they are constant, the overall behavior remains unchanged. Hence, the range becomes a singular element, \(\{c\}\).
- Wider applications: While constant compositions are simple, in variable functions, composite structures can merge simplicity with complexity.
Other exercises in this chapter
Problem 67
Use the analytic method of Example 3 to determine whether the graph of the given function is symmetric with respect to the \(y\) -axis, symmetric with respect t
View solution Problem 67
Let the domain of \(f(x)\) be \([-1,2]\) and the range be \([0,3] .\) Find the domain and range of the following. $$-f(x)$$
View solution Problem 68
An equation of the form \(|f(x)|=|g(x)|\) is given. (a) Solve the equation analytically and support the solution graphically. (b) Solve \(|f(x)|>|g(x)|\) (c) So
View solution Problem 68
Use the analytic method of Example 3 to determine whether the graph of the given function is symmetric with respect to the \(y\) -axis, symmetric with respect t
View solution