Problem 68
Question
If \(f(2)=6,\) find \(x\) satisfying \(8+f^{-1}(x-1)=10\)
Step-by-Step Solution
Verified Answer
The solution for \(x\) is 7.
1Step 1: Simplify the Equation
Firstly, simplify the equation \(8 + f^{-1}(x - 1) = 10\) by subtracting 8 from both sides. Thus, it gives \(f^{-1}(x - 1) = 2\).
2Step 2: Identify the inverse function
Based on \(f(2) = 6\), and since the inverse function undoes the action of the function, it implied that \(f^{-1}(6) = 2\). Considering this and the equation from step 1, we can replace \(f^{-1}(x - 1) = 2\) with \(x - 1 = 6\).
3Step 3: Calculate 'x'
Finally, rearrange \(x - 1 = 6\) by adding 1 to both sides. This gives \(x = 6 + 1 = 7\).
Key Concepts
Function NotationSolving EquationsAlgebraic Manipulation
Function Notation
Function notation is a way to represent the relationship between input and output values in functions clearly. It is a fundamental concept in algebra and is expressed generally as \(f(x)\), where \(f\) is the function and \(x\) is the input value.
In this form, \(f(x)\) indicates the output derived when \(x\) is the input.
In this form, \(f(x)\) indicates the output derived when \(x\) is the input.
- For example, if \(f(2) = 6\), it means when \(x\) is 2, the output, or \(f(x)\), is 6.
- Similarly, inverse function notation, \(f^{-1}(x)\), represents the reverse operation. If \(f(x)\) transforms \(x\) to a certain \(y\), \(f^{-1}(y)\) converts \(y\) back to \(x\).
Solving Equations
Solving equations involves finding values for unknown variables that make the equation true. Understanding how to simplify expressions and transform equations is key.
In the provided exercise, start by simplifying the expression \(8 + f^{-1}(x - 1) = 10\).
In the provided exercise, start by simplifying the expression \(8 + f^{-1}(x - 1) = 10\).
- Subtract 8 from both sides to isolate the inverse function: \(f^{-1}(x - 1) = 2\).
- This operation ensures the equation is in a simpler form, making it easier to analyze and solve.
- Be precise in each step to avoid errors, and always verify your solution by substituting back into the original equation.
Algebraic Manipulation
Algebraic manipulation is the process of rearranging and simplifying algebraic expressions to isolate variables. It is essential in finding solutions to equations.
In our problem, once we determined \(f^{-1}(x - 1) = 2\), we use algebraic manipulation to find \(x\).
In our problem, once we determined \(f^{-1}(x - 1) = 2\), we use algebraic manipulation to find \(x\).
- Replace the inverse function by its known value: \(x - 1 = 6\).
- To isolate \(x\), add 1 to both sides of the equation: \(x - 1 + 1 = 6 + 1\), resulting in \(x = 7\).
Other exercises in this chapter
Problem 67
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