Problem 68
Question
Fish are indeterminate growers; that is, they grow throughout their lifetime. The growth of fish can be described by the von Bertalanffy function $$ L(x)=L_{\infty}\left(1-e^{-k x}\right) $$ for \(x \geq 0\), where \(L(x)\) is the length of the fish at age \(x\) and \(k\) and \(L_{\infty}\) are positive constants. (a) Use a graphing calculator to graph \(L(x)\) for \(L_{\infty}=20\), for (i) \(k=1\) and (ii) \(k=0.1\). (b) For \(k=1\), find \(x\) so that the length is \(90 \%\) of \(L_{\infty} .\) Repeat for \(99 \%\) of \(L_{\infty} .\) Can the fish ever attain length \(L_{\infty}\) ? Interpret the meaning of \(L_{\infty}\) (c) Compare the graphs obtained in (a). Which growth curve reaches \(90 \%\) of \(L_{\infty}\) faster? Can you explain what happens to the curve of \(L(x)\) when you vary \(k\left(\right.\) for fixed \(\left.L_{\infty}\right)\) ?
Step-by-Step Solution
VerifiedKey Concepts
Indeterminate Growth
Asymptotic Maximum Length
Growth Rate Constant
Graphing Calculator
- when \(k = 1\), the graph shows a steep curve indicating rapid growth towards \(L_{\infty}\).
- When \(k = 0.1\), the growth curve is more gradual and takes longer to approach \(L_{\infty}\).