Problem 68
Question
Find the \(5^{\text {th }}\) term of the arithmetic sequence \(\\{9 b, 5 b, b, \ldots\\}\).
Step-by-Step Solution
Verified Answer
The 5th term is \(-7b\).
1Step 1: Identify the Sequence Terms
The given sequence starts with the terms \(9b, 5b, b, \ldots\). Let's denote the first term (\(a_1\)) as \(9b\) and the second term (\(a_2\)) as \(5b\).
2Step 2: Find the Common Difference
The common difference \(d\) in an arithmetic sequence is found by subtracting the first term from the second term. Thus, \(d = a_2 - a_1 = 5b - 9b = -4b\).
3Step 3: Use the Arithmetic Sequence Formula
The formula to find the \(n^{\text{th}}\) term of an arithmetic sequence is \(a_n = a_1 + (n-1) \cdot d\). We want to find the 5th term (\(a_5\)).
4Step 4: Calculate the 5th Term
Substitute \(a_1 = 9b\), \(d = -4b\), and \(n = 5\) into the formula: \[a_5 = 9b + (5-1) \cdot (-4b) \]. Simplifying this provides: \[a_5 = 9b - 16b = -7b\].
Key Concepts
Common DifferenceArithmetic Sequence FormulaTerm Calculation
Common Difference
In an arithmetic sequence, the common difference is a key feature that sets the pattern between consecutive terms. It can be thought of as the consistent "step size" that you repeatedly add (or subtract) to progress from one term to the next. Finding the common difference requires you to subtract the first term from the second.
For instance, in the given sequence with terms \(9b, 5b, b, \ldots\), the calculation goes like this:
For instance, in the given sequence with terms \(9b, 5b, b, \ldots\), the calculation goes like this:
- First term, \(a_1 = 9b\)
- Second term, \(a_2 = 5b\)
- \(d = a_2 - a_1 = 5b - 9b = -4b\)
Arithmetic Sequence Formula
To efficiently determine any term in an arithmetic sequence, we make use of the arithmetic sequence formula. This formula plays a pivotal role as it links the sequence’s first term, the common difference, and any desired term position all together. Understanding this formula can help simplify your calculations greatly.
The standard formula to find the \(n^{\text{th}}\) term, \(a_n\), is written as:
The standard formula to find the \(n^{\text{th}}\) term, \(a_n\), is written as:
- \(a_n = a_1 + (n-1) \cdot d\)
- \(a_1\) is your initial term in the sequence
- \((n-1)\) indicates how many steps away you are from the first term
- \(d\) is the common difference
Term Calculation
When tasked with finding a specific term within an arithmetic sequence, applying the arithmetic sequence formula simplifies the process. Let's walk through calculating the 5th term as in our exercise.
First, identify what you already know:
First, identify what you already know:
- First term \(a_1 = 9b\)
- Common difference \(d = -4b\)
- Desired term position \(n = 5\)
- \(a_5 = a_1 + (n-1) \cdot d\)
- \(a_5 = 9b + (5-1) \cdot (-4b)\)
- \(a_5 = 9b - 16b = -7b\)
Other exercises in this chapter
Problem 67
Give two examples of arithmetic sequences whose \(10^{\text {th }}\) terms are \(206 .\)
View solution Problem 67
Consider the sequence defined by \(a_{n}=-6-8 n .\) Is \(a_{n}=-421\) a term in the sequence? Verify the result.
View solution Problem 68
What term in the sequence \(a_{n}=\frac{n^{2}+4 n+4}{2(n+2)}\) has the value \(41 ?\) Verify the result.
View solution Problem 69
Find the \(11^{\text {th }}\) term of the arithmetic sequence \(\\{3 a-2 b, a+2 b,-a+6 b \ldots\\}\).
View solution