Problem 68
Question
Factor completely. $$64 x^{2}-112 x+49$$
Step-by-Step Solution
Verified Answer
The completely factored form of the given expression is: \((2x - 1)(32x - 3)\).
1Step 1: Identify the common factors for each term
Let's first identify if there are common factors for each term in the expression:
- For \(64x^2\), the factors are: \(2\), \(4\), \(8\), \(16\), \(32\), and \(64\).
- For \(112x\), the factors are: \(2\), \(4\), \(7\), \(14\), \(28\), and \(56\).
- For \(49\), the factors are: \(1\), \(7\), and \(49\).
The greatest common factor for all three terms seems to be 1, therefore we will need to continue to the next step.
2Step 2: Group the terms and factor by grouping
Now, let's try to factor the expression by grouping. We split the middle term into two terms, so that each of the resulting groups has a common factor.
We notice that \(112x\) can be written as \(32x\cdot3\).
So, the expression can be rewritten as:
\(64x^2 - 32x\cdot3 + 49\)
Now, we can group the terms as:
\((64x^2 - 32x) + (- 3x + 49)\)
3Step 3: Factor the common factor from each group
Now, we factor out the common factor from each group:
\(32x(2x - 1) - 3(2x - 1)\)
4Step 4: Factor the common binomial factor
Now, we can see a common binomial factor \((2x - 1)\) in both terms. Let's factor that out as well:
\((2x - 1)(32x - 3)\)
Our quadratic trinomial is now factored completely as:
\((2x - 1)(32x - 3)\)
Key Concepts
Quadratic TrinomialsGreatest Common FactorFactor by Grouping
Quadratic Trinomials
A quadratic trinomial is a polynomial with three terms, typically expressed in the standard form as \(ax^2 + bx + c\), where:
Each term contributes to the overall form and dictates the strategies used to factor it effectively. For instance, identifying that our trinomial fits the quadratic format helps us look for perfect square patterns or suitable grouping techniques to factor completely.
- \(a\), \(b\), and \(c\) are constants
- \(x\) is the variable
- The degree of the polynomial is 2, given by the highest power of \(x\)
Each term contributes to the overall form and dictates the strategies used to factor it effectively. For instance, identifying that our trinomial fits the quadratic format helps us look for perfect square patterns or suitable grouping techniques to factor completely.
Greatest Common Factor
The Greatest Common Factor (GCF) is the largest factor that divides all coefficients of the terms in the polynomial. Finding the GCF is an essential first step in simplifying expressions. It helps simplify the expression early on, reducing complexity.
By examining the polynomial given, \(64x^2 - 112x + 49\), you check the coefficients of each term:
Even if the GCF is trivial, performing this check can highlight opportunities for simplifying specific terms of the polynomial.
By examining the polynomial given, \(64x^2 - 112x + 49\), you check the coefficients of each term:
- 64 for \(64x^2\)
- 112 for \(-112x\)
- 49 for the constant term
Even if the GCF is trivial, performing this check can highlight opportunities for simplifying specific terms of the polynomial.
Factor by Grouping
Factoring by grouping is a technique used when the quadratic trinomial can be split into smaller expressions that reveal common factors. This involves rearranging or rewriting the trinomial in such a way that the expression becomes easier to manage.
Here, we attempt to break down \(64x^2 - 112x + 49\) by finding a smarter way to manage the middle term \(-112x\). It is split into terms like \((64x^2 - 32x) + (-3x + 49)\), so it pairs with a partner for easier factoring.
Here, we attempt to break down \(64x^2 - 112x + 49\) by finding a smarter way to manage the middle term \(-112x\). It is split into terms like \((64x^2 - 32x) + (-3x + 49)\), so it pairs with a partner for easier factoring.
- The first group \(64x^2 - 32x\) reveals a factor of \(32x\)
- The second group \(-3x + 49\) has no visible common factor, but matches a potential shared expression, leading to \((2x - 1)(32x - 3)\)
Other exercises in this chapter
Problem 68
The following equations are not quadratic but can be solved by factoring and applying the zero product rule. Solve each equation. $$14 a^{2}-49 a=a^{3}$$
View solution Problem 68
Factor by grouping. $$h k+6 k-4 h-24$$
View solution Problem 68
Factor completely, if possible. Begin by asking yourself, "Can I factor out a GCF?" $$p^{2}-7 p q-12 q^{2}$$
View solution Problem 69
Factor completely. $$3 x^{2}(y+6)^{2}-11 x(y+6)^{2}-20(y+6)^{2}$$
View solution