Problem 68
Question
Convert the polar equation to rectangular coordinates. $$\cos 2 \theta=1$$
Step-by-Step Solution
Verified Answer
The rectangular equation is the x-axis, where \( y = 0 \).
1Step 1: Understand the Polar Equation
The given polar equation is \( \cos 2\theta = 1 \). Our goal is to convert this equation into rectangular coordinates (\(x, y\)).
2Step 2: Use Double Angle Identity
Remember the trigonometric identity \( \cos^2\theta - \sin^2\theta = \cos 2\theta\). Here, \( \cos 2\theta = 1 \) implies \( \cos^2\theta - \sin^2\theta = 1 \).
3Step 3: Relationship with Rectangular Coordinates
Recall the relationships between polar and rectangular coordinates: \( x = r\cos\theta \) and \( y = r\sin\theta \). Also, note that \( r^2 = x^2 + y^2 \).
4Step 4: Replace Trigonometric Functions
Using the relationships, \(\cos\theta = \frac{x}{r}\) and \(\sin\theta = \frac{y}{r}\). Thus, \( \cos^2\theta = \frac{x^2}{r^2} \) and \( \sin^2\theta = \frac{y^2}{r^2} \).
5Step 5: Substitute and Simplify
Substitute these into the identity: \( \frac{x^2}{r^2} - \frac{y^2}{r^2} = 1 \). Since \( r^2 = x^2 + y^2 \), the equation becomes \( \frac{x^2}{x^2 + y^2} - \frac{y^2}{x^2 + y^2} = 1 \).
6Step 6: Simplify the Fraction
Combine the fractions: \( \frac{x^2 - y^2}{x^2 + y^2} = 1 \). Cross-multiply to solve for the equation: \( x^2 - y^2 = x^2 + y^2 \). This simplifies to \( -y^2 = y^2 \).
7Step 7: Solve the Resulting Equation
This further simplifies to \( 0 = 2y^2 \), which implies \( y^2 = 0 \). Thus, \( y = 0 \), so the rectangular equation simplifies to the x-axis.
Key Concepts
Polar EquationsTrigonometric IdentitiesCoordinate Transformation
Polar Equations
Polar equations make use of a different coordinate system compared to the more familiar rectangular or Cartesian coordinates. In this system, each point on the plane is determined by a distance from a reference point and an angle from a reference direction. These are represented as \( (r, \theta) \), where \( r \) is the radius (the distance from the pole, equivalent to the origin in rectangular coordinates) and \( \theta \) is the angle.
Polar coordinates are especially useful for problems involving circular or rotational symmetry. They simplify the representation of circles and spirals. In contrast, rectangular coordinates, expressed as \( (x, y) \), are better for linear problems.
Converting from polar to rectangular coordinates involves using the relationships \( x = r\cos\theta \) and \( y = r\sin\theta \). These equations allow one to translate polar expressions into the rectangular plane, making it easier to visualize certain problems without having to leave the rectangular grid behind.
Polar coordinates are especially useful for problems involving circular or rotational symmetry. They simplify the representation of circles and spirals. In contrast, rectangular coordinates, expressed as \( (x, y) \), are better for linear problems.
Converting from polar to rectangular coordinates involves using the relationships \( x = r\cos\theta \) and \( y = r\sin\theta \). These equations allow one to translate polar expressions into the rectangular plane, making it easier to visualize certain problems without having to leave the rectangular grid behind.
Trigonometric Identities
Trigonometric identities play a crucial role in converting polar equations into rectangular coordinates. They are equations involving trigonometric functions that are true for all values of involved variables. For this exercise, the double angle identity \( \cos 2\theta = \cos^2\theta - \sin^2\theta \) was particularly important.
This identity allowed us to express \( \cos 2\theta \) in terms of \( \cos\theta \) and \( \sin\theta \), laying the groundwork for converting the equation into a form involving \( x \) and \( y \).
This identity allowed us to express \( \cos 2\theta \) in terms of \( \cos\theta \) and \( \sin\theta \), laying the groundwork for converting the equation into a form involving \( x \) and \( y \).
- The double angle identity is useful when simplifying equations or expressions involving trigonometric functions.
- It can help in integrating or differentiating trigonometric equations.
- Investigating properties of trigonometric functions often requires the use of these identities.
Coordinate Transformation
The process of coordinate transformation involves changing the way a point or equation is represented from one coordinate system to another. In this scenario, we moved from polar coordinates to rectangular coordinates. Understanding transformations is crucial in mathematics, as different systems offer various advantages depending on the problem at hand.
Transforming the equation \( \cos 2\theta = 1 \) required knowledge of how to interchange variables using established relationships:
Coordinate transformations not only allow for easier computation but also provide insights such as simplifying integral calculus problems, examining symmetries, and solving differential equations across various applications in physics and engineering.
Transforming the equation \( \cos 2\theta = 1 \) required knowledge of how to interchange variables using established relationships:
- \( x = r\cos\theta \)
- \( y = r\sin\theta \)
- \( r^2 = x^2 + y^2 \) which combines the above two relations.
Coordinate transformations not only allow for easier computation but also provide insights such as simplifying integral calculus problems, examining symmetries, and solving differential equations across various applications in physics and engineering.
Other exercises in this chapter
Problem 68
Write \(z_{1}\) and \(z_{2}\) in polar form, and then find the product \(z_{1} z_{2}\) and the quotients \(z_{1} / z_{2}\) and \(1 / z_{1}\). $$z_{1}=3+4 i, \qu
View solution Problem 68
In this section we stated that parametric equations contain more information than just the shape of a curve. Write a short paragraph explaining this statement.
View solution Problem 69
Find the indicated power using De Moivre’s Theorem. $$(1+i)^{20}$$
View solution Problem 69
The curves \(C, D, E,\) and \(F\) are defined parametrically as follows, where the parameter \(t\) takes on all real values unless otherwise stated: $$C: \quad
View solution