Problem 68
Question
Consider the graph of \(r=f(\sin \theta)\). (a) Show that when the graph is rotated counterclockwise \(\pi / 2\) radians about the pole, the equation of the rotated graph is \(r=f(-\cos \theta)\). (b) Show that when the graph is rotated counterclockwise \(\pi\) radians about the pole, the equation of the rotated graph is \(r=f(-\sin \theta)\). (c) Show that when the graph is rotated counterclockwise \(3 \pi / 2\) radians about the pole, the equation of the rotated graph is \(r=f(\cos \theta)\).
Step-by-Step Solution
Verified Answer
The equations of the rotated graph for \(r=f(\sin \theta )\) are \(r=f(\cos \theta )\) after rotation by \(\pi / 2\) radians, \(r=f(-\sin \theta)\) after rotation by \(\pi\) radians, and \(r=f(-\cos \theta)\) after rotation by \(3 \pi / 2\) radians.
1Step 1: Rotate the graph by \(\pi / 2\) radians
Rotating the graph counterclockwise by \(\pi / 2\) radians amounts to replacing \(\theta\) with \(\theta - \pi / 2\). Thus, the equation of the rotated graph is \(r=f(\sin (\theta - \pi / 2))\). Now, using the identity \(\sin (\alpha - \beta) = \sin \alpha \cos \beta - \cos \alpha \sin \beta\), with \(\alpha=\theta\) and \(\beta=\pi / 2\), this gives \(r=f(\cos \theta)\), as \(\sin \pi / 2 = 1\) and \(\cos \pi / 2 = 0\). Therefore, this new equation represents the graph when it is rotated counterclockwise by \( \pi / 2\) radians about the pole.
2Step 2: Rotate the graph by \(\pi\) radians
Rotating the graph counterclockwise by \(\pi\) radians amounts to replacing \(\theta\) with \(\theta - \pi\). Thus, the equation of the rotated graph is \(r=f(\sin (\theta - \pi))\). Here, using the same trigonometric identity, we get \(r=f(-\sin \theta)\), as \(\sin \pi = 0\) and \(\cos \pi = -1\). This new equation represents the graph when it is rotated counterclockwise by \( \pi\) radians about the pole.
3Step 3: Rotate the graph by \(3 \pi / 2\) radians
Finally, rotating the graph counterclockwise by \(3 \pi / 2\) radians amounts to replacing \(\theta\) with \(\theta - 3 \pi / 2\). The equation of the rotated graph then becomes \(r=f(\sin (\theta - 3 \pi / 2))\). Using the relevant trigonometric identity again we get \(r=f(-\cos \theta)\), as \(\sin 3 \pi / 2 = -1\) and \(\cos 3 \pi / 2 = 0\). This new equation represents the graph when it is rotated counterclockwise by \( 3 \pi / 2\) radians about the pole.
Key Concepts
Trigonometric IdentitiesGraph RotationPolar Equations
Trigonometric Identities
Trigonometric identities are powerful tools used to simplify and solve problems involving angles and sides of triangles. They relate the angles of a triangle to the ratios of its sides, allowing for transformations and simplifications of expressions. In polar coordinates, these identities help in transforming polar equations through rotations or shifts.
For example, common trigonometric identities include:
For example, common trigonometric identities include:
- Pythagorean Identity: \( \sin^2 \theta + \cos^2 \theta = 1 \)
- Angle Addition Identities: \( \sin(\alpha + \beta) = \sin \alpha \cos \beta + \cos \alpha \sin \beta \)
- Angle Subtraction Identities: \( \sin(\alpha - \beta) = \sin \alpha \cos \beta - \cos \alpha \sin \beta \)
Graph Rotation
Understanding how graph rotation works is essential when dealing with polar equations. Rotating a graph in polar coordinates involves changing the angle \( \theta \) according to the direction and degree of rotation. This is particularly important in exercises where you need to visualize the placement of a graph after being rotated.
To rotate a graph counterclockwise:
To rotate a graph counterclockwise:
- By \( \pi / 2 \) radians, you replace \( \theta \) with \( \theta - \pi / 2 \). This means the sine in the original equation \( r=f(\sin \theta) \) should be transformed using trigonometric identities, ending up as \( r=f(-\cos \theta) \).
- For \( \pi \) radians, replace \( \theta \) with \( \theta - \pi \). The rotation affects your equation to become \( r=f(-\sin \theta) \).
- When you rotate by \( 3\pi / 2 \) radians, \( \theta \) becomes \( \theta - 3\pi / 2 \), resulting in \( r=f(\cos \theta) \).
Polar Equations
Polar equations represent points in the plane using a distance from a reference point and an angle from a reference direction. These equations offer a different perspective than Cartesian coordinates, dealing with curves that are esoteric or difficult to handle using standard linear equations.
Polar coordinates consist of:
By mastering polar equations, students can solve complex problems in physics and engineering, leveraging the unique benefits of this coordinate system for circular and spiral motion representation and beyond.
Polar coordinates consist of:
- The radial coordinate \( r \), which is the length from the pole (origin) to the point.
- The angular coordinate \( \theta \), which is the angle from the positive x-axis to the line connecting the pole with the point.
By mastering polar equations, students can solve complex problems in physics and engineering, leveraging the unique benefits of this coordinate system for circular and spiral motion representation and beyond.
Other exercises in this chapter
Problem 67
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