Problem 67 - Chemistry Central Science

Question

Write balanced equations for the following reactions: (a) barium oxide with water, (b) iron(II) oxide with perchloric acid, (c) sulfur trioxide with water, (d) carbon dioxide with aqueous sodium hydroxide.

Step-by-Step Solution

Answer

(a) BaO + H2O -> Ba(OH)2 (b) FeO + 2HClO4 -> Fe(ClO4)2 + H2O (c) SO3 + H2O -> H2SO4 (d) CO2 + 2NaOH -> Na2CO3 + H2O

Step 1: (a) Barium oxide with water

To write the balanced equation for the reaction between barium oxide (BaO) and water (H2O), we first predict the products. In this case, the reaction forms barium hydroxide (Ba(OH)2). Now, let's balance the equation: BaO + H2O -> Ba(OH)2 Looking at the equation, we can see that it is already balanced.

Step 2: (b) Iron(II) oxide with perchloric acid

Now, let's write the balanced equation for the reaction between iron(II) oxide (FeO) and perchloric acid (HClO4). Iron(II) oxide reacts with perchloric acid to form iron(II) perchlorate (Fe(ClO4)2) and water (H2O). The unbalanced equation looks like this: FeO + HClO4 -> Fe(ClO4)2 + H2O To balance the equation, we need 2 molecules of HClO4: FeO + 2HClO4 -> Fe(ClO4)2 + H2O The balanced equation for this reaction is: FeO + 2HClO4 -> Fe(ClO4)2 + H2O

Step 3: (c) Sulfur trioxide with water

Now, let's write the balanced equation for the reaction between sulfur trioxide (SO3) and water (H2O). The products of this reaction are sulfuric acid (H2SO4). The unbalanced equation looks like this: SO3 + H2O -> H2SO4 The equation is already balanced.

Step 4: (d) Carbon dioxide with aqueous sodium hydroxide

Finally, let's write the balanced equation for the reaction between carbon dioxide (CO2) and aqueous sodium hydroxide (NaOH). Carbon dioxide reacts with sodium hydroxide to form sodium carbonate (Na2CO3) and water (H2O). The unbalanced equation looks like this: CO2 + NaOH -> Na2CO3 + H2O To balance the equation, we need 2 molecules of NaOH: CO2 + 2NaOH -> Na2CO3 + H2O The balanced equation for this reaction is: CO2 + 2NaOH -> Na2CO3 + H2O