Problem 67 - Chemistry: The Central Science

Question

Write balanced equations for the following reactions: (a) barium oxide with water, (b) iron(II) oxide with perchloric acid, (c) sulfur trioxide with water, (d) carbon dioxide with aqueous sodium hydroxide.

Step-by-Step Solution

Answer

(a) \(\text{BaO} + \text{H}_2\text{O} \rightarrow \text{Ba(OH)}_2\) (b) \(\text{FeO} + 2\text{HClO}_4 \rightarrow \text{Fe(ClO}_4\text{)}_2 + \text{H}_2\text{O}\) (c) \(\text{SO}_3 + \text{H}_2\text{O} \rightarrow \text{H}_2\text{SO}_4\) (d) \(\text{CO}_2 + \text{NaOH} \rightarrow \text{NaHCO}_3\)

Step 1: a) Barium oxide with water

Step 1: Write the reactants Barium oxide: \(\text{BaO}\) Water: \(\text{H}_2\text{O}\) Step 2: Write the products Barium oxide will react with water to form barium hydroxide: Barium hydroxide: \(\text{Ba(OH)}_2\) Step 3: Balance the equation \[\text{BaO} + \text{H}_2\text{O} \rightarrow \text{Ba(OH)}_2\] The equation is balanced as there are equal numbers of each atom on both sides of the equation.

Step 2: b) Iron(II) oxide with perchloric acid

Step 1: Write the reactants Iron(II) oxide: \(\text{FeO}\) Perchloric acid: \(\text{HClO}_4\) Step 2: Write the products This reaction is an acid-base reaction forming iron(II) perchlorate and water: Iron(II) perchlorate: \(\text{Fe(ClO}_4\text{)}_2\) Water: \(\text{H}_2\text{O}\) Step 3: Balance the equation \[\text{FeO} + 2\text{HClO}_4 \rightarrow \text{Fe(ClO}_4\text{)}_2 + \text{H}_2\text{O}\] The equation is balanced as there are equal numbers of each atom on both sides of the equation.

Step 3: c) Sulfur trioxide with water

Step 1: Write the reactants Sulfur trioxide: \(\text{SO}_3\) Water: \(\text{H}_2\text{O}\) Step 2: Write the products Sulfur trioxide will react with water to form sulfuric acid: Sulfuric acid: \(\text{H}_2\text{SO}_4\) Step 3: Balance the equation \[\text{SO}_3 + \text{H}_2\text{O} \rightarrow \text{H}_2\text{SO}_4\] The equation is balanced as there are equal numbers of each atom on both sides of the equation.

Step 4: d) Carbon dioxide with aqueous sodium hydroxide

Step 1: Write the reactants Carbon dioxide: \(\text{CO}_2\) Aqueous sodium hydroxide: \(\text{NaOH}\) Step 2: Write the products Carbon dioxide reacts with sodium hydroxide to form sodium bicarbonate: Sodium bicarbonate: \(\text{NaHCO}_3\) Step 3: Balance the equation \[\text{CO}_2 + \text{NaOH} \rightarrow \text{NaHCO}_3\] The equation is balanced as there are equal numbers of each atom on both sides of the equation.

Key Concepts

Chemical Reaction

Understanding chemical reactions is fundamental to mastering chemistry. A chemical reaction involves the transformation of one or more substances into new substances. The substances you start with are called reactants, and the new substances formed as a result of the reaction are products.

In a reaction, atoms are rearranged through the breaking and forming of bonds. The overarching principle is the conservation of mass, which is reflected in the balancing of chemical equations. Each chemical reaction follows the law of conservation of mass, which states that matter cannot be created or destroyed. This concept is crucial when balancing equations, like those of barium oxide with water or carbon dioxide with sodium hydroxide. To convey the balancing of a chemical equation, you list the reactants and products and use coefficients to ensure the same number of atoms of each element is present on both sides.

Acid-Base Reaction

An acid-base reaction is a specific type of chemical reaction that involves the transfer of protons (H+) between a base and an acid. There are several definitions of acids and bases, but the most common one in use today is the Brønsted-Lowry theory, which defines an acid as a proton donor and a base as a proton acceptor.

Typically, when an acid reacts with a base, the outcome is the formation of water and a salt. This is precisely what we see in the reaction between iron(II) oxide, a base, and perchloric acid. The balancing of this reaction requires an understanding of the chemical formulas involved and the stoichiometry, which helps to ensure the equal number of atoms for each element on both sides of the equation. The reaction between carbon dioxide and sodium hydroxide can also be classified as an acid-base reaction, where carbon dioxide acts as an acid and sodium hydroxide as a base, resulting in the formation of sodium bicarbonate.

Stoichiometry

The term stoichiometry comes from the Greek words 'stoicheion' (element) and 'metron' (measure), and it is the branch of chemistry that deals with quantitatively measuring the amounts of reactants and products involved in a reaction. Calculating stoichiometric quantities requires a balanced chemical equation, which reveals the ratio of moles of reactants to moles of products.

Stoichiometry is pivotal for predicting product yield and ensuring that reactions occur in the desired proportions. For instance, in the example of sulfur trioxide reacting with water, stoichiometry tells us that one mole of sulfur trioxide will react with one mole of water to produce one mole of sulfuric acid. Understanding stoichiometry is not just about balancing equations but also about grasping the relationships between the reactants and products in terms of their amounts, and this understanding is essential for all types of chemical reactions, be they synthesis, decomposition, combustion, or acid-base.