Problem 67
Question
When \(\sin (x)\) and \(\cos (x)\) are both raised to the same positive power in an integrand, the identity \(\sin (2 x)=2 \sin (x) \cos (x)\) may be used to simplify the integral. Use this observation as the basis for calculation of the integrals. $$ \int \cos ^{2}(x) \sin ^{2}(x) d x $$
Step-by-Step Solution
Verified Answer
The integral is \( \frac{x}{8} - \frac{1}{32} \sin(4x) + C \).
1Step 1: Identify Trigonometric Identity Usage
We notice that both \( \sin(x) \) and \( \cos(x) \) are raised to the second power in the integral. To simplify, we can use the double angle identity for sine: \[ \sin(2x) = 2 \sin(x) \cos(x). \] This identity suggests a potential change to our integral.
2Step 2: Rewriting Using the Identity
Starting from \( \sin(2x) = 2 \sin(x) \cos(x) \), we find \( \sin(x) \cos(x) = \frac{1}{2} \sin(2x) \). Rewrite the integral as follows: \( \cos^2(x) \sin^2(x) = \left( \frac{1}{2} \sin(2x) \right)^2 \).
3Step 3: Simplify the Expression
We simplify \( \left( \frac{1}{2} \sin(2x) \right)^2 \) to \( \frac{1}{4} \sin^2(2x) \). So our integral becomes \( \int \frac{1}{4} \sin^2(2x) \, dx \). Taking out the constant factor, we have \( \frac{1}{4} \int \sin^2(2x) \, dx \).
4Step 4: Use the Reduction Formula for \( \sin^2(2x) \)
We use the trigonometric identity \( \sin^2(A) = \frac{1 - \cos(2A)}{2} \) to reduce the integral. Substitute \( 2x \) for \( A \), \( \sin^2(2x) = \frac{1 - \cos(4x)}{2} \). Thus, the integral becomes \( \frac{1}{4} \int \frac{1 - \cos(4x)}{2} \, dx \).
5Step 5: Simplify the Integral
This can be further simplified to \( \frac{1}{8} \int (1 - \cos(4x)) \, dx \), and split into two integrals: \( \frac{1}{8} \left( \int 1 \, dx - \int \cos(4x) \, dx \right) \).
6Step 6: Compute Each Integral
Compute the integral of each part: \( \int 1 \, dx = x \), and \( \int \cos(4x) \, dx = \frac{1}{4} \sin(4x) \). Thus, the expression becomes \( \frac{1}{8} \left( x - \frac{1}{4} \sin(4x) \right) \).
7Step 7: Final Simplification
Combine the terms to get \( \frac{x}{8} - \frac{1}{32} \sin(4x) + C \), where \( C \) is the constant of integration. This is the most simplified form of the integral.
Key Concepts
Trigonometric IdentitiesDouble Angle FormulasReduction FormulasCalculus
Trigonometric Identities
Trigonometric identities are powerful tools in calculus, helping to simplify complex expressions involving trigonometric functions. An identity like \( \sin(2x) = 2 \sin(x) \cos(x) \) shows the relationship between the sine of a double angle and the product of sine and cosine of a single angle. These identities make it possible to transform expressions so they are easier to integrate or differentiate.
- Some common trigonometric identities include Pythagorean identities, addition and subtraction formulas, and double angle formulas.
- In our case, the identity \( \sin(2x) = 2 \sin(x) \cos(x) \) is used to substitute and transform \( \sin^2(x) \cos^2(x) \) into a format conducive to further calculations.
Double Angle Formulas
Double angle formulas are a special subset of trigonometric identities. They provide a connection between the functions of an angle and its double, and are very useful in calculating integrals and derivatives. The formula \( \sin(2x) = 2 \sin(x) \cos(x) \) is crucial when dealing with integrals involving products of powers of sine and cosine.
- These formulas simplify expressions by reducing the number of different trigonometric terms involved.
- Using a double angle formula allows converting a product of trigonometric functions into a single trigonometric function with a double angle, as seen in our integral \( \int \cos^2(x) \sin^2(x) \,dx \).
Reduction Formulas
Reduction formulas are techniques that transform integrals into simpler forms, often exploiting trigonometric identities and algebraic manipulations. They are used to simplify powers of trigonometric functions, as shown in the integral \( \int \sin^2(2x) \, dx \).
- By using the identity \( \sin^2(A) = \frac{1 - \cos(2A)}{2} \), we express the integral in terms of a simpler expression using cosine.
- This helps in breaking down a complex integral into more manageable pieces for evaluation, such as turning an integral of \( \sin^2(2x) \) into separate integrals involving constant terms and cosine functions.
Calculus
Calculus is fundamentally about the study of change and motion, and integration is a key component of this analysis. In this integration problem, calculus involves transforming the integrand using relevant identities and solving the resulting expressions. The whole process involves breaking down a challenging integral into simpler parts which can be easily evaluated.
- Integration, particularly of trigonometric functions, often requires recognizing patterns and applying identities like those of double angles or reductions.
- By understanding the calculus involved in integrating \( \int \cos^2(x) \sin^2(x) \, dx \), students can appreciate how transformations and identity applications make complex calculus problems manageable.
Other exercises in this chapter
Problem 67
In each of Exercises \(58-69\) use the Comparison Theorem to determine whether the given improper integral is convergent or divergent. In some cases, you may ha
View solution Problem 67
Use the Comparison Theorem to establish that the given improper integral is convergent. $$ \int_{1}^{\infty} \frac{e^{-x}}{\sqrt{x}} d x $$
View solution Problem 67
Mr. Woodman set up a partial fraction decomposition $$ \frac{5 x^{2}-4 x+2}{x^{2}(x-1)^{2}}=\frac{A}{x^{2}}+\frac{B}{(x-1)^{2}} $$ and correctly solved \(A=2, B
View solution Problem 67
Integrate by parts. This will result in an integrand of the form \(P(x) / Q(x)\) where \(P(x)\) and \(Q(x)\) are polynomials with the degree of \(P(x)\) greater
View solution