Problem 67
Question
The rectangular coordinates of a point are given. Find polar coordinates for each point. $$ (1.3,-2.1) $$
Step-by-Step Solution
Verified Answer
The polar coordinates are approximately (2.47, 5.26).
1Step 1: Find the radius r
The radius (r) can be found using the Pythagorean theorem: \[ r = \sqrt{x^2 + y^2} \] Plug in the given coordinates (1.3, -2.1): \[ r = \sqrt{1.3^2 + (-2.1)^2} = \sqrt{1.69 + 4.41} = \sqrt{6.1} \approx 2.47 \]
2Step 2: Calculate the angle θ
Find the angle θ using the arctangent function: \[ \theta = \arctan \left( \frac{y}{x} \right) \] Since the point (1.3, -2.1) is in the fourth quadrant, we need to adjust θ by adding 2π if θ is negative: \[ \theta = \arctan \left( \frac{-2.1}{1.3} \right) \approx -1.02 \text{ radians} \] Adjusting for the fourth quadrant: \[ \theta = 2\pi - 1.02 \approx 5.26 \text{ radians} \]
Key Concepts
rectangular coordinatesradius calculationangle determinationquadrant adjustments
rectangular coordinates
Rectangular coordinates, also known as Cartesian coordinates, describe a point in a plane by specifying its distance from two perpendicular lines called axes. For any point, you need two values: the x-coordinate and the y-coordinate.
- The x-coordinate tells you how far the point is along the horizontal axis.
- The y-coordinate tells you how far the point is along the vertical axis.
radius calculation
The radius in polar coordinates is the distance from the point to the origin. You can find this distance using the Pythagorean theorem.
The formula for the radius is:
\( x^2 \) and \( y^2 \)
The formula for the radius is:
- Square each coordinate value:
\( x^2 \) and \( y^2 \)
- Add the squares together: \( x^2 + y^2 \)
- Take the square root of the sum: \( \sqrt{x^2 + y^2} \)
angle determination
Determining the angle \(\theta\) involves finding the direction of the point relative to the positive x-axis. You calculate this using the arctangent function:
\( \theta = \arctan\left( \frac{y}{x} \right) \)
For our example point (1.3, -2.1), you find the angle as follows:
\( \theta = \arctan\left( \frac{y}{x} \right) \)
For our example point (1.3, -2.1), you find the angle as follows:
- Divide the y-coordinate by the x-coordinate: \( \frac{-2.1}{1.3} \approx -1.615 \)
- Take the arctangent of this value: \( \theta \approx -1.02 \text{ radians} \)
quadrant adjustments
The angle calculation often requires adjustment depending on which quadrant the point is in. The Cartesian plane is divided into four quadrants:
In our example, the point (1.3, -2.1) is in the fourth quadrant, where the angle from the positive x-axis is negative. To adjust the angle for correct polar coordinates:
\[ \theta = 2\pi - |\text{calculated angle}| \] \ Using the initial result: \[ \theta \approx 2\pi - 1.02 \approx 5.26 \text{ radians} \]
This adjustment ensures the angle represents the correct direction for a point in the fourth quadrant.
- First Quadrant: Both x and y are positive.
- Second Quadrant: x is negative, y is positive.
- Third Quadrant: Both x and y are negative.
- Fourth Quadrant: x is positive, y is negative.
In our example, the point (1.3, -2.1) is in the fourth quadrant, where the angle from the positive x-axis is negative. To adjust the angle for correct polar coordinates:
\[ \theta = 2\pi - |\text{calculated angle}| \] \ Using the initial result: \[ \theta \approx 2\pi - 1.02 \approx 5.26 \text{ radians} \]
This adjustment ensures the angle represents the correct direction for a point in the fourth quadrant.
Other exercises in this chapter
Problem 66
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