Problem 67
Question
The driver of three-wheeler moving with a speed of \(36 \mathrm{~km} / \mathrm{h}\) sees a child standing in the middle of the road and brings his vehicle to rest in \(4.0 \mathrm{~s}\) just in time to save the child. What is the average retarding force on the vehicle? The mass of the three-wheeler is \(400 \mathrm{~kg}\) and the mass of the driver is \(65 \mathrm{~kg}\). (A) \(1162.5 \mathrm{~N}\) (B) \(116.25 \mathrm{~N}\) (C) \(1112 \mathrm{~N}\) (D) None of these
Step-by-Step Solution
Verified Answer
The short answer to the problem is:
(A) \(1162.5 \mathrm{~N}\)
1Step 1: Calculate the total mass of the system
First, we need to find the total mass of the system. Since we have the mass of the vehicle (m₁) and the mass of the driver (m₂), we can find the total mass (M) by adding the two masses.
Total mass M = m₁ + m₂
2Step 2: Convert the initial speed to m/s
The given speed is in km/h, and we need to convert it to meters per second (m/s) so that we can easily deal with units in our calculations.
To convert from km/h to m/s, we need to multiply the given speed by (1000 m / 1 km) and divide by (3600 s / 1 h).
\(v_0 = 36 \frac{km}{h} \cdot \frac{1000\,m}{1\,km} \cdot \frac{1\,h}{3600\,s}\)
3Step 3: Find the final velocity
Since the vehicle comes to rest, the final velocity (v) of the vehicle will be 0 m/s.
v = 0 m/s
4Step 4: Calculate the average acceleration
Now, we will calculate the average acceleration (a) of the vehicle using the formula:
\(a = \frac{v - v_0}{t}\)
We have the values v, v₀, and t, so we can find the acceleration.
5Step 5: Calculate the average retarding force
Finally, we will find the average retarding force (F) using the formula:
F = M * a
We have the value of M and a, so we can calculate the value of F.
Once we solve the above steps, we will get the answer to the problem, which we can then match with the given options (A, B, C, or D).
Other exercises in this chapter
Problem 65
A constant force acting on a body of mass \(3.0 \mathrm{~kg}\) changes its speed from \(2.0 \mathrm{~ms}^{-1}\) to \(3.5 \mathrm{~ms}^{-1}\) in \(25 \mathrm{~s}
View solution Problem 66
A body of mass \(5 \mathrm{~kg}\) is acted upon by two perpendicular forces \(8 \mathrm{~N}\) and \(6 \mathrm{~N}\). Give the magnitude of the acceleration of t
View solution Problem 68
A man of mass \(70 \mathrm{~kg}\) stands on a weighing scale in lift which is moving. Choose the correct statement. (A) Reading of weighing scale is \(700 \math
View solution Problem 69
A ball is travelling with uniform translatory motion. This means that (A) it is at rest. (B) the path can be a straight line or circular and the ball travels wi
View solution