Problem 67
Question
State the distributive laws using the sets \(A\) and \(B_{i}, i \in I\)
Step-by-Step Solution
Verified Answer
The two distributive laws for sets A and sets $B_i, i \in I$ are:
1. \(A \cap (\bigcup_{i \in I} B_i) = \bigcup_{i \in I} (A \cap B_i) \) - Intersection over Union
2. \(A \cup (\bigcap_{i \in I} B_i) = \bigcap_{i \in I} (A \cup B_i) \) - Union over Intersection
1Step 1: Distributive Law 1: Intersection over Union
To state the distributive law for the intersection over the union of sets, we write the formula as follows:
\[A \cap (\bigcup_{i \in I} B_i) = \bigcup_{i \in I} (A \cap B_i) \]
This law states that the intersection of set A with a union of multiple sets Bi is equivalent to the union of the intersections of set A with each individual set Bi.
2Step 2: Distributive Law 2: Union over Intersection
To state the distributive law for the union over the intersection of sets, we write the formula as follows:
\[A \cup (\bigcap_{i \in I} B_i) = \bigcap_{i \in I} (A \cup B_i) \]
This law states that the union of set A with an intersection of multiple sets Bi is equivalent to the intersection of the unions of set A with each individual set Bi.
Key Concepts
Distributive LawsIntersection of SetsUnion of Sets
Distributive Laws
In set theory, distributive laws help us understand how operations of intersection and union interact with each other. These laws function much like distributive laws in arithmetic, where multiplication distributes over addition. In the context of sets:
- The first law, known as "Intersection over Union," is explained by the equation: \[ A \cap (\bigcup_{i \in I} B_i) = \bigcup_{i \in I} (A \cap B_i) \]. This means if you have a set \(A\) and you are intersecting it with a large union of many sets \(B_i\), it is the same as taking \(A\) and intersecting it individually with each \(B_i\), and then uniting all those results.
- The second law, "Union over Intersection," is expressed as: \[ A \cup (\bigcap_{i \in I} B_i) = \bigcap_{i \in I} (A \cup B_i) \]. Here, if set \(A\) is united with an intersection of several sets \(B_i\), we find it equivalent to uniting \(A\) with each \(B_i\) first, then obtaining the intersection of all these unions.
Intersection of Sets
The concept of intersection in set theory represents the common elements shared among sets. When you "intersect" sets, you are finding all items that the sets share.
For example, if you have Set A containing elements {1, 2, 3} and Set B containing {2, 3, 4}, their intersection, written as \(A \cap B\), would result in a new set {2, 3}, because those are the elements both sets have in common.
For example, if you have Set A containing elements {1, 2, 3} and Set B containing {2, 3, 4}, their intersection, written as \(A \cap B\), would result in a new set {2, 3}, because those are the elements both sets have in common.
- Intersection is denoted by the symbol \(\cap\).
- It is commutative, meaning \(A \cap B = B \cap A\).
- If there are no common elements, the intersection is an empty set, denoted by \(\emptyset\).
Union of Sets
In contrast to intersection, the union of sets involves combining all the elements from different sets into one set without repeating any elements. It effectively gathers together everything from the sets involved.
For instance, if Set A contains {1, 2, 3} and Set B contains {2, 3, 4}, their union, noted as \(A \cup B\), becomes {1, 2, 3, 4} as it includes all unique elements from both sets.
For instance, if Set A contains {1, 2, 3} and Set B contains {2, 3, 4}, their union, noted as \(A \cup B\), becomes {1, 2, 3, 4} as it includes all unique elements from both sets.
- Union is represented using the symbol \(\cup\).
- The operation is associative \((A \cup B) \cup C = A \cup (B \cup C)\).
- The union enjoys a commutative property, which tells us \(A \cup B = B \cup A\).
Other exercises in this chapter
Problem 65
Simplify each set expression. $$\left(A^{\prime} \cup B^{\prime}\right)^{\prime} \cup\left(A^{\prime} \cap B\right)$$
View solution Problem 66
State De Morgan's laws for sets \(A_{i}, i \in I .\) (I is an index set.)
View solution Problem 68
The sum of two fuzzy sets \(A\) and \(B\) is the fuzzy set \(A \oplus B,\) where \(d_{A \oplus B}(x)=\) 1\(\wedge\left|d_{A}(x)+d_{B}(x)\right|\) itheir differe
View solution Problem 70
The sum of two fuzzy sets \(A\) and \(B\) is the fuzzy set \(A \oplus B,\) where \(d_{A \oplus B}(x)=\) 1\(\wedge\left|d_{A}(x)+d_{B}(x)\right|\) itheir differe
View solution