Problem 67
Question
Solve the quadratic equation by finding square roots or by using the quadratic formula. Explain why you chose the method. $$h^{2}+18 h+81=0$$
Step-by-Step Solution
Verified Answer
The solution for given quadratic equation is \(h = -9\).
1Step 1: Calculation of the discriminant
First calculate the discriminant \(D\) using the formula \(D = b^2 - 4ac\). So, Substitute \(a = 1, b = 18, and c = 81\) into the formula yielding \(D = (18)^2 - 4*1*81\) which results in \(D = 0\)
2Step 2: Choosing the method
Since the discriminant \(D\) is equal to 0, which implies that the equation has equal roots. Thus, the method of finding square roots becomes a more appropriate approach in this context than using the quadratic formula.
3Step 3: Solving the equation via square roots
Given the equation \(h^{2}+18 h+81=0\) can be expressed as \((h+9)^2 = 0\). Taking square roots on both sides, \(h+9 = 0\) or \(h+9 = 0\). Solving both equations independently will reveal that \(h = -9\) for both, hence there is only one root, and it is \(h = -9\).
Key Concepts
Understanding the DiscriminantSquare Roots Method for Solving QuadraticsThe Quadratic Formula and Its Use
Understanding the Discriminant
The discriminant of a quadratic equation is a foundational concept that provides insight into the nature of its roots. The discriminant is represented by the symbol \(D\) and is calculated using the formula:
\[D = b^2 - 4ac\]
Here:
\[D = b^2 - 4ac\]
Here:
- \(a\) is the coefficient of \(x^2\)
- \(b\) is the coefficient of \(x\)
- \(c\) is the constant term
- If \(D > 0\), the equation has two distinct real roots.
- If \(D = 0\), there is exactly one real root, also referred to as a repeated or double root.
- If \(D < 0\), the equation has no real roots, but rather two complex roots.
Square Roots Method for Solving Quadratics
When the discriminant is zero, the quadratic equation simplifies to a perfect square trinomial. This makes the square roots method an efficient and straightforward approach to finding the roots. Let's break down this method.
Given the quadratic equation:
\[h^2 + 18h + 81 = 0\]
It can be expressed as:
\[(h + 9)^2 = 0\]
This step involves recognizing that the original quadratic is a square of a binomial. By this recognition, we can directly solve the equation by taking the square root of both sides. Here's how:
Given the quadratic equation:
\[h^2 + 18h + 81 = 0\]
It can be expressed as:
\[(h + 9)^2 = 0\]
This step involves recognizing that the original quadratic is a square of a binomial. By this recognition, we can directly solve the equation by taking the square root of both sides. Here's how:
- Taking the square root of both sides gives \(h + 9 = 0\).
- Solving for \(h\), we find \(h = -9\).
The Quadratic Formula and Its Use
The quadratic formula is a powerful tool for finding the roots of any quadratic equation, represented as:
\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]
This formula works universally for all quadratic equations and is especially helpful when factoring is difficult or impossible. It combines the coefficients \(a\), \(b\), and \(c\) directly into a calculation that reveals the roots.
Although versatile, using the quadratic formula to solve our example \(h^2 + 18h + 81 = 0\) is unnecessary given the discriminant is zero. For this exercise, because the equation developed into a perfect square, the square roots method provided a quicker solution.
However, more complex equations or those without perfect square trinomials benefit significantly from the quadratic formula. Remember, the formula always depends on calculating the discriminant, which determines the nature of the roots and guides us to the next steps or methods to employ.
\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]
This formula works universally for all quadratic equations and is especially helpful when factoring is difficult or impossible. It combines the coefficients \(a\), \(b\), and \(c\) directly into a calculation that reveals the roots.
Although versatile, using the quadratic formula to solve our example \(h^2 + 18h + 81 = 0\) is unnecessary given the discriminant is zero. For this exercise, because the equation developed into a perfect square, the square roots method provided a quicker solution.
However, more complex equations or those without perfect square trinomials benefit significantly from the quadratic formula. Remember, the formula always depends on calculating the discriminant, which determines the nature of the roots and guides us to the next steps or methods to employ.
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