Problem 67
Question
Solve each equation or inequality. Graph the solution set. $$ |10-12 x| \geq 4 $$
Step-by-Step Solution
Verified Answer
The solution set is \((-\infty, \frac{1}{2}] \cup [\frac{7}{6}, \infty)\).
1Step 1 - Understand the Absolute Value Inequality
The given inequality is \(|10 - 12x| \geq 4\). This means that the expression inside the absolute value can be either greater than or equal to 4 or less than or equal to -4.
2Step 2 - Split the Inequality
Break down the absolute value inequality into two separate inequalities:1. \(10 - 12x \geq 4\)2. \(10 - 12x \leq -4\)
3Step 3 - Solve the First Inequality
Solve \(10 - 12x \geq 4\):First, subtract 10 from both sides:\(10 - 12x - 10 \geq 4 - 10\)This simplifies to:\(-12x \geq -6\)Then, divide both sides by -12 and reverse the inequality sign:\(x \leq \frac{1}{2}\)
4Step 4 - Solve the Second Inequality
Solve \(10 - 12x \leq -4\):First, subtract 10 from both sides:\(10 - 12x - 10 \leq -4 - 10\)This simplifies to:\(-12x \leq -14\)Then, divide both sides by -12 and reverse the inequality sign:\(x \geq \frac{7}{6}\)
5Step 5 - Combine the Solutions
Combine the two solutions: \(x \leq \frac{1}{2}\) and \(x \geq \frac{7}{6}\). Since the solutions do not overlap, the solution set is the union of the two intervals: \((-\infty, \frac{1}{2}] \cup [\frac{7}{6}, \infty)\).
6Step 6 - Graph the Solution Set
Graph the solution set on a number line. Indicate the intervals \((-\infty, \frac{1}{2}]\) and \([\frac{7}{6}, \infty)\) with filled circles at \(x = \frac{1}{2}\) and \(x = \frac{7}{6}\). Shade the regions extending to negative infinity from \(\frac{1}{2}\) and to positive infinity from \(\frac{7}{6}\).
Key Concepts
solving inequalitiesgraphing solution setsalgebraic expressions
solving inequalities
Solving absolute value inequalities involves understanding that the absolute value of an expression can be interpreted in two ways. For the inequality \(|10 - 12x| \geq 4\), this means we need to consider two separate conditions.
An absolute value inequality \[ |A| \geq B \] can be split into:
An absolute value inequality \[ |A| \geq B \] can be split into:
- \( A \geq B \)
- \( A \leq -B \)
- \( 10 - 12x \geq 4 \)
- \( 10 - 12x \leq -4 \)
graphing solution sets
Once you solve the inequalities, graphing the solution set correctly is crucial. For the given problem, the combined solutions to the inequalities are \[ x \leq \frac{1}{2} \] and \[ x \geq \frac{7}{6} \].
To graph these, follow these steps:
To graph these, follow these steps:
- Draw a number line.
- Mark the points \(\frac{1}{2}\) and \(\frac{7}{6}\) on the number line.
- Use filled circles at \(\frac{1}{2}\) and \(\frac{7}{6}\) to indicate that these values are included.
- Shade the regions to the left of \(\frac{1}{2}\) and to the right of \(\frac{7}{6}\).
algebraic expressions
Understanding how to manipulate algebraic expressions is essential in solving absolute value inequalities. Start by isolating the absolute value term on one side of the inequality.
For \(|10 - 12x| \geq 4\), isolate \(10 - 12x\). This gives two separate inequalities to solve. First, handle \(10 - 12x \geq 4\):
For \(|10 - 12x| \geq 4\), isolate \(10 - 12x\). This gives two separate inequalities to solve. First, handle \(10 - 12x \geq 4\):
- Subtract 10 from both sides to get \(-12x \geq -6\).
- Divide by \(-12\), remembering to reverse the inequality sign: \(\frac{x}{-\frac{12}{12}} \leq \frac{-6}{-12}\), simplifying to \( x \leq \frac{1}{2}\).
- Subtract 10 from both sides to get \(-12x \leq -14\).
- Divide by \(-12\), reversing the inequality sign: \(\frac{x}{\frac{-12}{12}} \geq \frac{-14}{-12}\), simplifying to \( x \geq \frac{7}{6}\).
Other exercises in this chapter
Problem 66
Solve each equation, and check the solution. \(\frac{3 x+2}{7}-\frac{x+4}{5}=2\)
View solution Problem 67
Give, in interval notation, the unknown numbers in each description. Six times a number is between -12 and 12 .
View solution Problem 67
Solve each equation, and check the solution. \(\frac{4 x+1}{3}=\frac{x+5}{6}+\frac{x-3}{6}\)
View solution Problem 68
Solve each equation or inequality. Graph the solution set. $$ |8-10 x| \geq 2 $$
View solution