Problem 67
Question
Simplify. $$ \frac{1}{3}(15 a+9 b)-\frac{1}{7}(28 b-84 a) $$
Step-by-Step Solution
Verified Answer
The simplified expression is \( 17a - b \).
1Step 1: Distribute the First Term
Distribute the factor of \( \frac{1}{3} \) to each term inside the parentheses. Apply the distributive property: \( \frac{1}{3}(15a) + \frac{1}{3}(9b) \). This simplifies to \( 5a + 3b \).
2Step 2: Distribute the Second Term
Distribute the factor of \( \frac{1}{7} \) to each term inside the parentheses, remembering the minus sign: \( -\frac{1}{7}(28b) + \frac{1}{7}(84a) \). This simplifies to \( -4b + 12a \).
3Step 3: Combine Like Terms
Now, combine the results from Steps 1 and 2. Our expression is now: \( 5a + 3b + 12a - 4b \).
4Step 4: Simplify the Expression
Combine like terms to simplify the expression: \( 5a + 12a = 17a \) and \( 3b - 4b = -b \). The simplified expression is \( 17a - b \).
Key Concepts
Distributive PropertyCombining Like TermsAlgebraic Expressions
Distributive Property
The distributive property is a fundamental concept in algebra that allows you to break down and simplify expressions. It is used to multiply a single term by terms inside a set of parentheses. This property states that for any numbers or variables,
In the original exercise, the distributive property was used twice. First, with the factor \( \frac{1}{3} \) applied to \( 15a + 9b \), resulting in \( 5a + 3b \). Then, the factor \( -\frac{1}{7} \) was applied to \( 28b - 84a \), resulting in \( -4b + 12a \). By distributing and simplifying early, you can make the entire process of solving algebraic problems much easier.
- \( a(b + c) = ab + ac \)
In the original exercise, the distributive property was used twice. First, with the factor \( \frac{1}{3} \) applied to \( 15a + 9b \), resulting in \( 5a + 3b \). Then, the factor \( -\frac{1}{7} \) was applied to \( 28b - 84a \), resulting in \( -4b + 12a \). By distributing and simplifying early, you can make the entire process of solving algebraic problems much easier.
Combining Like Terms
Combining like terms is another essential step in simplifying algebraic expressions. Like terms are terms that have the same variables raised to the same power. Only the coefficients of these terms are different, and these are the only parts of the terms that you add or subtract.
In the original problem, the like terms were \( 5a + 12a \) and \( 3b - 4b \). By combining the \( a \) terms, we get \( 17a \), and by combining the \( b \) terms, we get \( -b \). Properly combining like terms is crucial for reducing expressions to their simplest form.
- Examples of like terms: \( 2x \) and \( -5x \)
- Non-like terms: \( 3x \) and \( 3y \)
In the original problem, the like terms were \( 5a + 12a \) and \( 3b - 4b \). By combining the \( a \) terms, we get \( 17a \), and by combining the \( b \) terms, we get \( -b \). Properly combining like terms is crucial for reducing expressions to their simplest form.
Algebraic Expressions
An algebraic expression is a mathematical phrase that can include numbers, variables, and arithmetic operations. Unlike an equation, an algebraic expression does not have an equality sign. It merely represents a value and is used extensively in various mathematical calculations and problem-solving.
In the exercise given, the expression \( \frac{1}{3}(15a+9b)-\frac{1}{7}(28b-84a) \) is an algebraic expression. Simplifying such expressions allows you to find equivalent forms that are easier to interpret. Mastering the principles of working with algebraic expressions is foundational in algebra, enabling more advanced mathematical reasoning and problem-solving.
- Example: \( 3x + 4 \)
- Components: Variables like \( x \), coefficients like \( 3 \), and constants like \( 4 \).
In the exercise given, the expression \( \frac{1}{3}(15a+9b)-\frac{1}{7}(28b-84a) \) is an algebraic expression. Simplifying such expressions allows you to find equivalent forms that are easier to interpret. Mastering the principles of working with algebraic expressions is foundational in algebra, enabling more advanced mathematical reasoning and problem-solving.
Other exercises in this chapter
Problem 66
Find the reciprocal of each number. \(-4\)
View solution Problem 67
Solve each equation. Check your solution. $$ x+3=2 $$
View solution Problem 67
Find the reciprocal of each number. \(\frac{1}{2}\)
View solution Problem 68
Solve each equation. Check your solution. $$ -4+2 y=0 $$
View solution