Problem 67
Question
Simplify each rational expression. $$ \frac{x^{2}+4 x+3}{x^{2}-3 x-4} $$
Step-by-Step Solution
Verified Answer
The simplified form of the given rational expression is \( \frac{x+3}{x-4}\)
1Step 1: Factorize quadratic expressions
We need to factor the quadratic expressions in both numerator and denominator. Start with the numerator \(x^{2} + 4x + 3\). Look for two numbers that multiply to form 3 and add to form 4. We find 1 and 3 satisfy the condition, so we can factor the numerator as \( (x+1)(x+3)\). Follow the same procedure for the denominator \(x^{2} - 3x - 4\). Look for two numbers that multiply to form -4 and add to form -3. We find -4 and 1 satisfy these conditions. As a result, we can write the denominator as \( (x-4)(x+1)\) .
2Step 2: Simplify the rational expression
We can simplify the expression by canceling common factors from the numerator and denominator. Both \(x+1\) are common factors. Therefore the expression simplifies to \( \frac{x+3}{x-4}\) .
Key Concepts
Factoring QuadraticsRational ExpressionCanceling Common Factors
Factoring Quadratics
Factoring quadratics is a crucial skill in algebra. It's all about transforming a quadratic expression into a product of two binomials. Think of it as finding two numbers that fit together to replace a polynomial. To factor a quadratic expression like \(x^2 + 4x + 3\), follow these steps:
For the denominator \(x^2 - 3x - 4\), apply the same strategy:
- Identify the numbers you need to find. Look for two numbers that multiply to give the constant term (3 in this case) and add up to the coefficient of the middle term (4).
- In this example, 1 and 3 fit the bill since \(1 \times 3 = 3\) and \(1 + 3 = 4\).
- Write the expression as \((x + 1)(x + 3)\).
For the denominator \(x^2 - 3x - 4\), apply the same strategy:
- You're looking for numbers that multiply to -4 and add up to -3.
- -4 and 1 work here, as \(-4 \times 1 = -4\) and \(-4 + 1 = -3\).
- Thus, the expression becomes \((x - 4)(x + 1)\).
Rational Expression
A rational expression is similar to a fraction, but with polynomials in both the numerator and the denominator. It's crucial to understand because it's common in algebra to work with these forms. Rational expressions can seem challenging, but breaking them down step-by-step makes them manageable.
- First, view the expression as a division problem between polynomials. For example, the expression given is \( \frac{x^2 + 4x + 3}{x^2 - 3x - 4} \).
- After factoring the quadratics, the expression becomes \( \frac{(x+1)(x+3)}{(x-4)(x+1)} \).
Canceling Common Factors
Canceling common factors is the crucial step that simplifies rational expressions effectively. It's akin to reducing a fraction by removing common divisors. Once you've factored both the numerator and the denominator, as we've done with the expressions here, look for terms that appear in both.
- In our example, \((x+1)\) is a common factor in both the numerator and the denominator.
- Cancel the common factor out to simplify the expression. After canceling \((x+1)\), the rational expression \( \frac{(x+1)(x+3)}{(x-4)(x+1)} \) becomes \( \frac{x+3}{x-4} \).
Other exercises in this chapter
Problem 66
The first term of a geometric sequence is 1 and its common ratio is \(6 .\) What is the sixth term? $$ \begin{array}{lllll}{\text { F. } 31} & {\text { G. } 317
View solution Problem 66
Find the missing terms of each arithmetic sequence. (Hint: The arithmetic mean of the first and fifth terms is the third term.)
View solution Problem 67
The first term of a geometric sequence is \(-1 .\) The common ratio is \(-5 .\) Find the eighth term in the sequence.
View solution Problem 68
Simplify each rational expression. $$ \frac{c^{2}-8 c+12}{c^{2}-11 c+30} $$
View solution