Problem 67
Question
If \(z \neq 1\) and \(\frac{z^{2}}{z-1}\) is real, then the point represented by the complex number \(z\) lies (A) either on the real axis or on a circle passing through the origin. (B) on a circle with centre at the origin. (C) either on the real axis or on a circle not passing through the origin. (D) on the imaginary axis.
Step-by-Step Solution
Verified Answer
A: Either on the real axis or on a circle passing through the origin.
1Step 1: Understand the Condition
The expression \(\frac{z^2}{z-1}\) is given as real, indicating that its imaginary part is zero. This implies that \(\text{Im}\left(\frac{z^2}{z-1}\right) = 0\). We must manipulate this condition further to understand where the complex number \(z\) lies in the complex plane.
2Step 2: Set up the Complex Number
Let \(z = x + yi\) where \(x\) and \(y\) are real numbers. Then \(z^2 = (x + yi)^2 = x^2 - y^2 + 2xyi\) and \(z - 1 = x - 1 + yi\). The fraction is \(\frac{z^2}{z-1} = \frac{x^2 - y^2 + 2xyi}{x - 1 + yi}\).
3Step 3: Simplify the Fraction
Multiply the numerator and denominator by the conjugate of the denominator to eliminate the imaginary part: \((x - 1 - yi)\). This leads to \(\frac{(x^2 - y^2 + 2xyi)(x - 1 - yi)}{(x-1)^2 + y^2}\).
4Step 4: Calculate the Imaginary Part
After expanding and simplifying the terms, the imaginary part of the complex number \((x^2 - y^2 + 2xyi)(x - 1 - yi)\) should equal zero. This condition provides a relationship between \(x\) and \(y\).
5Step 5: Analyze the Result
By setting the imaginary part to zero, analyze the expression and identify the set of \(z\) values satisfying this condition. The relation derived is \(y (x^2 + y^2 - x) = 0\).
6Step 6: Solve for Possible Values of z
From \(y (x^2 + y^2 - x) = 0\), either \(y = 0\) (implying \(z\) lies on the real axis) or \(x^2 + y^2 = x\) (which is the equation of a circle centered at \((0.5, 0)\) with radius \(0.5\)).
7Step 7: Final Condition Verification
This circle passes through the origin because when \(x = 0, y=0\), the equation \(x^2 + y^2 = x\) is satisfied. Thus, \(z\) lies either on the real axis or on a circle passing through the origin.
Key Concepts
Real Number ConditionsEquation of a CircleImaginary Part
Real Number Conditions
When we talk about real numbers in terms of complex numbers, we focus on expressions where the imaginary part equals zero. For example, an expression like \(\text{Im}\left(\frac{z^2}{z-1}\right) = 0\) tells us that the result has no imaginary component.
This provides critical information:
This provides critical information:
- If a fraction involving a complex number \(z\) is real, any imaginary terms must cancel each other out.
- The complex number \(z\) can be expressed as \(x + yi\), where \(x\) and \(y\) are real numbers, and \(i\) represents the square root of -1.
Equation of a Circle
The equation of a circle is a useful concept when dealing with complex numbers. Particularly, when the expression related to a complex number meets certain conditions, it translates into a geometric shape on the complex plane.
When you solve the equation \(x^2 + y^2 = x\), it represents a circle:
When you solve the equation \(x^2 + y^2 = x\), it represents a circle:
- With a center at \((0.5, 0)\)
- And a radius of 0.5
Imaginary Part
In complex number expressions, the imaginary part plays a key role in understanding the nature of the number. The imaginary part arises when a complex number is expressed as \(a + bi\), where \(b\) is the imaginary component.
For the expression \(\frac{z^2}{z-1}\) to be real, its imaginary part needs to be zero. Simplifying the complex expression requires multiplying the numerator and denominator by the conjugate to eliminate \(i\).
Evaluating the imaginary part of an expanded expression reveals which components must zero out for the entire expression to be purely real or imaginary. This kind of analysis:
For the expression \(\frac{z^2}{z-1}\) to be real, its imaginary part needs to be zero. Simplifying the complex expression requires multiplying the numerator and denominator by the conjugate to eliminate \(i\).
Evaluating the imaginary part of an expanded expression reveals which components must zero out for the entire expression to be purely real or imaginary. This kind of analysis:
- Helps determine the condition of the equation relative to real numbers.
- Offers insight into the potential locations of \(z\) in the complex plane, such as lying on an axis or circle.
Other exercises in this chapter
Problem 65
Let \(\alpha, \beta\) be real and \(z\) be a complex number. If \(z^{2}+\alpha z\) \(+\beta=0\) has two distinct roots on the line \(\operatorname{Re} z=1\), th
View solution Problem 66
If \(\omega(\neq 1)\) is a cube root of unity, and \((1+\omega)^{7}=A+B \omega\). Then \((A, B)\) equals (A) \((-1,1)\) (B) \((0,1)\) (C) \((1,1)\) (D) \((1,0)\
View solution Problem 68
Two circles in complex plane are \(C_{1}:|z-i|=2\) \(C_{2}:|z-1-2 i|=4\). Then (A) \(C_{1}\) and \(C_{2}\) touch each other. (B) \(C_{1}\) and \(C_{2}\) interse
View solution Problem 69
Two circles in complex plane are \(C_{1}:|z-i|=2\) \(C_{2}:|z-1-2 i|=4\). Then (A) \(C_{1}\) and \(C_{2}\) touch each other. (B) \(C_{1}\) and \(C_{2}\) interse
View solution