Problem 67
Question
How would you synthesize each of the following? a. 1,2-dibromopropane from propene b. acetone (2-propanone) from an alcohol c. tert-butyl alcohol ( 2 -methyl-2-propanol) from an alkene (See Exercise 62.) d. propanoic acid from an alcohol
Step-by-Step Solution
Verified Answer
a. Brominate propene using Br2 to form 1,2-dibromopropane.
\[ \text{Propene + Br}_2 \rightarrow \text{1,2-dibromopropane}\]
b. Oxidize propan-2-ol using K2Cr2O7 and H2SO4 to form acetone (2-propanone).
\[ \text{Propan-2-ol + K}_2\text{Cr}_2\text{O}_7 + \text{H}_2\text{SO}_4 \xrightarrow[]{\Delta} \text{2-propanone (acetone)}\]
c. Hydrate 2-methylpropene using H2O and H2SO4 to form tert-butyl alcohol (2-methyl-2-propanol).
\[ \text{2-Methylpropene} + \text{H}_2\text{O} + \text{H}_2\text{SO}_4 \rightarrow \text{tert-butyl alcohol (2-methyl-2-propanol)}\]
d. Oxidize propan-1-ol using K2Cr2O7 and H2SO4 to form propanoic acid.
\[ \text{Propan-1-ol} + 2 \, \text{K}_2\text{Cr}_2\text{O}_7 + 2 \, \text{H}_2\text{SO}_4 \xrightarrow[]{\Delta} \text{Propanoic acid}\]
1Step 1: Bromination of propene
Add one equivalent of bromine (Br2) to the propene molecule. The bromination of an alkene is an electrophilic addition reaction. Br2 will add across the double bond of propene, forming 1,2-dibromopropane as the product.
\[ \text{Propene + Br}_2 \rightarrow \text{1,2-dibromopropane}\]
b. Synthesis of acetone (2-propanone) from an alcohol
2Step 1: Identify the precursor alcohol
Determine the alcohol precursor from which we can synthesize acetone. It is propan-2-ol, given that oxidation of this secondary alcohol will result in a ketone.
3Step 2: Oxidation of propan-2-ol
Oxidize propan-2-ol using an appropriate oxidizing agent, such as potassium dichromate (K2Cr2O7) and concentrated sulfuric acid (H2SO4), and then heat the solution. This reaction will transform the secondary alcohol into 2-propanone (acetone).
\[ \text{Propan-2-ol + K}_2\text{Cr}_2\text{O}_7 + \text{H}_2\text{SO}_4 \xrightarrow[]{\Delta} \text{2-propanone (acetone)}\]
c. Synthesis of tert-butyl alcohol (2-methyl-2-propanol) from an alkene
4Step 1: Identify the precursor alkene
Determine the alkene precursor from which we can synthesize tert-butyl alcohol. It is 2-methylpropene, given that hydration of this alkene will result in a tertiary alcohol.
5Step 2: Hydration of 2-methylpropene
Hydrate 2-methylpropene using water (H2O) in the presence of an acid catalyst, such as concentrated sulfuric acid (H2SO4) or phosphoric acid (H3PO4). This reaction will result in the formation of tert-butyl alcohol (2-methyl-2-propanol).
\[ \text{2-Methylpropene} + \text{H}_2\text{O} + \text{H}_2\text{SO}_4 \rightarrow \text{tert-butyl alcohol (2-methyl-2-propanol)}\]
d. Synthesis of propanoic acid from an alcohol
6Step 1: Identify the precursor alcohol
Determine the alcohol precursor from which we can synthesize propanoic acid. It is propan-1-ol, given that oxidation of this primary alcohol will result in a carboxylic acid.
7Step 2: Oxidation of propan-1-ol
Oxidize propan-1-ol using an appropriate oxidizing agent, such as potassium dichromate (K2Cr2O7) and concentrated sulfuric acid (H2SO4), and then heat the solution to reflux. This reaction will transform the primary alcohol into propanal (an aldehyde) first, followed by further oxidation into propanoic acid.
\[ \text{Propan-1-ol} + 2 \, \text{K}_2\text{Cr}_2\text{O}_7 + 2 \, \text{H}_2\text{SO}_4 \xrightarrow[]{\Delta} \text{Propanoic acid}\]
Key Concepts
BrominationOxidation ReactionsHydration ReactionsAlkene Reactions
Bromination
Bromination is a fascinating process where bromine atoms are added to a molecule. This type of reaction is commonly seen in organic synthesis, especially with alkenes. Alkenes, which are hydrocarbons with double bonds, readily react with halogens like bromine. When you add bromine (
Br_2)
to an alkene like propene, an electrophilic addition reaction occurs. The double bond in the alkene opens up, allowing two bromine atoms to attach to the molecule, converting it to 1,2-dibromopropane.
- Bromination is useful for adding complex groups to simple molecules.
- It changes physical properties like reactivity and solubility.
Oxidation Reactions
Oxidation reactions are pivotal in transforming alcohols into different functional groups like ketones or carboxylic acids. These reactions involve increasing the oxidation number of the carbon atom, typically with an oxidative agent like potassium dichromate (
K_2Cr_2O_7)
in the presence of an acid like sulfuric acid (
H_2SO_4)
.
- For converting secondary alcohols to ketones, mild oxidation is used.
- For turning primary alcohols into carboxylic acids, strong oxidants are required.
Hydration Reactions
Hydration reactions involve the addition of water to a compound. Alkene hydration is a classic method for producing alcohols. Alkenes, when treated with water in an acidic environment, undergo an electrophilic addition to form alcohols. For instance, when 2-methylpropene is hydrated, it results in the formation of tert-butyl alcohol (also known as 2-methyl-2-propanol).
Hydration is very useful for:
- Producing alcohols sustainably.
- Modifying the functional groups of hydrocarbons.
Alkene Reactions
Alkenes are versatile molecules in organic chemistry, primarily because of their double bonds. These double bonds are sites of reactivity where various reactions, including halogenation, hydration, and oxidation, can take place. The reactivity of alkenes makes them a central focus in the making of significant chemical materials.
Key reactions include:
- Bromination: Adding bromine across double bonds, leading to dibromoalkanes.
- Hydration: Introducing water molecules to form alcohols.
- Oxidation: Transforming alkenes into alcohols or carboxylic acids, depending on the starting material.
Other exercises in this chapter
Problem 65
Using appropriate reactants, alcohols can be oxidized into aldehydes, ketones, and/or carboxylic acids. Primary alcohols can be oxidized into aldehydes, which c
View solution Problem 66
Oxidation of an aldehyde yields a carboxylic acid: Draw the structures for the products of the following oxidation reactions. a. propanal \(\stackrel{\text { [o
View solution Problem 68
What tests could you perform to distinguish between the following pairs of compounds? a. \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{3}, \qua
View solution Problem 69
How would you synthesize the following esters? a. \(n\) -octylacetate
View solution