Problem 67
Question
For exercises 67-82, factor by grouping. Do not combine like terms before factoring. $$ x^{2}+7 x+4 x+28 $$
Step-by-Step Solution
Verified Answer
(x + 7)(x + 4)
1Step 1 - Group the terms
Group the terms into two pairs: o x² + 7x o 4x + 28
2Step 2 - Factor out the greatest common factor from each pair
From the first group (x² + 7x), factor out x: x(x + 7) From the second group (4x + 28), factor out 4: 4(x + 7)
3Step 3 - Factor out the common binomial factor
Notice that (x + 7) is a common factor: x(x + 7) + 4(x + 7) Factor out (x + 7): (x + 7)(x + 4)
Key Concepts
greatest common factorpolynomial factorizationcommon binomial factor
greatest common factor
The greatest common factor (GCF) is a crucial concept in factoring by grouping. It refers to the largest number or mathematical expression that divides all the terms in a group.
When factoring a polynomial like \(x^2 + 7x + 4x + 28\), we look for the GCF in each pair of terms.
In our example, we group the polynomial into two pairs: \(x^2 + 7x\) and \(4x + 28\).
We then identify the GCF for each pair:
When factoring a polynomial like \(x^2 + 7x + 4x + 28\), we look for the GCF in each pair of terms.
In our example, we group the polynomial into two pairs: \(x^2 + 7x\) and \(4x + 28\).
We then identify the GCF for each pair:
- For \(x^2 + 7x\), the GCF is \(x\) because both terms have an \(x\) in common.
- For \(4x + 28\), the GCF is \(4\) because both terms are divisible by 4.
polynomial factorization
Polynomial factorization is the process of breaking down a polynomial into simpler 'factor' expressions that, when multiplied together, give back the original polynomial.
With the polynomial \(x^2 + 7x + 4x + 28\), we use grouping and factoring to simplify it.
First, we formed groups: \(x^2 + 7x\) and \(4x + 28\).
After factoring out the GCF from each group, we got:
This process makes solving equations or simplifying expressions much easier.
With the polynomial \(x^2 + 7x + 4x + 28\), we use grouping and factoring to simplify it.
First, we formed groups: \(x^2 + 7x\) and \(4x + 28\).
After factoring out the GCF from each group, we got:
- \(x(x + 7)\) from \(x^2 + 7x\)
- \(4(x + 7)\) from \(4x + 28\)
This process makes solving equations or simplifying expressions much easier.
common binomial factor
The common binomial factor is the binomial expression that appears in multiple terms and can be factored out to simplify an expression.
In our problem, after factoring the GCF from each pair, we get: \(x(x + 7) + 4(x + 7)\).
Here, \((x + 7)\) is a common factor in both expressions.
To factor out this common binomial factor, we treat \((x + 7)\) as we would a single variable or a number.
We can rewrite the expression as: \((x + 7)(x + 4)\).
Factoring out common binomial factors simplifies the polynomial, making it easier to work with and solve.
In our problem, after factoring the GCF from each pair, we get: \(x(x + 7) + 4(x + 7)\).
Here, \((x + 7)\) is a common factor in both expressions.
To factor out this common binomial factor, we treat \((x + 7)\) as we would a single variable or a number.
We can rewrite the expression as: \((x + 7)(x + 4)\).
Factoring out common binomial factors simplifies the polynomial, making it easier to work with and solve.
Other exercises in this chapter
Problem 67
Use any of the factoring methods to factor. Identify any prime polynomials. $$ 15 p x-9 r x+10 p y-6 r y $$
View solution Problem 67
Factor. Either factor out the greatest common factor, factor by grouping, use the guess and check method, or use the \(a c\) method. $$ 5 q^{2}+9 q+3 $$
View solution Problem 68
Factor completely. Identify any prime polynomials. $$ 7 a-7 b^{2} $$
View solution Problem 68
Use any of the factoring methods to factor. Identify any prime polynomials. $$ 14 v x-10 p x+21 v z-15 p z $$
View solution