Problem 67
Question
For each pair of functions, find \(f(g(x))\) and \(g(f(x))\) $$ f(x)=-x-7, g(x)=4 x $$
Step-by-Step Solution
Verified Answer
Therefore, the composition of functions \(f\) and \(g\) gives \(f(g(x)) = -4x - 7\) and \(g(f(x)) = -4x - 28.\)
1Step 1: Finding \(f(g(x))\)
To find \(f(g(x))\), substitute \(g(x)\) into \(f(x)\). This gives us the expression \(f(g(x)) =-(4x)-7= -4x-7.\)
2Step 2: Finding \(g(f(x))\)
Similarly, to find \(g(f(x))\), substitute \(f(x)\) into \(g(x)\). This gives us the expression \(g(f(x)) =4(-x-7)= -4x-28.\)
Key Concepts
Function CompositionInverse FunctionsDomain and RangeAlgebraic Expressions
Function Composition
Function composition is when one function is applied to the result of another function. It is like having two processes, and using the output of the first process as the input for the second. This is expressed as \((f \circ g)(x)\), which means "apply \(g\) first, then apply \(f\)".
In this exercise, we have two functions, \(f(x)=-x-7\) and \(g(x)=4x\). To find \(f(g(x))\):
In this exercise, we have two functions, \(f(x)=-x-7\) and \(g(x)=4x\). To find \(f(g(x))\):
- First, find the output of \(g(x)\), which is \(4x\).
- Then, substitute \(4x\) into \(f(x)\), replacing every \(x\) in \(f(x)\) with \(4x\).
- This gives us \(f(g(x)) = -(4x) - 7 = -4x - 7\).
Inverse Functions
Inverse functions "undo" each other. If you have a function \(f(x)\), its inverse \(f^{-1}(x)\) reverses the process. Think of it as working backwards from the output to the input.
Finding an inverse function involves switching the roles of \(x\) and \(y\). You solve the equation \(y = f(x)\) for \(x\). While function composition takes you one way, an inverse function takes you back.
For example, if \(f(x) = y\) and the inverse \(f^{-1}(y) = x\), then applying \(f\) and then \(f^{-1}\) will get you back to your original starting value. In the exercise case, knowing how to find an inverse helps understand why compositions can be simplified or "undone" in certain situations.
Finding an inverse function involves switching the roles of \(x\) and \(y\). You solve the equation \(y = f(x)\) for \(x\). While function composition takes you one way, an inverse function takes you back.
For example, if \(f(x) = y\) and the inverse \(f^{-1}(y) = x\), then applying \(f\) and then \(f^{-1}\) will get you back to your original starting value. In the exercise case, knowing how to find an inverse helps understand why compositions can be simplified or "undone" in certain situations.
Domain and Range
Understanding the domain and range of functions is essential for function composition. The domain of a function is the set of all possible inputs, while the range is the set of all possible outputs.
When composing functions, it is crucial to consider:
In our example, \(g(x) = 4x\) has a domain and range of all real numbers, which fits the domain requirements of \(f(x) = -x - 7\). Therefore, the function composition \(f(g(x))\) is valid with these given functions.
When composing functions, it is crucial to consider:
- The domain of the first function (\(g(x)\) in \(f(g(x))\)).
- Then, check if the range of \(g(x)\) falls within the domain of \(f(x)\).
In our example, \(g(x) = 4x\) has a domain and range of all real numbers, which fits the domain requirements of \(f(x) = -x - 7\). Therefore, the function composition \(f(g(x))\) is valid with these given functions.
Algebraic Expressions
Algebraic expressions are combinations of numbers, variables, and operations. Understanding how to manipulate these expressions is crucial for composing functions.
In this exercise, to find \(g(f(x))\), you compose \(g\) and \(f\):
In this exercise, to find \(g(f(x))\), you compose \(g\) and \(f\):
- Take the expression for \(f(x) = -x - 7\).
- Substitute it into \(g(x) = 4x\), so that each \(x\) in \(g(x)\) is replaced by \(-x - 7\).
- This results in the expression \(g(f(x)) = 4(-x - 7)\), which simplifies to \(-4x - 28\).
Other exercises in this chapter
Problem 67
Find the inverse of each function. Is the inverse a function? $$ f(x)=\sqrt[4]{x} $$
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Simplify each expression. \(6^{\frac{1}{2}} \cdot 12^{\frac{1}{2}}\)
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Critical Thinking When \(\sqrt{x^{a} y^{b}}\) is simplified, the result is \(\frac{1}{x^{c} y^{3 d}}\) , where \(c\) and \(d\) are positive integers. Express \(
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Simplify each expression. Rationalize all denominators. Assume that all variables are positive. $$ \sqrt[3]{2 x^{2}} \cdot \sqrt[3]{4 x} $$
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