Problem 67
Question
Find the perimeter of the triangle with vertices \(A(-1,2,1)\) \(B(1,-1,3),\) and \(C(3,4,5)\)
Step-by-Step Solution
Verified Answer
The perimeter of the triangle is \( \sqrt{17} + \sqrt{33} + 6 \).
1Step 1: Identify the formula for distance
To find the perimeter of the triangle, we need to calculate the sum of the lengths of its sides. The length of a side can be found using the distance formula. For two points \( (x_1, y_1, z_1) \) and \( (x_2, y_2, z_2) \) in the 3D space, the distance \( d \) between them is given by: \[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2 + (z_2 - z_1)^2} \] We'll apply this formula to each pair of points.
2Step 2: Calculate distance AB
Using the coordinates of points A and B, \( A(-1, 2, 1) \) and \( B(1, -1, 3) \), substitute into the distance formula:\[ AB = \sqrt{(1 - (-1))^2 + (-1 - 2)^2 + (3 - 1)^2} \]\[ AB = \sqrt{(2)^2 + (-3)^2 + (2)^2} \]\[ AB = \sqrt{4 + 9 + 4} \]\[ AB = \sqrt{17} \]
3Step 3: Calculate distance BC
Using the coordinates of points B and C, \( B(1, -1, 3) \) and \( C(3, 4, 5) \), substitute into the distance formula:\[ BC = \sqrt{(3 - 1)^2 + (4 - (-1))^2 + (5 - 3)^2} \]\[ BC = \sqrt{(2)^2 + (5)^2 + (2)^2} \]\[ BC = \sqrt{4 + 25 + 4} \]\[ BC = \sqrt{33} \]
4Step 4: Calculate distance CA
Using the coordinates of points C and A, \( C(3, 4, 5) \) and \( A(-1, 2, 1) \), substitute into the distance formula:\[ CA = \sqrt{(-1 - 3)^2 + (2 - 4)^2 + (1 - 5)^2} \]\[ CA = \sqrt{(-4)^2 + (-2)^2 + (-4)^2} \]\[ CA = \sqrt{16 + 4 + 16} \]\[ CA = \sqrt{36} \]\[ CA = 6 \]
5Step 5: Calculate the perimeter of the triangle
Now that we have the lengths of all sides, we can find the perimeter by summing these lengths:\[ \text{Perimeter} = AB + BC + CA \]\[ \text{Perimeter} = \sqrt{17} + \sqrt{33} + 6 \]
Key Concepts
Perimeter of a TriangleCoordinate Geometry3D Geometry
Perimeter of a Triangle
The perimeter is the total distance around a triangle, which in this case involves adding up the lengths of all its sides.
The notion of a perimeter applies to any polygon, but for a triangle, it simply means the sum of its three sides' lengths.
Calculating the perimeter of a triangle in a 3D space is similar to doing it in 2D, just requiring the 3D distance formula.
The notion of a perimeter applies to any polygon, but for a triangle, it simply means the sum of its three sides' lengths.
Calculating the perimeter of a triangle in a 3D space is similar to doing it in 2D, just requiring the 3D distance formula.
- First, identify the vertices of the triangle. Here, they are points A, B, and C with their respective coordinates.
- Next, calculate the distance between each pair of points: AB, BC, and CA, using the 3D distance formula.
- Finally, add these distances together to get the perimeter.
Coordinate Geometry
Coordinate geometry, often called Cartesian geometry, is a way to define the location of points in a plane using pairs of numbers. These numbers, known as coordinates, provide a precise way to describe the exact position of any point.
In 3D or three-dimensional geometry, each point is defined by three coordinates, typically noted as
For our exercise, coordinates help us organize and calculate distances between each pair of vertices of the triangle.
Understanding coordinate geometry is crucial as it provides the foundation needed for calculating the distance formula.
In 3D or three-dimensional geometry, each point is defined by three coordinates, typically noted as
- \((x, y, z)\) - where each coordinate represents a measurement in one of the three dimensions.
For our exercise, coordinates help us organize and calculate distances between each pair of vertices of the triangle.
Understanding coordinate geometry is crucial as it provides the foundation needed for calculating the distance formula.
3D Geometry
3D Geometry extends the concepts of 2D plane geometry into three dimensions, adding depth to the familiar length and width.
This field of geometry is crucial for understanding the real world, where objects aren't confined to a flat surface. In three dimensions, you can imagine moving up, down, left, right, forward, and backward.
Since our triangle's vertices are points like in geometry, understanding these principles allows us to apply the necessary calculations to solve for the perimeter of the triangle in 3D space.
This field of geometry is crucial for understanding the real world, where objects aren't confined to a flat surface. In three dimensions, you can imagine moving up, down, left, right, forward, and backward.
- The 3D distance formula helps calculate the direct distance between two points in space, which includes the x, y, and z coordinates.
- To calculate it, you use \(d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2 + (z_2 - z_1)^2}\), where \(d\) is the distance between two points.
Since our triangle's vertices are points like in geometry, understanding these principles allows us to apply the necessary calculations to solve for the perimeter of the triangle in 3D space.
Other exercises in this chapter
Problem 66
Find a formula for the distance from the point \(P(x, y, z)\) to the a. \(x y\) -plane. b. \(y z\) -plane. c. \(x z\) -plane.
View solution Problem 67
Use Equations ( 3 ) to generate a parametrization of the line through \(P(2,-4,7)\) parallel to \(\mathbf{v}_{1}=2 \mathbf{i}-\mathbf{j}+3 \mathbf{k} .\) Then g
View solution Problem 68
Use the component form to generate an equation for the plane through \(P_{1}(4,1,5)\) normal to \(\mathbf{n}_{1}=\mathbf{i}-2 \mathbf{j}+\mathbf{k} .\) Then gen
View solution Problem 68
Show that the point \(P(3,1,2)\) is equidistant from the points \(A(2,-1,3)\) and \(B(4,3,1)\)
View solution