Problem 67
Question
. Find a curve given by a polynominal \(P_{5}(x)\) that provides a smooth
transition between two horizontal lines. That is, assume a function of the
form \(P_{5}(x)=a_{0}+a_{1} x+a_{2} x^{2}+\) \(a_{3} x^{3}+a_{4} x^{4}+a_{5}
x^{5}\), which provides a smooth transition between \(y=0\) for \(x \leq 0\) and
\(y=1\) for \(x \geq 1\) in such a way that the function, its derivative, and
curvature are all continuous for all values of \(x\).
$$
y=\left\\{\begin{array}{ll}
0 & \text { if } \quad x \leq 0 \\
P_{5}(x) & \text { if } \quad 0
Step-by-Step Solution
Verified Answer
Solve the system using boundary and continuity conditions to get coefficients.
1Step 1: Establish continuity at endpoints
To ensure continuity at the endpoints, set the polynomial equal to the endpoint values. Thus, solve for the unknowns with these conditions: \(P_{5}(0) = 0\) and \(P_{5}(1) = 1\).
2Step 2: Define the function and its derivative
We define the polynomial and its first derivative to create continuity. Start with the polynomial: \[P_{5}(x) = a_0 + a_1 x + a_2 x^2 + a_3 x^3 + a_4 x^4 + a_5 x^5\]Differentiate to find:\[P_{5}'(x) = a_1 + 2a_2 x + 3a_3 x^2 + 4a_4 x^3 + 5a_5 x^4\]
3Step 3: Establish derivative continuity at endpoints
Ensure the first derivative \(P_{5}'(x)\) is zero at the endpoints (\(x=0\) and \(x=1\)):For \(x = 0\), set \(P_{5}'(0) = 0\).For \(x = 1\), set \(P_{5}'(1) = 0\).
4Step 4: Define and establish curvature continuity
The second derivative expresses curvature. Compute it as:\[P_{5}''(x) = 2a_2 + 6a_3 x + 12a_4 x^2 + 20a_5 x^3\]Ensure continuity by setting \(P_{5}''(0) = 0\) and \(P_{5}''(1) = 0\).
5Step 5: Solve the system of equations
Formulate and solve the system of equations derived from the conditions in previous steps. This will yield the values of \(a_0, a_1, a_2, a_3, a_4,\) and \(a_5\).
6Step 6: Verify solution
Check that the solution satisfies all initial conditions for continuity of the function, first derivative, and curvature across the interval \(x = 0\) and \(x = 1\).
Key Concepts
Smooth transition with polynomialsDerivative continuityCurvature continuity
Smooth transition with polynomials
Creating a smooth transition between two horizontal lines involves crafting a polynomial function that seamlessly connects the lines at specific points. In this case, we're looking for smooth transitions at the endpoints where the polynomials meet these lines. This concept involves ensuring that the polynomial function does not have any sudden jumps or kinks, making the change appear steady and gradual.
- Start with defining the polynomial, ensuring it meets the boundary conditions.
- Check endpoint values, ensuring that the polynomial's value at these points aligns with the horizontal lines.
- Avoid sharp edges or discontinuities in the graph.
Derivative continuity
Derivative continuity ensures that the change rate of our main function is consistent at the endpoints. In mathematical terms, this means that the first derivative of the polynomial must match at these key points. When computing the first derivative, it is vital that at point zero and point one, the derivatives also equate to zero. Simple checks involve:
- Taking the first derivative of the polynomial, denoting how fast the function's value changes.
- Setting the derived function equal to zero at the boundary points.
- Solving these equations to maintain derivative continuity.
Curvature continuity
Curvature continuity takes our tasks a step further, demanding that not only the function and its first derivative are smooth, but so is the second derivative. The second derivative gives us insight into the curve's bend or concave quality and tells us about the change within the change.
- The second derivative is computed from the first derivative and describes how the rate of change itself changes.
- You'll need to solve conditions like ensuring this derivative is zero at specific points: typically the same boundary points.
- This step guarantees no unexpected twists or turns in our transition.
Other exercises in this chapter
Problem 65
Find the equation of the plane having the given normal vector \(\mathbf{n}\) and passing through the given point \(P .\) $$ \mathbf{n}=2 \mathbf{i}-4 \mathbf{j}
View solution Problem 66
Find the equation of the plane having the given normal vector \(\mathbf{n}\) and passing through the given point \(P .\) $$ \mathbf{n}=3 \mathbf{i}-2 \mathbf{j}
View solution Problem 67
Find the equation of the plane having the given normal vector \(\mathbf{n}\) and passing through the given point \(P .\) $$ \mathbf{n}=\langle 1,4,4\rangle ; P(
View solution Problem 68
Find a curve given by a polynomial \(P_{5}(x)\) that provides a smooth transition between \(y=0\) for \(x \leq 0\) and \(y=x\) for \(x \geq 1\)
View solution