Problem 67
Question
Factor. $$ 9 x^{2} y^{2}+30 x y+25 $$
Step-by-Step Solution
Verified Answer
The expression factors to \((3xy + 5)^2\).
1Step 1: Recognize the Form
Notice that the expression is a trinomial. It resembles the perfect square trinomial form which is of the type \((ax)^2 + 2abx + b^2\). Here, let's check if we can express the trinomial in this form.
2Step 2: Identify Components
Compare the given trinomial \(9x^2y^2 + 30xy + 25\) with the perfect square form \((ax)^2 + 2abx + b^2\). Identify \(a = 3xy\) and \(b = 5\), since \((3xy)^2 = 9x^2y^2\) and \(5^2 = 25\).
3Step 3: Check the Middle Term
Verify if the middle term equals \(2ab\). For \(a = 3xy\) and \(b = 5\), calculate \(2ab = 2 \times 3xy \times 5 = 30xy\). The middle term matches, confirming that it's a perfect square trinomial.
4Step 4: Write the Factored Form
Since all conditions are met for a perfect square trinomial, we can write it in its factored form: \((3xy + 5)^2\). This uses the formula \((ax + b)^2 = (ax)^2 + 2abx + b^2\).
Key Concepts
Perfect Square TrinomialAlgebraic ExpressionsPolynomial Factorization
Perfect Square Trinomial
A perfect square trinomial is a special type of polynomial expression that results from squaring a binomial. It takes the form
- \((ax)^2 + 2abx + b^2\)
- \((ax + b)^2\)
- \((ax)^2\) as the square of the first term
- \(b^2\) as the square of the second term
- \(2abx\) as the product of the first term and second, doubled
- \(a = 3xy\)
- \(b = 5\)
- middleware term \(2ab = 30xy\)
Algebraic Expressions
Algebraic expressions are mathematical phrases that can contain numbers, variables, and operators. They're the building blocks of algebra and are used to express relationships between quantities. A trinomial, like the one in our problem, is a type of algebraic expression with three terms. To better manage algebraic expressions, it's crucial to understand the following:
- Variables: Symbols like \(x\) and \(y\) represent quantities that can change or vary.
- Coefficients: The numerical factor that multiplies a variable, such as \(9\) in the term \(9x^2y^2\).
- Constants: Numbers on their own, such as \(25\) in the exercise.
- Terms: Parts of the expression separated by plus or minus signs.
Polynomial Factorization
Polynomial factorization is breaking down a polynomial into simpler components, or "factors," that, when multiplied together, give back the original polynomial. This process is essential for simplifying expressions and solving equations. In particular, perfect square trinomials offer an efficient method of factorization.
There are several methods for factorizing polynomials, but the perfect square method applies when the expression fits the pattern
In the exercise, recognizing the trinomial as a perfect square made the factorization straightforward:
There are several methods for factorizing polynomials, but the perfect square method applies when the expression fits the pattern
- \((ax + b)^2\)
In the exercise, recognizing the trinomial as a perfect square made the factorization straightforward:
- \((3xy + 5)(3xy + 5)\)
Other exercises in this chapter
Problem 66
Factor each polynomial by factoring out the opposite of the GCF. $$ -4 a^{2}-6 a $$
View solution Problem 67
The following is a list of random factoring problems. Factor each expression. If an expression is not factorable, write "prime." See Examples 1-5. $$ 35 x^{8}-2
View solution Problem 67
Solve each equation. $$ 4 x^{2}=81 $$
View solution Problem 67
Factor. If an expression is prime, so indicate. $$ 8 y^{2}-2 y-1 $$
View solution