Problem 67
Question
A portable radio is sitting at the edge of a balcony \(5.1 \mathrm{~m}\) above the ground. The unit is emitting sound uniformly in all directions. By accident, it falls from rest off the balcony and continues to play on the way down. A gardener is working in a flower bed directly below the falling unit. From the instant the unit begins to fall, how much time is required for the sound intensity level heard by the gardener to increase by \(10.0 \mathrm{~dB} ?\)
Step-by-Step Solution
Verified Answer
It takes approximately 0.843 seconds for the intensity level to increase by 10 dB.
1Step 1: Understanding the Problem
The portable radio is dropping from a height of 5.1 m and we need to determine how much time it takes for the sound intensity to increase by 10 dB for a gardener standing directly below. We start by examining how the intensity of sound changes with distance and how the drop time relates to this change.
2Step 2: Formula for Sound Intensity Increase
The intensity level in decibels (dB) is calculated with the formula \[ L = 10 \times \log\left(\frac{I}{I_0}\right) \]where \(L\) is the intensity level, \(I\) is the intensity at a given point, and \(I_0\) is the reference intensity. A change of 10 dB corresponds to the intensity being multiplied by 10.
3Step 3: Relationship Between Intensity and Distance
Sound intensity \(I\) is inversely proportional to the square of the distance \(r\) from the source, given as \[ I \propto \frac{1}{r^2} \]Thus, if the distance decreases by a factor of \(\sqrt{10}\), the intensity becomes 10 times greater.
4Step 4: Calculate the Factor and New Distance
Since the intensity needs to increase by a factor of 10 (because a 10 dB increase), the new distance from the gardener to the radio should be \(5.1 / \sqrt{10}\). Calculate this distance: \[ r_\text{new} = \frac{5.1}{\sqrt{10}} \approx 1.613 \text{ m} \]
5Step 5: Use Kinematics to Find Time
Use the kinematic equation for an object falling under gravity from rest: \[ h = \frac{1}{2} g t^2 \]Where \(h\) is the distance fallen (5.1 m - 1.613 m = 3.487 m) and \(g\) is the acceleration due to gravity (9.8 m/s²). Solving for \(t\): \[ 3.487 = \frac{1}{2} \times 9.8 \times t^2 \]\[ t^2 = \frac{3.487 \times 2}{9.8} \approx 0.711 \]\[ t \approx \sqrt{0.711} \approx 0.843 \text{ seconds} \]
Key Concepts
Decibel (dB)Kinematics in physicsInverse-square law
Decibel (dB)
The decibel (dB) is a unit that measures the intensity of sound. It’s a logarithmic unit, which means it scales in a non-linear way. This can be a bit tricky to understand at first, but let's break it down.
Firstly, the formula for sound intensity level in decibels is given by:\[ L = 10 \times \log\left(\frac{I}{I_0}\right) \]where:
Firstly, the formula for sound intensity level in decibels is given by:\[ L = 10 \times \log\left(\frac{I}{I_0}\right) \]where:
- \(L\) is the sound intensity level in decibels.
- \(I\) is the intensity of the sound being measured.
- \(I_0\) is the reference sound intensity, typically set to the threshold of hearing, which is about \(10^{-12} \text{ W/m}^2\).
Kinematics in physics
Kinematics is a branch of physics that deals with the motion of objects. It’s concerned with the concepts of velocity, acceleration, and displacement, without considering the forces that cause the motion. In our exercise, understanding kinematics is crucial to solve how long it takes for the radio to fall.Consider an object in free fall, such as our fallen radio. We use the basic kinematic equation:\[ h = \frac{1}{2} g t^2 \]where:
- \(h\) is the height from which the object falls.
- \(g\) is the acceleration due to gravity, approximately \(9.8 \text{ m/s}^2\) on Earth.
- \(t\) is the time it takes for the object to fall that distance.
Inverse-square law
The inverse-square law is a principle that applies to various physical phenomena, including sound and light. It states that a specified physical quantity or intensity is inversely proportional to the square of the distance from the source of that physical quantity.In our scenario, when the radio falls closer to the gardener, sound intensity increases because of the inverse-square relationship expressed as:\[ I \propto \frac{1}{r^2} \]where:
- \(I\) is the intensity.
- \(r\) is the distance from the sound source.
Other exercises in this chapter
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