Problem 67
Question
A fish has 5000 catfish in his pond. The number of catfish by \( 8 \% \) per month and the farmer harvests 300 catfish per month. (a) Show that the catfish population \( P_n \) after \( n \) months is given recursively by \( P_n = 1.08 P_{n-1} - 300\) \(P_0 = 5000\) (b) How many catfish are in the pond after six months?
Step-by-Step Solution
Verified Answer
After 6 months, the pond has 5735 catfish.
1Step 1: Understand the Problem
We have a pond with 5000 catfish initially. Each month, the number of catfish increases by \(8\%\) and the farmer removes 300 catfish from the pond.
2Step 2: Formulate the Recursive Formula
The catfish population grows by \(8\%\), meaning each month the population from the previous month is multiplied by \(1.08\). After the growth, the farmer harvests 300 catfish. This creates the recursive formula: \[ P_n = 1.08 P_{n-1} - 300 \].
3Step 3: Check Initial Condition
We know the initial number of catfish, \(P_0 = 5000\). This serves as the starting point for our recursive formula.
4Step 4: Calculate Population After First Month
Using the recursive formula: \[ P_1 = 1.08 imes 5000 - 300 = 5400 - 300 = 5100\].
5Step 5: Calculate Population After Second Month
Continue using the recursive formula:\[ P_2 = 1.08 imes 5100 - 300 = 5508 - 300 = 5208\].
6Step 6: Calculate Population After Third Month
Calculate using:\[ P_3 = 1.08 imes 5208 - 300 = 5624.64 - 300 = 5324.64\]. Since we deal with whole catfish, we can round to \(5325\).
7Step 7: Calculate Population After Fourth Month
Find the population with:\[ P_4 = 1.08 imes 5325 - 300 = 5751 - 300 = 5451\].
8Step 8: Calculate Population After Fifth Month
Proceed with:\[ P_5 = 1.08 imes 5451 - 300 = 5887.08 - 300 = 5587.08\]. Round to \(5587\).
9Step 9: Calculate Population After Sixth Month
Finally, using the formula:\[ P_6 = 1.08 imes 5587 - 300 = 6034.96 - 300 = 5734.96\]. Round to \(5735\).
10Step 10: Complete the Solution
After calculating step by step with the recursive formula, we find that the number of catfish in the pond after six months is 5735.
Key Concepts
Population ModelingDiscrete MathematicsCalculus
Population Modeling
In this exercise, we are dealing with population modeling to figure out how the number of catfish changes over time in a controlled environment. Population modeling is a method used to understand how populations, like fish, grow or shrink over time based on specific influences or controls, such as growth rates and harvesting rates. This type of modeling is helpful for numerous fields including ecology, environmental management, and even economics.
We start with an initial population of 5000 catfish. The population grows by a certain percentage each month, here it is an 8% increase. This means the catfish population is not static, and without any intervention, it would continue to swell.
We start with an initial population of 5000 catfish. The population grows by a certain percentage each month, here it is an 8% increase. This means the catfish population is not static, and without any intervention, it would continue to swell.
- The 8% growth is a natural process where each month's population is 1.08 times that of the previous month.
- The harvesting of 300 catfish per month counteracts this growth, indicating human intervention to control the population size.
Discrete Mathematics
Discrete mathematics involves studying distinct and separated objects, and recursive sequences, like the one in our exercise, are a pivotal part of this branch. Recursive sequences define a series where each term is determined by the preceding ones, using a set mathematical operation. In our case, we define each monthly fish population based on the previous month's population.
Let's explore the components in more detail:
Let's explore the components in more detail:
- The recursive formula we've used is: \[ P_n = 1.08 P_{n-1} - 300 \]. This identifies that the population at any month 'n' depends on the population of the previous month 'n-1'.
- The initial condition, given by \( P_0 = 5000 \), sets the starting point for calculating future populations.
Calculus
Although primarily this problem operates within the realm of discrete mathematics, calculus also provides significant insights into population dynamics, particularly when exploring continuous growth models. Here, we use discrete steps (each month) to calculate growth, while calculus could help in understanding the continuous change.
How might calculus be applied to such a problem?
How might calculus be applied to such a problem?
- **Continuous Growth:** By extending calculus concepts, we can consider how populations grow continuously, which would involve using differential equations to model these changes.
- **Growth Rates:** Calculus helps us grasp the concept of growth rates (in this case, 8%), showing how these rates impact the overall change over time.
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