Problem 66
Question
Write the sum using sigma notation. \(1-2 x+3 x^{2}-4 x^{3}+5 x^{4}+\cdots-100 x^{99}\)
Step-by-Step Solution
Verified Answer
\( \sum_{n=1}^{100} (-1)^{n+1} n x^{n-1} \)
1Step 1: Identify the Sequence
Observe that the given series starts at 1 and proceeds with alternating positive and negative terms. The series is: \[ 1 - 2x + 3x^2 - 4x^3 + 5x^4 + ext{...} - 100x^{99} \] This indicates an alternating sign structure based on the power of \(x\).
2Step 2: Determine the General Term
The general term follows the pattern of alternating terms with increasing powers of \(x\) and coefficients increasing linearly. The positive integers \(n\) are increasing as coefficients and the power of \(x\) is increasing by 1 each time. Considering these, the general term formula is:\[ (-1)^{n+1} n x^{n-1} \] where \(n\) starts from 1.
3Step 3: Express the Sum in Sigma Notation
The series can now be rewritten in sigma notation using the general term we derived. Since the series starts from the first term, \(n = 1\), and ends at the 100th term, \(n = 100\), the sum is:\[ \sum_{n=1}^{100} (-1)^{n+1} n x^{n-1} \]
Key Concepts
Alternating SeriesGeneral TermSeries ExpressionAlgebraic Series
Alternating Series
In mathematics, an alternating series is a sequence of numbers in which the signs alternate all the time. This means that if one term is positive, the next will be negative and vice versa. In our exercise, we see an alternating pattern in the series:
- It starts with a positive number, 1, and switches its sign each following term.
- The negative term appears at every odd power of x and the positive term appears at every even power.
General Term
Identifying the general term of a series is crucial in working with complicated expressions. It allows us to describe any term in the series using a formula. In our series, the formula for the general term is:
- The sign alternates based on the term's position:\[ (-1)^{n+1} \]
- The coefficients are increasing by one at each step, represented by:\[ n \]
- The power of x also increases as the term progresses, denoted by:\[ x^{n-1} \]
Series Expression
When expressing a series, capturing the overall pattern in a concise way is important. This is where sigma notation comes in. It allows you to express an entire series succinctly.Our series:\[ 1 - 2x + 3x^2 - 4x^3 + 5x^4 + ... - 100x^{99} \]can be written in sigma notation as:\[ \sum_{n=1}^{100} (-1)^{n+1} nx^{n-1} \]Here, the expression:
- Starts with \( n = 1 \) and ends at \( n = 100 \) because these are the limits of the terms we have.
- Uses the general term we identified to calculate each element in the series.
Algebraic Series
Algebraic series involve summing terms that are defined by algebraic expressions. In our context, the series involves a polynomial pattern where the expression is related to a power of a variable, like \( x \). Some characteristics include:
- It has coefficients that are changing predictably (increasing by one).
- It includes a variable \( x \) raised to the power that directly relates to the term's position.
Other exercises in this chapter
Problem 65
Write the sum using sigma notation. $$1+x+x^{2}+x^{3}+\cdots+x^{100}$$
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