Problem 66
Question
Which series in Exercises \(53-76\) converge, and which diverge? Give reasons for your answers. If a series converges, find its sum. $$\sum_{n=1}^{\infty} \frac{n^{n}}{n !}$$
Step-by-Step Solution
Verified Answer
The series diverges by the Ratio Test.
1Step 1: Define the Series
The series in question is \( \sum_{n=1}^{\infty} \frac{n^n}{n!} \). We need to determine if this series converges or diverges.
2Step 2: Apply the Ratio Test
To determine convergence, we use the Ratio Test. The Ratio Test states that a series \( \sum a_n \) converges absolutely if \( \lim_{n \to \infty} \left| \frac{a_{n+1}}{a_n} \right| < 1 \).For our series, \( a_n = \frac{n^n}{n!} \). We need to find:\[\lim_{n \to \infty} \left| \frac{a_{n+1}}{a_n} \right| = \lim_{n \to \infty} \left| \frac{(n+1)^{n+1}}{(n+1)!} \cdot \frac{n!}{n^n} \right| \]
3Step 3: Simplify the Limit Expression
Let's simplify the expression:1. \( \frac{(n+1)^{n+1}}{n^n} = \frac{(n+1)^{n} \cdot (n+1)}{n^n} = \left(\frac{n+1}{n}\right)^n \cdot (n+1) \)2. \( \frac{n!}{(n+1)!} = \frac{1}{n+1} \)3. Combining these gives \[\lim_{n \to \infty} \left| \frac{(n+1)^{n+1}}{(n+1)!} \cdot \frac{n!}{n^n} \right| = \lim_{n \to \infty} \left(\frac{n+1}{n}\right)^n = e\].
4Step 4: Analyze the Limit Result
The limit found in Step 3 is \( e \), which is approximately 2.718...Since \( e > 1 \), according to the Ratio Test, the series \( \sum_{n=1}^{\infty} \frac{n^n}{n!} \) diverges.
Key Concepts
Understanding Series ConvergenceDemystifying Factorial FunctionsExploring the Limit Comparison TestDiving into Infinite Series
Understanding Series Convergence
In mathematics, determining whether an infinite series converges or diverges is a fundamental concept. Convergence refers to the property of a series to approach a specific value as more and more terms are added. On the other hand, divergence means that the series does not settle towards any particular value. For an infinite series, written as \( \sum_{n=1}^{\infty} a_n \), we explore these properties to understand if the series is summing up to a finite number or not.
- If the series converges, the sum \( S \) can be found where \( S = \lim_{n \to \infty} S_n \) with \( S_n \) being the partial sum of the first \( n \) terms.
- A diverging series means \( \lim_{n \to \infty} S_n \) does not exist or becomes infinite.
Demystifying Factorial Functions
The factorial function, denoted as \( n! \) (read as 'n factorial'), is a key mathematical operation, especially in series and combinatorics. It is defined as the product of an integer and all the positive integers below it:
- \( n! = n \times (n-1) \times (n-2) \times ... \times 1 \)
- For example, \( 5! = 5 \times 4 \times 3 \times 2 \times 1 = 120 \)
- By convention, \( 0! = 1 \).
Exploring the Limit Comparison Test
The Limit Comparison Test is a handy tool in determining the behavior of series. It helps compare a given series with another series whose convergence behavior is known:
- We compare the series \( \sum a_n \) to \( \sum b_n \), where \( b_n \) is a benchmark series.
- If \( \lim_{n \to \infty} \frac{a_n}{b_n} = c \), where \( 0 < c < \infty \), both series will either converge or diverge together.
- This method is particularly useful when direct application of tests, like the Ratio Test or Integral Test, is complex.
Diving into Infinite Series
An infinite series is a sum of infinitely many terms like \( \sum_{n=1}^{\infty} a_n \). These are not just theoretical constructs; they play crucial roles in mathematical analysis, physics, and engineering.
- Infinite series can represent complex functions and model real-world phenomena.
- Some well-known infinite series include geometric series and harmonic series.
- The behavior of these series is often studied to understand their convergence properties.
Other exercises in this chapter
Problem 66
In Exercises \(57 - 82 ,\) use any method to determine whether the series converges or diverges. Give reasons for your answer. $$ \sum _ { n = 0 } ^ { \infty }
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