Problem 66
Question
Which of the following is a correct factorization \( \text { of }-12 x^{2}+147 ?\) A. \(-3(2 x+7)^{2}\) B. \(3(2 x-7)(2 x+7)\) C. \(-2(2 x-7)(2 x+7)\) D. \(-3(2 x-7)(2 x+7)\)
Step-by-Step Solution
Verified Answer
The correct factorization of the expression \(-12x^2+147\) is \(-3(2x-7) (2x+7)\), which corresponds to option D.
1Step 1: Factorising the Negative term
Start by moving the negative operator to outside the parentheses. This transforms \(-12x^2+147\) into \(-1(12x^2-147)\).
2Step 2: Applying the difference of squares
Next apply the difference of squares formula, which states that \(a^2 - b^2 = (a - b)(a + b)\). Here \(a= \sqrt{12}x\) and \(b= \sqrt{147}\). So \(-1(12x^2-147)\) becomes \(-1( (\sqrt{12}x)^2 - (\sqrt{147})^2 ) = -1( (\sqrt{12}x - \sqrt{147}) (\sqrt{12}x + \sqrt{147}) )\).
3Step 3: Simplify the Solution
Simplify the expression further as \(-1( (2\sqrt{3}x - 7\sqrt{3}) (2\sqrt{3}x + 7\sqrt{3}) )\) which becomes \(-1(2x-7\sqrt{3})(2x+7\sqrt{3})\). The-\(\sqrt{3}\) inside the brackets can be simplified further, giving us \(-1(2x-7) (2x+7)\). This will transform into \(-1*3* (2x-7) (2x+7) = -3(2x-7) (2x+7)\).
Key Concepts
difference of squarespolynomialsalgebraic expressions
difference of squares
The difference of squares is a fundamental concept in algebra that simplifies the factorization of certain quadratic expressions. It follows the formula: \[a^2 - b^2 = (a - b)(a + b)\]. This is powerful because it allows us to factor expressions that appear complex at first glance.
For the expression \(12x^2 - 147\), identify that it fits the difference of squares format where \(a = \sqrt{12}x\) and \(b = \sqrt{147}\). Applying the formula, the expression becomes:
For the expression \(12x^2 - 147\), identify that it fits the difference of squares format where \(a = \sqrt{12}x\) and \(b = \sqrt{147}\). Applying the formula, the expression becomes:
- \(( sqrt{12}x - sqrt{147}) ( sqrt{12}x + sqrt{147})\)
polynomials
Polynomials are expressions consisting of variables (like \(x\)), coefficients, and exponents that are combined using addition, subtraction, and multiplication. A polynomial is typically expressed as:
\[ a_n x^n + a_{n-1} x^{n-1} + \ldots + a_1 x + a_0 \]
Here, each \(a_n\) represents a coefficient, and \(x^n\) indicates the degree. In this case, \(-12x^2 + 147\) is a second-degree polynomial due to the \(x^2\) term.
\[ a_n x^n + a_{n-1} x^{n-1} + \ldots + a_1 x + a_0 \]
Here, each \(a_n\) represents a coefficient, and \(x^n\) indicates the degree. In this case, \(-12x^2 + 147\) is a second-degree polynomial due to the \(x^2\) term.
- The highest degree term indicates the polynomial's order, which influences its graph's shape and turning points.
- Understanding polynomials also aids in various operations such as addition, subtraction, multiplication, division, and factorization.
algebraic expressions
Algebraic expressions are statements comprised of numbers, variables, and arithmetic operations such as addition (+), subtraction (-), multiplication (*), and division (÷). They are fundamental in outlining mathematical relationships and allowing calculations beyond simple arithmetic.
For example, in the expression \(-12x^2 + 147\), we have two key elements:
For example, in the expression \(-12x^2 + 147\), we have two key elements:
- Terms: \(-12x^2\) (a term with variable and exponent) and \(+147\) (a constant term)
- Operators: Indicate the mathematical operations linked to these terms.
Other exercises in this chapter
Problem 65
Find the product. \((2 x+7)(3 x-1)\)
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Find the product. $$ (2 a-7)(2 a+7) $$
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In Exercises \(65-70,\) simplify. Then use a calculator to evaluate the expression. $$ \left(3^{2} \cdot 1^{3}\right)^{2} $$
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Solve the equation. $$ (y+47)(y-27)=0 $$
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