Problem 66
Question
Verify the identity by transforming the lefthand side into the right-hand side. $$\cot \theta+\tan \theta=\csc \theta \sec \theta$$
Step-by-Step Solution
Verified Answer
The identity is verified: \( \cot \theta + \tan \theta = \csc \theta \sec \theta \).
1Step 1: Convert to Sine and Cosine
Express cotangent and tangent in terms of sine and cosine. We have \( \cot \theta = \frac{\cos \theta}{\sin \theta} \) and \( \tan \theta = \frac{\sin \theta}{\cos \theta} \). Substitute these into the left-hand side of the equation: \[\cot \theta + \tan \theta = \frac{\cos \theta}{\sin \theta} + \frac{\sin \theta}{\cos \theta}.\]
2Step 2: Find a Common Denominator
To add these fractions, we need a common denominator, which is \( \sin \theta \cdot \cos \theta \). Rewrite each term with this common denominator:\[\frac{\cos \theta}{\sin \theta} = \frac{\cos^2 \theta}{\sin \theta \cdot \cos \theta}, \quad \frac{\sin \theta}{\cos \theta} = \frac{\sin^2 \theta}{\sin \theta \cdot \cos \theta}.\]
3Step 3: Combine Fractions
Add the fractions obtained from Step 2 with the common denominator:\[\frac{\cos^2 \theta}{\sin \theta \cdot \cos \theta} + \frac{\sin^2 \theta}{\sin \theta \cdot \cos \theta} = \frac{\cos^2 \theta + \sin^2 \theta}{\sin \theta \cdot \cos \theta}.\]
4Step 4: Use Pythagorean Identity
Recall the Pythagorean identity \( \cos^2 \theta + \sin^2 \theta = 1 \). Apply this identity to simplify the numerator:\[\frac{\cos^2 \theta + \sin^2 \theta}{\sin \theta \cdot \cos \theta} = \frac{1}{\sin \theta \cdot \cos \theta}.\]
5Step 5: Express in Terms of Cosecant and Secant
Recognize that \( \frac{1}{\sin \theta} = \csc \theta \) and \( \frac{1}{\cos \theta} = \sec \theta \). Thus,\[\frac{1}{\sin \theta \cdot \cos \theta} = \csc \theta \cdot \sec \theta.\]
6Step 6: Verify the Identity
We have transformed the left-hand side \( \cot \theta + \tan \theta \) into \( \csc \theta \cdot \sec \theta \), which matches the right-hand side of the identity. Therefore, the given identity is verified.
Key Concepts
Pythagorean IdentitySine and Cosine ConversionCommon Denominator in Fractions
Pythagorean Identity
The Pythagorean Identity is a fundamental concept in trigonometry and can be expressed as: \( \cos^2 \theta + \sin^2 \theta = 1 \). This identity stems from the Pythagorean theorem related to right triangles on the unit circle. Here is why the Pythagorean Identity is so useful:
- Firstly, it helps in simplifying expressions where both sine and cosine are present.
- Secondly, it can be used to verify and prove other trigonometric identities.
- Lastly, in problems where either sine or cosine values are given, it makes finding the other value straightforward.
Sine and Cosine Conversion
Trigonometric functions like tangent and cotangent can often be expressed in terms of sine and cosine. This conversion is especially useful when trying to simplify or manipulate trigonometric equations. Let's break it down:
- The cotangent of an angle, \( \theta \), is defined as \( \cot \theta = \frac{\cos \theta}{\sin \theta} \).
- Similarly, the tangent of an angle is \( \tan \theta = \frac{\sin \theta}{\cos \theta} \).
Common Denominator in Fractions
When adding or subtracting fractions, finding a common denominator is a crucial part of the process. In arithmetic, just as in trigonometry, this makes it possible to combine terms or simplify expressions. Consider this process:
- To add \( \frac{\cos \theta}{\sin \theta} \) and \( \frac{\sin \theta}{\cos \theta} \), a common denominator must be established.
- The least common denominator here is \( \sin \theta \cdot \cos \theta \), which enables straightforward addition of the fractions.
Other exercises in this chapter
Problem 66
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