Problem 66
Question
Use the formula for the general term (the nth term) of a geometric sequence to solve Exercises \(65-68\) In Exercises \(65-66,\) suppose you save \(\$ 1\) the first day of a month, \(\$ 2\) the second day, \(\$ 4\) the third day, and so on. That is, each day you save twice as much as you did the day before. What will you put aside for savings on the thirtieth day of the month?
Step-by-Step Solution
Verified Answer
The amount set aside for savings on the thirtieth day of the month is \(\$ 2^{29}\) dollars
1Step 1: Identify the characteristics of the geometric sequence.
The first term (a) of the sequence is \(\$1\) and the ratio (r), which is the factor by which we multiply each term to get the next, is \(2\). We are asked to find the thirtieth term of the sequence, which means n (the term number in the sequence) is \(30\).
2Step 2: Apply the formula for the nth term of a geometric sequence
The formula for the nth term of a geometric sequence is given by \(a_n = a \cdot r^{(n-1)}\), where \(a\) is the first term, \(r\) is the common ratio, and \(n\) is the term number. Therefore, substitute \(a = 1\), \(r = 2\), and \(n = 30\) into the formula to find the thirtieth term.
3Step 3: Compute the value.
Calculating it, we have \(a_{30} = 1 \cdot 2^{(30-1)} = 1 \cdot 2^{29}\). The result is the equivalent in dollars of the value of \(2^{29}\).
Key Concepts
nth term formulacommon ratiogeometric sequence problemsterm calculation
nth term formula
In a geometric sequence, each term is scaled by a constant value known as the common ratio. The formula used to calculate any term in this type of sequence is pivotal for understanding its behavior and predicting future terms. This formula is known as the nth term formula and is expressed as:
- \(a_n = a \cdot r^{(n-1)}\)
common ratio
The common ratio in a geometric sequence is the factor by which you multiply each term to get to the next. In our savings problem, the common ratio is \(2\). Each day you save twice as much money as you saved the previous day. This consistency in multiplication is what defines a geometric sequence, distinguishing it from arithmetic sequences where you add a constant value instead.Understanding the common ratio:
- Increases rapidly: Multiplying by a number greater than one will rapidly increase the next terms.
- In this case, the savings plan grows exponentially as days go by.
geometric sequence problems
When dealing with geometric sequence problems, one must focus on the key elements like identifying the first term and the common ratio. Knowing these elements allows you to use the nth term formula effectively. In the issue discussed, you start with a small daily saving that grows exponentially throughout the month:
- First term \(a = 1\)
- Common ratio \(r = 2\)
- Identify known values: first term and common ratio.
- Apply the nth term formula to predict the outcome for desired terms.
- Solve to find actual values.
term calculation
Calculating a specific term in a geometric sequence involves a clear understanding of the nth term formula. Let's dive into the term calculation itself:In our savings scenario, to find out how much you will save on the 30th day, you use the nth term formula:
- Given \(a = 1\), \(r = 2\), and \(n = 30\), plug these into the formula: \(a_{30} = 1 \times 2^{29}\)
- Calculate \(2^{29}\)
- The result is the amount saved on the 30th day.
Other exercises in this chapter
Problem 65
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