Problem 66
Question
Use the discriminant to determine the number of real solutions of the equation. Do not solve the equation. \(9 x^{2}-4 x+\frac{4}{9}=0\)
Step-by-Step Solution
Verified Answer
The equation has exactly one real solution.
1Step 1: Identify the coefficients
For the quadratic equation in the form of \(ax^2 + bx + c = 0\), identify the coefficients: \(a = 9\), \(b = -4\), and \(c = \frac{4}{9}\).
2Step 2: Calculate the discriminant
The discriminant \(D\) is calculated using the formula \(D = b^2 - 4ac\). Substitute \(b = -4\), \(a = 9\), and \(c = \frac{4}{9}\) to get \(D = (-4)^2 - 4 \times 9 \times \frac{4}{9}\).
3Step 3: Simplify the discriminant
Calculate \((-4)^2 = 16\). Then calculate \(4 \times 9 = 36\), so \(36 \times \frac{4}{9} = 16\). Therefore, the discriminant \(D = 16 - 16 = 0\).
4Step 4: Interpret the discriminant
The discriminant \(D = 0\) indicates that the quadratic equation has exactly one real solution.
Key Concepts
Quadratic EquationReal SolutionsCoefficients
Quadratic Equation
A quadratic equation is a polynomial equation of degree two. It is generally expressed in the standard form: \[ ax^2 + bx + c = 0 \] where
Quadratic equations can be solved using various methods, including factoring, using the quadratic formula, completing the square, and graphing. However, before finding the solutions, it's useful to determine the nature and number of the solutions using the discriminant.
- \(a\), \(b\), and \(c\) are coefficients,
- \(a\) is not equal to zero,
- \(x\) represents the variable or the unknown in the equation.
Quadratic equations can be solved using various methods, including factoring, using the quadratic formula, completing the square, and graphing. However, before finding the solutions, it's useful to determine the nature and number of the solutions using the discriminant.
Real Solutions
In the context of quadratic equations, solutions refer to the values of \(x\) that satisfy the equation \(ax^2 + bx + c = 0\). When we talk about real solutions, we specifically mean solutions that are real numbers as opposed to complex numbers.
The discriminant, represented by \(D\), provides key insights into the nature of these solutions:
In our task with the discriminant of 0, it indicated that there is one real solution for the given quadratic equation.
The discriminant, represented by \(D\), provides key insights into the nature of these solutions:
- If \(D > 0\), the quadratic equation has two distinct real solutions.
- If \(D = 0\), there is exactly one real solution, also known as a repeated or double root.
- If \(D < 0\), there are no real solutions; however, there are two complex solutions.
In our task with the discriminant of 0, it indicated that there is one real solution for the given quadratic equation.
Coefficients
Coefficients are numerical or constant factors associated with the terms in an equation. In a quadratic equation \( ax^2 + bx + c = 0 \), the coefficients \(a\), \(b\), and \(c\) play specific roles:
These values are then used in the discriminant formula \(D = b^2 - 4ac\) to evaluate the nature of the solutions. Proper manipulation of these values determines whether we have real solutions, and if so, how many.
- \(a\) is called the leading coefficient, as it is multiplied to the highest power of \(x\), which is \(x^2\).
- \(b\) is the coefficient of the linear term, \(x\).
- \(c\) is the constant term, which stands alone without \(x\).
These values are then used in the discriminant formula \(D = b^2 - 4ac\) to evaluate the nature of the solutions. Proper manipulation of these values determines whether we have real solutions, and if so, how many.
Other exercises in this chapter
Problem 66
Find all solutions of the equation and express them in the form \(a+b i .\) $$ x^{2}+\frac{1}{2} x+1=0 $$
View solution Problem 66
65–68 ? Solve the equation for the variable x. The constants a and b represent positive real numbers. $$ a^{3} x^{3}+b^{3}=0 $$
View solution Problem 66
\(47-70\) The given equation involves a power of the variable. Find all real solutions of the equation. $$ 4(x+2)^{5}=1 $$
View solution Problem 67
\(67-70=\) Determine the values of the variable for which the expression is defined as a real number. $$ \sqrt{16-9 x^{2}} $$
View solution