Problem 66
Question
The widths of two slits in YDSE are in the ratio \(1: 4\). The ratio of amplitudes of light waves from two slits will be (a) \(9: 1\) (b) \(4: 1\) (c) \(1: 2\) (d) \(1: \sqrt{2}\)
Step-by-Step Solution
Verified Answer
The ratio of amplitudes is \(1:2\).
1Step 1: Understanding the Relation Between Slit Width and Amplitude
In Young's Double Slit Experiment (YDSE), the intensity of light coming from a slit is proportional to the area of the slit, and hence the width of the slit affects the amplitude. Specifically, the amplitude of the light wave, denoted as \( A \), from a slit is proportional to the square root of the width of the slit. Thus, if \( w_1 \) and \( w_2 \) are widths of the slits, the amplitudes \( A_1 \) and \( A_2 \) are proportional to \( \sqrt{w_1} \) and \( \sqrt{w_2} \), respectively.
2Step 2: Determine the Ratio of Amplitudes
The given slit width ratio is \( w_1 : w_2 = 1 : 4 \). Using the relationship that the amplitude is proportional to the square root of the width, we find the amplitude ratio \( A_1 : A_2 = \sqrt{w_1} : \sqrt{w_2} \). Substitute for the widths: \( A_1 : A_2 = \sqrt{1} : \sqrt{4} = 1 : 2 \).
Key Concepts
Amplitude of Light WavesSlit Width RatioLight Intensity in Interference
Amplitude of Light Waves
In Young's Double Slit Experiment, understanding the amplitude of light waves is crucial to grasping how light behaves. The amplitude of a light wave corresponds to the maximum extent of a wave from its rest position, and it determines the wave's energy. In essence, higher amplitude means higher light intensity. The relationship between slit width and amplitude is fundamental in the experiment.
- The amplitude of a light wave passing through a slit is directly related to the slit’s width.
- The formula for the amplitude (\(A\)) is proportional to the square root of the slit’s width (\(w\)): \(A \propto \sqrt{w}\).
- This means if you know the width ratio of two slits, you can determine their amplitude ratio through square root calculation.
Slit Width Ratio
The slit width ratio in Young’s Double Slit Experiment is an important factor when examining light interference patterns. The ratio influences how much light intensity each slit contributes to the final interference pattern visible on a screen. The widths given here are in the ratio of \(1:4\).
- The slit width ratio defines the proportion between the widths of two slits, allowing for predictions about their relative impacts.
- In our given exercise, with widths \(w_1\) and \(w_2\) at a ratio of \(1:4\), the effect of each slit becomes evident.
- A larger slit allows more light through, increasing the light’s amplitude and intensity from that slit more than the smaller slit.
Light Intensity in Interference
Light intensity in Young's Double Slit Experiment results from the superposition of light waves emanating from the slits. The light intensity at a point on the interference pattern is affected by several factors, including the amplitude of light waves and phase difference. In terms of this exercise, the interplay of different factors determines the intensity of the resultant pattern.
- The intensity of light is proportional to the square of the amplitude, \(I \propto A^2\).
- Constructive interference occurs when wave amplitudes combine to increase intensity, whereas destructive interference reduces it.
- The intensity pattern shown on a screen is a result of these alternating constructive and destructive interferences.
Other exercises in this chapter
Problem 65
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