Problem 66
Question
The most prominent line in the emission spectrum of chromium is found at \(425.4 \mathrm{nm} .\) Other lines in the chromium spectrum are found at \(357.9 \mathrm{nm}, 359.3 \mathrm{nm}\) \(360.5 \mathrm{nm}, 427.5 \mathrm{nm}, 429.0 \mathrm{nm},\) and \(520.8 \mathrm{nm}\) (a) Which of these lines represents the most energetic light? (b) What color is light of wavelength \(425.4 \mathrm{nm} ?\)
Step-by-Step Solution
Verified Answer
(a) 357.9 nm is the most energetic light.
(b) 425.4 nm light is blue.
1Step 1: Understand Energy and Wavelength Relationship
The energy of light is inversely proportional to its wavelength, according to the formula \(E = \frac{hc}{\lambda}\), where \(E\) is energy, \(h\) is Planck's constant, \(c\) is the speed of light, and \(\lambda\) is the wavelength. Therefore, shorter wavelengths correspond to higher energy.
2Step 2: Compare Wavelengths for Highest Energy
To determine which line represents the most energetic light, compare the wavelengths listed:
- 357.9 nm
- 359.3 nm
- 360.5 nm
- 425.4 nm
- 427.5 nm
- 429.0 nm
- 520.8 nm
The shortest wavelength is 357.9 nm, which corresponds to the most energetic light.
3Step 3: Determine the Color of 425.4 nm Light
The wavelength of 425.4 nm falls within the visible spectrum. It is approximately in the range of violet to blue light. Therefore, light at 425.4 nm is typically perceived as blue.
Key Concepts
Wavelength and Energy RelationshipVisible Light SpectrumChromium Spectral Lines
Wavelength and Energy Relationship
The relationship between wavelength and energy is fundamental in understanding emission spectra. Energy (E) of photons is related inversely to their wavelength (\(\lambda\)). This means when the wavelength decreases, the energy increases. This relationship is quantified by the equation:\[E = \frac{hc}{\lambda}\]where \(h\) is Planck's constant (6.626 \times 10^{-34} \, \text{J s}), and \(c\) is the speed of light (3.00 \times 10^{8} \text{ m/s}). Thus, shorter wavelengths, like those near 357.9 nm in chromium’s emission spectrum, are the most energetic. Steps for comparing and understanding the emission of different spectra involve looking at their wavelengths and using this formula to calculate energy. Always remember:
- Shorter wavelength → Higher energy
- Longer wavelength → Lower energy
Visible Light Spectrum
The visible light spectrum is the portion of the electromagnetic spectrum that is visible to the human eye. It ranges from roughly 380 nm to 750 nm in wavelength. Different wavelengths within this spectrum correspond to different colors:
- Violet: 380-450 nm
- Blue: 450-495 nm
- Green: 495-570 nm
- Yellow: 570-590 nm
- Orange: 590-620 nm
- Red: 620-750 nm
Chromium Spectral Lines
Chromium spectral lines are vital for understanding both atomic structure and spectroscopy. The spectrum comprises several specific wavelengths emitted by electrons in the chromium atom as they transition between energy levels. When these electrons release energy, they emit light at characteristic wavelengths, produce specific lines
a.k.a. spectral lines.
The most prominent lines for chromium, such as those at 357.9 nm and 425.4 nm, reveal essential aspects of its atomic structure. These wavelengths help scientists identify and analyze the element's presence in various samples.
The diversity in line intensities and colors (as seen with the multiple lines listed in chromium’s spectrum) indicate different electron transitions. For students, understanding these lines not only involves recognizing the wavelengths themselves but also interpreting what they imply about electron configurations and energy states in atoms. Such insights are crucial for fields like astrophysics and chemical analysis.
Other exercises in this chapter
Problem 63
Cobalt-60 is a radioactive isotope used in medicine for the treatment of certain cancers. It produces \(\beta\) particles and \(\gamma\) rays, the latter having
View solution Problem 64
A Exposure to high doses of microwaves can cause tissue damage. Estimate how many photons, with \(\lambda=12 \mathrm{cm},\) must be absorbed to raise the temper
View solution Problem 70
A solution of KMnO absorbs light at 540 nm (page 192). What is the frequency of the light absorbed? What is the energy of one mole of photons with \(\lambda=540
View solution Problem 71
A large pickle is attached to two electrodes, which are then attached to a \(110-\mathrm{V}\) power supply. As the voltage is increased across the pickle, it be
View solution