Problem 66
Question
The figure shows the graph of \(f(x)=\ln x .\) In Exercises \(65-74\) use transformations of this graph to graph each function. Graph and give equations of the asymptotes. Use the graphs to determine each function's domain and range. $$ g(x)=\ln (x+1) $$
Step-by-Step Solution
Verified Answer
The graph of \(g(x) = \ln(x+1)\) is a shift of the graph of \(f(x) = \ln(x)\) 1 unit to the left. The vertical asymptote of the function is at \(x=-1\). The domain of the function is \(x > -1\) and the range is all real numbers.
1Step 1: Identify the Transformation
The transformation from \(f(x)=\ln(x)\) to \(g(x)=\ln(x+1)\) involves a horizontal shift, specifically a shift to the left by one unit. This happens because x in the function is replaced by (x+1).
2Step 2: Graphing the Function
Start with the graph of \(y=\ln(x)\), and then shift every point on this graph one unit to the left to graph \(y=\ln(x+1)\). The point (1, 0) shifts to the point (0, 0), and the y-axis serves as a vertical asymptote.
3Step 3: Identify the Asymptote
An asymptote is a line that the graph approaches but never touches. In this case, with the function \(g(x) = \ln(x+1)\), the vertical asymptote is the line \(x=-1\), due to the shift of the function.
4Step 4: Determine the Range and Domain
The domain of a function is the set of all possible x-values. In this case, the domain of \(g(x) = \ln(x+1)\) is \(x > -1\), because logarithms are only defined for positive numbers. The range of a function is the set of all possible y-values. For the function \(g(x)=\ln(x+1)\), as with any logarithmic function, the range is all real numbers.
Key Concepts
Horizontal ShiftDomain and RangeVertical Asymptote
Horizontal Shift
A horizontal shift is a transformation that moves the graph of a function left or right. In the case of the function transformation from \(f(x) = \ln(x)\) to \(g(x) = \ln(x+1)\), the graph is shifted left by one unit. This happens because the expression \((x+1)\) inside the logarithm suggests that we start at earlier values of \(x\). Essentially, when you add a positive constant inside the expression \( (x + c) \), you shift the graph to the left by \(c\) units.
For example:
For example:
- The point \((1, 0)\) on the graph of \(\ln(x)\) moves to \((0, 0)\) on the graph of \(\ln(x+1)\).
- Similarly, the point \((e, 1)\) — where \(e\) is the base of the natural logarithm, approximately 2.718 — now appears at \((e-1, 1)\).
Domain and Range
The domain of a function refers to all the possible x-values that make the function defined. For logarithmic functions like \(g(x) = \ln(x+1)\), the domain is influenced by the need for the argument inside the logarithm to be greater than zero.
Here's a breakdown:
Here's a breakdown:
- For \(g(x) = \ln(x+1)\), the argument \((x+1)\) must be greater than zero.
- This means \(x > -1\) to keep the function defined and real.
Vertical Asymptote
A vertical asymptote is a line that the graph of a function approaches as the x-values get very close to a certain number but never actually reaches or intersects. In the transformed function \(g(x) = \ln(x+1)\), due to the horizontal shift, the vertical asymptote shift also occurs.
For the basic function \(f(x) = \ln(x)\), the vertical asymptote is at \(x = 0\), just because logarithms aren't defined for non-positive numbers.
For the basic function \(f(x) = \ln(x)\), the vertical asymptote is at \(x = 0\), just because logarithms aren't defined for non-positive numbers.
- When \(f(x)\) changes to \(g(x) = \ln(x+1)\), the vertical asymptote shifts too, moving one unit to the left because of the \(+1\) inside the logarithm.
- As a result, we end up with a vertical asymptote at \(x = -1\) for the function \(g(x)\).
Other exercises in this chapter
Problem 66
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