Problem 66
Question
Solve the equation. Check your answers. $$ x^{2 / 3}=16 $$
Step-by-Step Solution
Verified Answer
The solution to the equation is \(x = 64\).
1Step 1: Understanding the Problem
The goal is to solve for \(x\) in the equation \(x^{2/3} = 16\). This means we need to find the value(s) of \(x\) that satisfy the equation when raised to the power of \(2/3\) and equals 16.
2Step 2: Isolate the Power
Since the left side of the equation is \(x^{2/3}\), we can solve for \(x\) by raising both sides of the equation to the reciprocal power, which is \(3/2\). This will help in cancelling out the power on \(x\).
3Step 3: Apply Reciprocal Power
Raise both sides of the equation to the power of \(3/2\):\[(x^{2/3})^{3/2} = 16^{3/2}\]This simplifies to:\[x = (16^{3/2})\].
4Step 4: Simplify the Right Side
We need to calculate \(16^{3/2}\). First, recall that \(16^{1/2} = \sqrt{16} = 4\). Now, raise this result to the power of 3:\[16^{3/2} = (16^{1/2})^3 = 4^3 = 64\].
5Step 5: Verify the Solution
Now we need to verify our solution. Plug \(x = 64\) back into the original equation: \[(64)^{2/3}\]. First, find \(64^{1/3} = \sqrt[3]{64} = 4\). Then, \(4^2 = 16\), which matches the right side of the equation. Thus, \(x = 64\) is correct.
Key Concepts
ExponentsVerify SolutionReciprocal Powers
Exponents
Exponents tell us how many times to multiply a number by itself. In algebra, they are crucial in simplifying expressions and solving equations. For instance, when we see an exponent like \( x^{2/3} \), it indicates two operations:
This approach is integral in understanding how to manipulate and solve equations involving fractional exponents efficiently.
- The "2" represents squaring, or multiplying the base by itself once.
- The "3" indicates the cube root, which is finding a number that, when multiplied by itself twice, gives back the original number.
This approach is integral in understanding how to manipulate and solve equations involving fractional exponents efficiently.
Verify Solution
Verifying a solution means checking to ensure that the solution we have satisfies the original equation. It's like double-checking our work.
In this context, after determining that \( x = 64 \) satisfies the equation \( x^{2/3} = 16 \), we must substitute 64 back into the equation to see if it holds true.
In this context, after determining that \( x = 64 \) satisfies the equation \( x^{2/3} = 16 \), we must substitute 64 back into the equation to see if it holds true.
- The power \( 2/3 \) means we first find \( 64^{1/3} \) or \( \sqrt[3]{64} \), which turns out to be 4 because \( 4 \times 4 \times 4 = 64 \).
- Then, we square this result, \( 4^2 = 16 \).
Reciprocal Powers
Reciprocal powers are used to simplify and solve equations involving exponents. They are particularly helpful when the equation includes fractional exponents. The reciprocal of an exponent is simply "flipping" the fraction over.
For example, in the equation \( x^{2/3} = 16 \), we employed the reciprocal exponent \( 3/2 \).
For example, in the equation \( x^{2/3} = 16 \), we employed the reciprocal exponent \( 3/2 \).
- This means raising both sides of the equation such that the powers can cancel out.
- For \( x^{2/3} \), the reciprocal \( 3/2 \) cancels \( 2/3 \), returning us to \( x^1 \) or \( x \).
Other exercises in this chapter
Problem 65
Solve the rational inequality. $$ \frac{3-2 x}{1+x}
View solution Problem 65
Graph \(y=f(x) .\) You may want to use division, factoring, or transformations as an aid. Show all asymptotes and "holes." $$ f(x)=\frac{x+2}{x+1} $$
View solution Problem 66
Solve the rational inequality. $$ \frac{x+1}{4-2 x} \geq 1 $$
View solution Problem 66
Graph \(y=f(x) .\) You may want to use division, factoring, or transformations as an aid. Show all asymptotes and "holes." $$ f(x)=\frac{2 x+3}{x+1} $$
View solution