Problem 66
Question
Sketch the surfaces in Exercises \(13-76\) $$ y^{2}-x^{2}-z^{2}=1 $$
Step-by-Step Solution
Verified Answer
This is a hyperboloid of two sheets, symmetric about the x-z plane.
1Step 1: Identify the Surface Type
The given equation is a quadratic equation in three variables: \( y^2 - x^2 - z^2 = 1 \). By comparing the equation with the standard form of a hyperboloid of two sheets \( \frac{y^2}{a^2} - \frac{x^2}{b^2} - \frac{z^2}{c^2} = 1 \), we can identify this as a hyperboloid of two sheets.
2Step 2: Determine the Characteristics
In this hyperboloid of two sheets, \( a^2 = 1 \), \( b^2 = 1 \), and \( c^2 = 1 \). It opens along the y-axis because the \( y^2 \) term is positive, whereas \( x^2 \) and \( z^2 \) terms are negative.
3Step 3: Sketch the Surface
To sketch the hyperboloid of two sheets, note that for any constant \( y = k \), the cross-sections are hyperbolae in the \((x, z)\)-plane. The surfaces appear as two separate sheets symmetric with respect to the x-z plane, starting from \( y = -rac{1}{2} \) and \( y = rac{1}{2} \). As \(|y|\) increases, the sheets are farther apart.
Key Concepts
Quadratic Surfaces3D Coordinate SystemsSketching 3D SurfacesConic Sections
Quadratic Surfaces
Quadratic surfaces are fascinating in the realm of mathematics, particularly in multivariable calculus and 3D geometry. These surfaces are defined by second-degree polynomial equations in three variables, often taking forms such as ellipsoids, paraboloids, hyperboloids, and others.
Their significance lies in their symmetrical properties and the way they can represent complex 3D objects concisely. Understanding quadratic surfaces allows one to explore various sections and projections, crucial for fields like architecture and engineering. By looking into the equation \( y^2 - x^2 - z^2 = 1 \), we understand it is specifically a hyperboloid of two sheets. Recognizing this is key to drafting precise sketches and models in practical applications.
Their significance lies in their symmetrical properties and the way they can represent complex 3D objects concisely. Understanding quadratic surfaces allows one to explore various sections and projections, crucial for fields like architecture and engineering. By looking into the equation \( y^2 - x^2 - z^2 = 1 \), we understand it is specifically a hyperboloid of two sheets. Recognizing this is key to drafting precise sketches and models in practical applications.
3D Coordinate Systems
The 3D coordinate system is essential for graphing and analyzing equations involving three dimensions. It extends the familiar 2D Cartesian system with an additional z-axis. Each point in 3D space is represented as a tuple \((x, y, z)\), describing its position relative to the origin.
- The x-axis generally runs horizontally.
- The y-axis runs vertically.
- The z-axis comes out from or into the page or screen.
Sketching 3D Surfaces
When sketching a 3D surface such as a hyperboloid of two sheets, it's helpful to identify the main features of its equation. For \( y^2 - x^2 - z^2 = 1 \):
- The equation suggests the surface opens along the y-axis, with the positive \(y^2\) term.
- The negative \(x^2\) and \(z^2\) terms indicate the surface extends symmetrically along these axes.
- The hyperboloid presents two separate 'sheets' or pieces.
Conic Sections
Conic sections are the curves obtained when a plane intersects a cone. They include ellipses, parabolas, and hyperbolas. Intriguingly, these curves have direct relationships to quadratic surfaces in 3D.
- For hyperboloids, like in our equation \( y^2 - x^2 - z^2 = 1 \), the intersection in vertical planes parallel to the axis of symmetry are hyperbolas.
- These hyperbolas help reveal the shape and structure of the 3D surface.
- The nature of intersections—whether they rise steeply or flatten—varies significantly based on the coefficients and signs in the surface equations.
Other exercises in this chapter
Problem 65
Find the points in which the line \(x=1+2 t, y=-1-t\) \(z=3 t\) meets the coordinate planes. Describe the reasoning be- hind your answer.
View solution Problem 65
Sketch the surfaces in Exercises \(13-76\) $$ z=-\left(x^{2}+y^{2}\right) $$
View solution Problem 66
Find equations for the line in the plane \(z=3\) that makes an angle of \(\pi / 6\) rad with \(\mathbf{i}\) and an angle of \(\pi / 3\) rad with \(\mathbf{j}\)
View solution Problem 67
Sketch the surfaces in Exercises \(13-76\) $$ x^{2}-4 y^{2}=1 $$
View solution